MCQ: Complementary angles - 1 - SSC CGL MCQ

# MCQ: Complementary angles - 1 - SSC CGL MCQ

Test Description

## 15 Questions MCQ Test Quantitative Aptitude for SSC CGL - MCQ: Complementary angles - 1

MCQ: Complementary angles - 1 for SSC CGL 2024 is part of Quantitative Aptitude for SSC CGL preparation. The MCQ: Complementary angles - 1 questions and answers have been prepared according to the SSC CGL exam syllabus.The MCQ: Complementary angles - 1 MCQs are made for SSC CGL 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for MCQ: Complementary angles - 1 below.
Solutions of MCQ: Complementary angles - 1 questions in English are available as part of our Quantitative Aptitude for SSC CGL for SSC CGL & MCQ: Complementary angles - 1 solutions in Hindi for Quantitative Aptitude for SSC CGL course. Download more important topics, notes, lectures and mock test series for SSC CGL Exam by signing up for free. Attempt MCQ: Complementary angles - 1 | 15 questions in 15 minutes | Mock test for SSC CGL preparation | Free important questions MCQ to study Quantitative Aptitude for SSC CGL for SSC CGL Exam | Download free PDF with solutions
MCQ: Complementary angles - 1 - Question 1

### In the given figure, if AB || CD, then ∠FXE is equal to:

Detailed Solution for MCQ: Complementary angles - 1 - Question 1

As per the given figure,
∠BFE = ∠CEF = 110° (alt. ∠s).
So, ∠XFE = ∠BFE ‒ ∠BFX = (110° ‒ 50°) = 60°.
And on straight line CD,
110° + ∠FEX + 30° = 180° ⇒ ∠FEX = 40°.
Now, ∠XFE + ∠FEX + ∠FXE = 180° ⇒ 60° + 40° + ∠FXE = 180°.
∴ ∠FXE = 80°.
Hence, option D is correct.

MCQ: Complementary angles - 1 - Question 2

### If two angles are complementary of each other, then each angle is:

Detailed Solution for MCQ: Complementary angles - 1 - Question 2

If two angles are complementary, then clearly each angle is less than 90° and is therefore an acute
angle.
Hence, option C is correct.

 1 Crore+ students have signed up on EduRev. Have you?
MCQ: Complementary angles - 1 - Question 3

### In the given figure, the value of x, that would make POQ a straight line, is:

Detailed Solution for MCQ: Complementary angles - 1 - Question 3

POQ will be a straight line,
If 80° + 66° + x = 180°, i.e. x = 34°.
Hence, option C is correct.

MCQ: Complementary angles - 1 - Question 4

In the given figure, if AOB is a straight line, then the value of x is:

Detailed Solution for MCQ: Complementary angles - 1 - Question 4

As, (x + 30°) + 45° + (x + 15°) = 180°
⇒ x = 45°.
Hence, option B is correct.

MCQ: Complementary angles - 1 - Question 5

In the given figure, AOB is a straight line. If ∠AOC + ∠BOD = 85°, then ∠COD is:

Detailed Solution for MCQ: Complementary angles - 1 - Question 5

Clearly,
∠AOC + ∠COD + ∠BOD = 180°
∴ 85° + ∠COD = 180°.
So, ∠COD = (180° ‒ 85°) = 95°.
Hence, option C is correct.

MCQ: Complementary angles - 1 - Question 6

The straight lines AD and BC intersect one another at the point O.
If ∠AOB + ∠BOD + ∠DOC = 274°, then ∠AOC is:

Detailed Solution for MCQ: Complementary angles - 1 - Question 6

As we know that the sum of all the angles around a point is 360°.
(∠AOB + ∠BOD + ∠DOC) + ∠AOC = 360°
∴ 274° + ∠AOC = 360° or ∠AOC = 86°.
Hence, option A is correct.

MCQ: Complementary angles - 1 - Question 7

Two straight lines AB and CD cut each other at O. If ∠BOD = 63°, then ∠BOC is:

Detailed Solution for MCQ: Complementary angles - 1 - Question 7

As given ∠BOD = 63°
Since COD is a straight line, we have:
∠BOC + ∠BOD = 180°. So, ∠BOC = (180° ‒ 63°) = 117°.
Hence, option B is correct.

MCQ: Complementary angles - 1 - Question 8

The supplement of 154° 30’ is:

Detailed Solution for MCQ: Complementary angles - 1 - Question 8

Supplement of 154° 30’ is 180° ‒ (154° 30’)
= (179° 30’) ‒ (154° 30’) {since 1° = 60’}
= 25° 30’.
Hence, option A is correct.

MCQ: Complementary angles - 1 - Question 9

The complement of 72° 40’ is:

Detailed Solution for MCQ: Complementary angles - 1 - Question 9

Complement of 72° 40’ is 90° ‒ (72° 40’)
= (89° 60’) ‒ (72° 40’) {since 1° = 60’}
= 17° 20’
Hence, option C is correct.

MCQ: Complementary angles - 1 - Question 10

An angle which is greater than 180° but less than 360° is called:

Detailed Solution for MCQ: Complementary angles - 1 - Question 10

An angle which is greater than 180° but less than 360° is called a reflex angle.
Hence, option D is correct.

MCQ: Complementary angles - 1 - Question 11

In the figure given below, EC is parallel to AB, ∠ECD = 70° and ∠BDO = 20°. What is the value of ∠OBD?

Detailed Solution for MCQ: Complementary angles - 1 - Question 11

Given that, EC || AB
∴ ∠ECO + ∠AOC = 180°

⇒ ∠AOC = 180° –70° = 110°
∴ ∠BOD = ∠AOC = 110° (alternate angle)
Now, in ΔOBD ∠BOD + ∠ODB + ∠DBO = 180°
∴ 110° + 20° + x° = 180° ⇒ x° = 50°.
Hence, option D is correct.

MCQ: Complementary angles - 1 - Question 12

In the figure given below LOM is a straight line. What is the value of x°?

Detailed Solution for MCQ: Complementary angles - 1 - Question 12

From the given figure,
∠LOQ + ∠QOP + ∠POM = 180°  (straight line)
∴ (x° + 20°) + 50° + (x° – 10°) = 180°
⇒ 2x° + 60° = 180° ⇒ 2x° = 120°
∴ x° = 60°
Hence, option B is correct.

MCQ: Complementary angles - 1 - Question 13

Consider the following statements If two straight lines intersect, then
I. vertically opposite angles are equal.
II. vertically opposite angles are supplementary.
Which of the statements given above is/are correct?

Detailed Solution for MCQ: Complementary angles - 1 - Question 13

Here, AB and CD are two lines.

If two straight lines intersect, then opposite vertically angles are equal.
Hence, option B is correct.

MCQ: Complementary angles - 1 - Question 14

If two supplementary angles differ by 44°, then one of the angle is:

Detailed Solution for MCQ: Complementary angles - 1 - Question 14

Let the two angles are x and y. Therefore, as per the given information,
x ‒ y = 44° and
x + y = 180°   [As the total of supplementary angles is 180°] On solving these two linear equations we get,
2x = 224,
x = 112°.
Therefore the other angle y = 180° ‒ 112° = 68°
Hence, option C is correct.

MCQ: Complementary angles - 1 - Question 15

In the given figure, line CE is drawn parallel to DB. If ∠BAD = 110°, ∠ABD = 30°, ∠ADC = 75° and ∠BCD = 60°, then the value of x° is:

Detailed Solution for MCQ: Complementary angles - 1 - Question 15

As in the given figure,
∠ADB = 180° ‒ (110° + 30°) = 40°.
So, ∠BDC = (75° ‒ 40°) = 35°.
∴ ∠DBC = 180° ‒ (60° + 35°) = 85°.
∴ ∠BCE = ∠DBC = 85° (alt. ∠s).
So, x = 85°.
Hence, option C is correct.

## Quantitative Aptitude for SSC CGL

314 videos|170 docs|185 tests
Information about MCQ: Complementary angles - 1 Page
In this test you can find the Exam questions for MCQ: Complementary angles - 1 solved & explained in the simplest way possible. Besides giving Questions and answers for MCQ: Complementary angles - 1, EduRev gives you an ample number of Online tests for practice

## Quantitative Aptitude for SSC CGL

314 videos|170 docs|185 tests