MCQ: Puzzles- 1 - Bank Exams MCQ

From the following common explanation, we get box Y is placed 5^th position from the bottom.
Hence, Option B is correct.
Final Arrangement:

Common Explanation:
References:
Two boxes are placed between boxes T and U.
One box is placed between boxes T and Z, which is placed above T.
Inferences:
From the above references, we get the following cases:

References:
Three boxes are placed between boxes V and Z.
Box V is placed below box Z.
Box X is placed just above box V.
Inferences:
From the above references, we get the following cases:

References:
Three boxes are placed between boxes X and W.
Inferences:
From the above references, Case 1 is not valid we can place box W by using these references:

Hence, Case 2 is the final arrangement.

From the following common explanation, we get three boxes are placed below box T.
Hence, Option D is correct.

Final Arrangement:

Common Explanation:
References:
Two boxes are placed between boxes T and U.
One box is placed between boxes T and Z, which is placed above T.
Inferences:
From the above references, we get the following cases:

References:
Three boxes are placed between boxes V and Z.
Box V is placed below box Z.
Box X is placed just above box V.
Inferences:
From the above references, we get the following cases:

References:
Three boxes are placed between boxes X and W.
Inferences:
From the above references, Case 1 is not valid we can place box W by using these references:

Hence, Case 2 is the final arrangement.

From the following common explanation, we get three boxes placed between box Y and box U.
Hence, Option C is correct.
Final Arrangement:

Common Explanation:
References:
Two boxes are placed between boxes T and U.
One box is placed between boxes T and Z, which is placed above T.
Inferences:
From the above references, we get the following cases:

References:
Three boxes are placed between boxes V and Z.
Box V is placed below box Z.
Box X is placed just above box V.
Inferences:
From the above references, we get the following cases:

References:
Three boxes are placed between boxes X and W.
Inferences:
From the above references, Case 1 is not valid we can place box W by using these references:

Hence, Case 2 is the final arrangement.

From the following common explanation, only one box ‘X’ remain in the same position after rearrangement.
Hence, Option B is correct.
Final Arrangement:

Common Explanation:
References:
Two boxes are placed between boxes T and U.
One box is placed between boxes T and Z, which is placed above T.
Inferences:
From the above references, we get the following cases:

References:
Three boxes are placed between boxes V and Z.
Box V is placed below box Z.
Box X is placed just above box V.
Inferences:
From the above references, we get the following cases:

References:
Three boxes are placed between boxes X and W.
Inferences:
From the above references, Case 1 is not valid we can place box W by using these references:

Hence, Case 2 is the final arrangement.

From the following common explanation, we get except box T, all are placed at odd position from both top and bottom.
Hence, Option C is correct.
Final Arrangement:

Common Explanation:
References:
Two boxes are placed between boxes T and U.
One box is placed between boxes T and Z, which is placed above T.
Inferences:
From the above references, we get the following cases:

References:
Three boxes are placed between boxes V and Z.
Box V is placed below box Z.
Box X is placed just above box V.
Inferences:
From the above references, we get the following cases:

References:
Three boxes are placed between boxes X and W.
Inferences:
From the above references, Case 1 is not valid we can place box W by using these references:

Hence, Case 2 is the final arrangement.

From the common explanation, we get Only 4 people are lighter than N.

Hence, Option C is correct.

Final Arrangement:

Common Explanation:

References:

P is heavier than Q, whose weight is 55kg.

The weight of O is 70kg and only two people are heavier than O.

P, who is not the lightest, is lighter than O.

R is lighter than Q and N is lighter than M.

Inferences:

O weighs 70kg and only two people are heavier than O so O is 3rd heaviest person.

P, who is heavier than Q, is lighter than O and R is lighter than Q. So, P is 4th heaviest, Q is 5th heaviest and R is the lightest person. N is lighter than M, so M is the heaviest and N is 2nd heaviest person.

Thus we get:

From the common explanation, we get ’70 > P > 55, so weight of P is 60kg.
Hence, Option D is correct.

Final Arrangement:

Common Explanation:
References:

P is heavier than Q, whose weight is 55kg.

The weight of O is 70kg and only two people are heavier than O.

P, who is not the lightest, is lighter than O.

R is lighter than Q and N is lighter than M.

Inferences:

O weighs 70kg and only two people are heavier than O so O is 3rd heaviest person.

P, who is heavier than Q, is lighter than O and R is lighter than Q. So, P is 4th heaviest, Q is 5th heaviest and R is the lightest person. N is lighter than M, so M is the heaviest and N is 2nd heaviest person.

Thus we get:

Solution:

Based on the information provided:

• O weighs 70kg and is lighter than two people.
• P is lighter than O but not the lightest.
• Q weighs 55kg and is lighter than P.
• R is lighter than Q.
• N is lighter than M.

From this, we can deduce the following:

• The two people heavier than O must be M and someone else.
• P must weigh more than Q but less than O, indicating P is heavier than 55kg but less than 70kg.
• Since R is lighter than Q, R weighs less than 55kg.
• This implies that M must be heavier than O.

Thus, the only statement that is definitely true is that M is heavier than O.

The given clues are:

• O's weight is 70 kg, and only two people are heavier than O. So, O is the third heaviest.
• P is not the lightest and is lighter than O, so P's weight is less than 70 kg but not the least.
• R is lighter than Q; N is lighter than M.
• P is heavier than Q, and Q's weight is 55 kg. Thus, P's weight is more than 55 kg but less than 70 kg.

Let's arrange the people in order:

1. M is heavier than N, and since only two people are heavier than O, M and N must be those two. M is the heaviest, N is the second heaviest, O is third.
2. So, order from heaviest: M > N > O (70 kg) > P > Q (55 kg) > R.

Thus, M is the heaviest.

From the following common explanation, we get that Maahi was born in 2002.
Hence, Option C is correct.
Final Arrangement:

Common Explanation:
References:
Ten people were born in ten different years from 1994 to 2003.
Inferences:
So, we need to arrange as follows to accommodate the information stated in the reference:

References:
Ekta was born in a year which is a multiple of 5.
Two people were born between Ekta and Raj.
Sagar was born immediately after Ekta.
Inferences:
From the above references, we get the following cases:

References:
Four people were between Hari and Raj.
Maahi was born immediately before Hari.
Inferences:
From the above references, we get the following cases:

According to the given conditions, Maahi was born immediately before Hari. Thus case 3 is not valid.
References:
Three people were born between Prem and Sagar.
Mahesh was born after Prem.
Inferences:
From the above references, we get the following cases:

According to the given conditions, three people were between Prem and Sagar. Thus case 2 is not valid.
References:
David was born after Tejas but before Maya.
Inferences:
From the above references, we get the final arrangement:

From the following common explanation, we get that no one sits between Prem and Maaya.
Hence, Option D is correct.
 

Final Arrangement:

Common Explanation:
References:
Ten people were born in ten different years from 1994 to 2003.
Inferences:
So, we need to arrange as follows to accommodate the information stated in the reference:

References:
Ekta was born in a year which is a multiple of 5.
Two people were born between Ekta and Raj.
Sagar was born immediately after Ekta.
Inferences:
From the above references, we get the following cases:

References:
Four people were between Hari and Raj.
Maahi was born immediately before Hari.
Inferences:
From the above references, we get the following cases:

According to the given conditions, Maahi was born immediately before Hari. Thus case 3 is not valid.
References:
Three people were born between Prem and Sagar.
Mahesh was born after Prem.
Inferences:
From the above references, we get the following cases:

According to the given conditions, three people were between Prem and Sagar. Thus case 2 is not valid.
References:
David was born after Tejas but before Maya.
Inferences:
From the above references, we get the final arrangement:

From the following common explanation, we get except Ekta all were born in even years.
Hence, Option A is correct.
 

Final Arrangement:

Common Explanation:
References:
Ten people were born in ten different years from 1994 to 2003.
Inferences:
So, we need to arrange as follows to accommodate the information stated in the reference:

References:
Ekta was born in a year which is a multiple of 5.
Two people were born between Ekta and Raj.
Sagar was born immediately after Ekta.
Inferences:
From the above references, we get the following cases:

References:
Four people were between Hari and Raj.
Maahi was born immediately before Hari.
Inferences:
From the above references, we get the following cases:

According to the given conditions, Maahi was born immediately before Hari. Thus case 3 is not valid.
References:
Three people were born between Prem and Sagar.
Mahesh was born after Prem.
Inferences:
From the above references, we get the following cases:

According to the given conditions, three people were between Prem and Sagar. Thus case 2 is not valid.
References:
David was born after Tejas but before Maya.
Inferences:
From the above references, we get the final arrangement:

From the following common explanation, we get that Hari is youngest person.
Hence, Option D is correct.
 

Final Arrangement:

Common Explanation:
References:
Ten people were born in ten different years from 1994 to 2003.
Inferences:
So, we need to arrange as follows to accommodate the information stated in the reference:

References:
Ekta was born in a year which is a multiple of 5.
Two people were born between Ekta and Raj.
Sagar was born immediately after Ekta.
Inferences:
From the above references, we get the following cases:

References:
Four people were between Hari and Raj.
Maahi was born immediately before Hari.
Inferences:
From the above references, we get the following cases:

According to the given conditions, Maahi was born immediately before Hari. Thus case 3 is not valid.
References:
Three people were born between Prem and Sagar.
Mahesh was born after Prem.
Inferences:
From the above references, we get the following cases:

According to the given conditions, three people were between Prem and Sagar. Thus case 2 is not valid.
References:
David was born after Tejas but before Maya.
Inferences:
From the above references, we get the final arrangement:

From the following common explanation, we get Mahesh was born in 2001.
Hence, Option D is correct.
 

Final Arrangement:

Common Explanation:
References:
Ten people were born in ten different years from 1994 to 2003.
Inferences:
So, we need to arrange as follows to accommodate the information stated in the reference:

References:
Ekta was born in a year which is a multiple of 5.
Two people were born between Ekta and Raj.
Sagar was born immediately after Ekta.
Inferences:
From the above references, we get the following cases:

References:
Four people were between Hari and Raj.
Maahi was born immediately before Hari.
Inferences:
From the above references, we get the following cases:

According to the given conditions, Maahi was born immediately before Hari. Thus case 3 is not valid.
References:
Three people were born between Prem and Sagar.
Mahesh was born after Prem.
Inferences:
From the above references, we get the following cases:

According to the given conditions, three people were between Prem and Sagar. Thus case 2 is not valid.
References:
David was born after Tejas but before Maya.
Inferences:
From the above references, we get the final arrangement:

To determine the possible weight of W, consider the following points:

• The 4th heaviest person weighs 35kg.
• There are only two persons heavier than W.
• B is not the lightest, and Q is just heavier than B.
• G is heavier than M, and M is heavier than the 4th lightest person.
• S weighs 1/5th of L and is lighter than Q.
• If M is 45kg heavier than a weight of 5kg, M weighs 50kg.

Given these details, we can deduce the possible weights:

• If W is heavier than two persons, W must be lighter than the 3rd heaviest person.
• Since M weighs 50kg and is heavier than the 4th heaviest at 35kg, W must be less than 50kg.

Therefore, the possible weight of W is:

• 48kg (as the best feasible option that satisfies all conditions).