MCQ: Geometric Progressions - 1 - SSC CGL MCQ

MCQ: Geometric Progressions - 1 - SSC CGL MCQ

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15 Questions MCQ Test Quantitative Aptitude for SSC CGL - MCQ: Geometric Progressions - 1

MCQ: Geometric Progressions - 1 for SSC CGL 2024 is part of Quantitative Aptitude for SSC CGL preparation. The MCQ: Geometric Progressions - 1 questions and answers have been prepared according to the SSC CGL exam syllabus.The MCQ: Geometric Progressions - 1 MCQs are made for SSC CGL 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for MCQ: Geometric Progressions - 1 below.
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MCQ: Geometric Progressions - 1 - Question 1

A sequence is called ___________________ if an+1 = an * r.

Detailed Solution for MCQ: Geometric Progressions - 1 - Question 1

Clarification: A sequence is called geometric progression if an+1 = an * r where a1 is the first term and r is common ratio.

MCQ: Geometric Progressions - 1 - Question 2

If first term of a G.P. is 20 and common ratio is 4. Find the 5th term.

Detailed Solution for MCQ: Geometric Progressions - 1 - Question 2

Given, a = 20 and r = 4.
We know, an = arn-1
⇒ a5 = 20*44 = 20*256 = 5120.

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MCQ: Geometric Progressions - 1 - Question 3

If r = 1 in a G.P. then what is the sum to n terms?

Detailed Solution for MCQ: Geometric Progressions - 1 - Question 3

If a is the first term of G.P., then G.P. look like a, a, a, a, …………
Then sum to n terms becomes n*a.

MCQ: Geometric Progressions - 1 - Question 4

In G.P. 4, 8, 16, 32, ………… find the sum up to 5th term.

Detailed Solution for MCQ: Geometric Progressions - 1 - Question 4

In the given G.P., a = 4 and r = 8/4 = 2.
We know, Sn = a(rn-1)/(r-1)
⇒ S5 = 4(25-1) / (2-1) = 4*31 = 124.

MCQ: Geometric Progressions - 1 - Question 5

In a G.P., 5th term is 27 and 8th term is 729. Find its 11th term.

Detailed Solution for MCQ: Geometric Progressions - 1 - Question 5

Given, a5 = 27 and a8 = 729.
⇒ ar4 = 27 and ar7 = 729
On dividing we get, r3 = 27 ⇒ r = 3
⇒ a = 27 / (34) = 1/3
⇒ a11 = ar10 = (1/3) (310) = 39 = 19683.

MCQ: Geometric Progressions - 1 - Question 6

How many terms of G.P. 2,4,8,16, …………… are required to give sum 254?

Detailed Solution for MCQ: Geometric Progressions - 1 - Question 6

a=2 and r = 4/2 = 2.
We know, Sn = a(rn-1)/(r-1)
2(2n-1) / (2-1) = 254
=>2n-1 = 127 => 2n = 128 = 27
=> n=7.

MCQ: Geometric Progressions - 1 - Question 7

If three positive numbers are inserted between 4 and 512 such that the resulting sequence is a G.P., which of the following is not among the numbers inserted?

Detailed Solution for MCQ: Geometric Progressions - 1 - Question 7

Let G.P. be 4, G1, G2, G3, 512.
=> a=4 and a5 = a*r4 = 512 => 4*r4 = 512 => r4 = 512/4 = 128 => r = 4.
G1 = a2 = a * r = 4*4 = 16.
G2 = G1 * r = 16 * 4 = 64.
G3 = G2 * r = 64*4 = 256.

MCQ: Geometric Progressions - 1 - Question 8

The sum of first three terms of a G.P. is 21/2 and their product is 27. Which of the following is not a term of the G.P. if the numbers are positive?

Detailed Solution for MCQ: Geometric Progressions - 1 - Question 8

Let three terms be a/r, a, a*r.
Product = 27 => (a/r) (a) (a*r) = 27 => a3 = 27
=>a = 3.
Sum = 21/2 => (a / r + a + a*r) = 21/2 => a (1 / r + 1 + 1*r) = 21/2
=> (1 / r + 1 + 1*r) = (21/2)/3 = 7/2
=> (r2 + r + 1) = (7/2) r => r2 – (5/2) r +1 = 0
=> r = 2 and 1/2.
Terms are 3/2, 3, 3*2 i.e. 3/2, 3, 6.

MCQ: Geometric Progressions - 1 - Question 9

If a sequence is in the form 2*5n then which of the following may be the sequence?

Detailed Solution for MCQ: Geometric Progressions - 1 - Question 9

If an = 2*5n then
a1 =10, a2 = 50, a3=250.
This is a geometric progression with first term 10 and common ratio 5.

MCQ: Geometric Progressions - 1 - Question 10

If a = 3 and r = 2 then find the sum up 5th term.

Detailed Solution for MCQ: Geometric Progressions - 1 - Question 10

We know, Sn = a(rn-1)/(r-1)
Here a = 3, r = 2 and n = 5
S5 = 3 (25-1) / (2-1) = 3(32 -1) = 3*31 = 93.

MCQ: Geometric Progressions - 1 - Question 11

Which term of G.P. 25, 125, 625, …………. is 390625?

Detailed Solution for MCQ: Geometric Progressions - 1 - Question 11

In the given G.P., a = 25 and r = 125/25 = 5.
Given, an = 390625 => arn-1 = 390625
=> 25*5n-1 = 390625
=> 5n-1 = 390625/25 = 15625 = 56
=> n-1 = 6 => n=7.

MCQ: Geometric Progressions - 1 - Question 12

What is nth term of a G.P.?

Detailed Solution for MCQ: Geometric Progressions - 1 - Question 12

Since every term of an G.P. is r times the previous term.
i.e. an+1 = an * r = an-1 * r2 = ….. = a1 * rn
or an = a*rn-1

MCQ: Geometric Progressions - 1 - Question 13

Find the sum of series 1+1/2 + 1/4 + ………. up to 6 terms.

Detailed Solution for MCQ: Geometric Progressions - 1 - Question 13

Given series is G.P. with first term 1 and common ratio 1/2.
We know, Sn = a(1-rn)/(1-r) for r<1.
S6 = 1(1-(1/2)6) / (1-1/2) = (1-1/64) / (1/2) = 63*2/64 = 63/32.

MCQ: Geometric Progressions - 1 - Question 14

The sum of first three terms of a G.P. is 21/2 and their product is 27. Find the common ratio.

Detailed Solution for MCQ: Geometric Progressions - 1 - Question 14

Let three terms be a/r, a, a*r.
Product = 27 => (a/r) (a) (a*r) = 27 => a3 = 27
=>a = 3.
Sum = 21/2 => (a / r + a + a*r) = 21/2 => a (1 / r + 1 + 1*r) = 21/2
=> (1 / r + 1 + 1*r) = (21/2)/3 = 7/2
=> (r2 + r + 1) = (7/2) r => r2 – (5/2) r + 1 = 0
=> r = 2 and 1/2.

MCQ: Geometric Progressions - 1 - Question 15

Which of the following is the geometric mean of 3 and 12.

Detailed Solution for MCQ: Geometric Progressions - 1 - Question 15

We know, geometric mean of two numbers a and b is given by

So, G.M. of 3 and 12 is

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Quantitative Aptitude for SSC CGL

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