MCQ: Pipes and Cisterns - 2 - SSC CGL MCQ

# MCQ: Pipes and Cisterns - 2 - SSC CGL MCQ

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## 15 Questions MCQ Test Quantitative Aptitude for SSC CGL - MCQ: Pipes and Cisterns - 2

MCQ: Pipes and Cisterns - 2 for SSC CGL 2024 is part of Quantitative Aptitude for SSC CGL preparation. The MCQ: Pipes and Cisterns - 2 questions and answers have been prepared according to the SSC CGL exam syllabus.The MCQ: Pipes and Cisterns - 2 MCQs are made for SSC CGL 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for MCQ: Pipes and Cisterns - 2 below.
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MCQ: Pipes and Cisterns - 2 - Question 1

### One tap can fill a water tank in 40 minutes and another tap can make the filled tank empty in 60 minutes. If both the taps are open, in how many hours will the empty tank be filled ?

Detailed Solution for MCQ: Pipes and Cisterns - 2 - Question 1

Using Rule 7,

Part of the tank filled when both taps are opened together

Hence, the tank will be filled in 120 minutes 2 hours.

MCQ: Pipes and Cisterns - 2 - Question 2

### Two pipes A and B can separately fill a tank in 2 hours and 3 hours respectively. If both the pipes are opened simultaneously in the empty tank, then the tank will be filled in

Detailed Solution for MCQ: Pipes and Cisterns - 2 - Question 2

Using Rule 1,
Part of tank filled by pipes A and B in 1 hour

Required time

= 1 hour 12 minutes

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MCQ: Pipes and Cisterns - 2 - Question 3

### A tank can be filled by pipe A in 2 hours and pipe B in 6 hours. At 10 A.M. pipe A was opened. At what time will the tank be filled if pipe B is opened at 11 A.M.?

Detailed Solution for MCQ: Pipes and Cisterns - 2 - Question 3

Part of the tank filled in 1 hour by pipe A = 1/2
Part of the tank filled by both pipes in1 hour

So, Time taken to fill 2/3 part = 60 minutes
Time taken to fill 1/2 part

The tank will be filled at 11:45 A.M.

MCQ: Pipes and Cisterns - 2 - Question 4

A water tank can be filled by a tap in 30 minutes and another tap can fill it in 60 minutes. If both the taps are kept open for 5 minutes and then the first tap is closed, how long will it take for the tank to be full ?

Detailed Solution for MCQ: Pipes and Cisterns - 2 - Question 4

Using Rule 2,
Part of the tank filled by both taps in 5 minutes

Remaining part =  that is filled by second tap.

MCQ: Pipes and Cisterns - 2 - Question 5

A pipe can fill a tank in ‘x’ hours and another pipe can empty it in‘y’ (y > x) hours. If both the pipes are open, in how many hours will the tank be filled ?

Detailed Solution for MCQ: Pipes and Cisterns - 2 - Question 5

Part of the tank filled in 1 hour = 1/x
Part of the tank emptied in 1 hour = 1/y
Part of the tank filled in 1 hour
when both are opened

Tank will be filled in

MCQ: Pipes and Cisterns - 2 - Question 6

A tap can fill storage in 8 hours and another tap can discharge it in 16 hours. In the event that both the taps are open, the time taken to fill the tank will be:

Detailed Solution for MCQ: Pipes and Cisterns - 2 - Question 6

Net part filled in 1 hr = (1/8 ? 1/16) = 1/16
Total time taken to fill the tank = 16 hrs.

MCQ: Pipes and Cisterns - 2 - Question 7

A funnel can discharge a tank in 40 minutes. A second pipe with distance across twice as much as that of the first is likewise joined with the tank to purge it. The two together can exhaust the tank in:

Detailed Solution for MCQ: Pipes and Cisterns - 2 - Question 7

A pipe with double diameter will take half time.
So, the second pipe can empty the full tank in 20 min.
Part emptied by both in 1 min. (1/40+ 1/20) = 3/40
Time taken to empty the full tank = 40/3 min.

MCQ: Pipes and Cisterns - 2 - Question 8

A tank is fitted with two taps A and B. A can fill the tank totally in 45 minutes and B can purge the full tank in 60 minutes. On the off chance that both the taps are opened on the other hand for 1 minute, then in what amount of time the unfilled tank will be filled totally?

Detailed Solution for MCQ: Pipes and Cisterns - 2 - Question 8

Work done by A in 1st minutes and B 2nd minute = (1/45- 1/60)= 1/180
Part filled in 2 min = 1/180
Part filled in 358 min = (1/360*358) =  358/360 = 179/180
Remaining part = (1-179/180) = 1/180
1/45 part is filled by A in (45*1/180) min= 1/4 min.
Total time taken to fill it = 358 1/4 min = 5 hrs.58 min 15 sec.

MCQ: Pipes and Cisterns - 2 - Question 9

A break in the base of a tank can purge the full tank in 6 hours. A channel funnel fills water at the rate of 4 liters for each moment. At the point when the tank is full, the channel is opened and because of the break, the tank is void in 8 hours. The limit of the tank is

Detailed Solution for MCQ: Pipes and Cisterns - 2 - Question 9

Part filled in 1 hour = (1/6-1/8)= 1/24
So, the inlet can fill the tank in 24 hours.
Capacity of the tank= volume of water that flows in 24 hrs
= (4*60*24) ltr. = 5760 liters.

MCQ: Pipes and Cisterns - 2 - Question 10

Two pipes A and B can fill a water tank in 20 and 24 min respectively. A third pipe C can empty at the rate of 3 gallons per minute. If A, B and C opened together fill the tank in 15 min, the capacity of the tank (in gallons) is:

Detailed Solution for MCQ: Pipes and Cisterns - 2 - Question 10

Let the capacity of the tank = x gallons
Quantity of the water filled in the tank in 1 min when all the pipes A, B and C are opened simultaneously= x/20 + x/24 - 3
According to question,
x/20 + x/24 - 3 = x/15
or, x/20 + x/24 - x/15 = 3
or, (6x + 5x  - 8x)/120 = 3
or, 3x/120 = 3
or, x = 120 gallons

MCQ: Pipes and Cisterns - 2 - Question 11

A channels can fill a tank in x hours and another funnel can exhaust it in y (y>x) hours. In the event that both the funnels are open, in how long will the tank be filled?

Detailed Solution for MCQ: Pipes and Cisterns - 2 - Question 11

Work done by filling pipe in 1 hr = 1/x
Work done by emptying pipe in 1 hr = 1/y
Net filling work done by both in 1 hr = (1/x- 1/y) = (y-x)/xy
∴ The tank will be filled in xy/(y-x) hrs.

MCQ: Pipes and Cisterns - 2 - Question 12

Two channels can fill a tank in 15 hours and 12 hours separately and a third pipe can purge it in 4 hours. In the event that the channels are opened all together at 8 am, 9 am and 11am separately, the tank will be exhausted at

Detailed Solution for MCQ: Pipes and Cisterns - 2 - Question 12

Let the tank be emptied in x hrs after 8 am.
Work done by A in x hrs, by B in (x-1) hrs and C in (x-3) hrs = 0
⇒x/15+ (x-1)/12- (x-3)/4 = 0 ⇒ 4x+5(x-1) - 15(x-3) = 0
⇒6x= 40 ⇒x= 20/3 hrs.
⇒x= 6 hrs. 40 min after 8 am
Hence the tank will be emptied at 14 hrs 40 min, i.e., 2:40 pm

MCQ: Pipes and Cisterns - 2 - Question 13

A substantial tanker can be filled by two pipes A and B in an hour and 40 minutes separately. How long will it take to fill the tanker from unfilled state if B is utilized for a fraction of the time and A and B fill it together for the other half?

Detailed Solution for MCQ: Pipes and Cisterns - 2 - Question 13

Let the total time taken be x minute. Then,
(1/40*x/2) + (1/60+ 1/40) x/2= 1 ⇒ x/80 + x/48 = 1
⇒3x+ 5x= 240 ⇒8x= 240 ⇒x= 30
Hence, the required time is 30 minutes.

MCQ: Pipes and Cisterns - 2 - Question 14

A cistern has 3 pipes A, B and C. A and B can ill it in 3 hours and 4 hours respectively while C can empty the completely filled cistern in 1 hour. If the pipes are opened in order at 3, 4 and 5 pm respectively, at what time will the cistern be empty?

Detailed Solution for MCQ: Pipes and Cisterns - 2 - Question 14

In 2 hours Pipe A will fill = 2/3 tank
In 1 hour Pipe B will fill = 1/4 tank
Part of tank filled till 5 PM = (2/3) + (1/4)
= 11/12
Remaining part = 1 - (11/12)
= 1/12
Net part emptied when A, b and C are opened = (1/3) +( 1/4) - 1
= (4+3-12)/12
=  -5/12
∴ 5/12 part is emptied in 1 hour.
∴ 11/12 is emptied in (12/5)*(11/12) = 11/5
= 2 hr 12 min
∴ Tank will be emptied at 7:12 PM.

MCQ: Pipes and Cisterns - 2 - Question 15

Taps A, B and C are connected to a water tank and the rate of flow of water is 42 ltr/hr, 56 ltr/hr and 48 ltr/hr respectively. A and ill fill the tank while tap C empties the tank. If the three taps are opened simultaneously, the tank gets filled up completely in 16 hours. What is the capacity of the tank?

Detailed Solution for MCQ: Pipes and Cisterns - 2 - Question 15

Net amount of water filled in 1 hr when all the pipes are opened simultaneously = 42 + 56 ? 48 = 50 ltr
Tank gets completely filled in 16 hrs.
∴ Capacity of tank = 16*50 = 800 liters.

## Quantitative Aptitude for SSC CGL

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## Quantitative Aptitude for SSC CGL

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