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Total balls and desired outcome
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The bag has 11 balls in all (6 black + 5 red).
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We want the probability of drawing 3 balls all black in one random draw of 3 balls.
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Count the total number of ways to choose any 3 balls
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You can pick any 3 out of 11 in “11 choose 3” ways.
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“11 choose 3” means the number of combinations of 11 items taken 3 at a time, which equals
(11 × 10 × 9) ÷ (3 × 2 × 1) = 165 total possible sets of 3 balls.
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Count the number of ways to get 3 black balls
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There are 6 black balls, and we need to pick 3 of them.
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That is “6 choose 3” = (6 × 5 × 4) ÷ (3 × 2 × 1) = 20 favourable sets.
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Form the probability
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Probability = (number of favourable sets) ÷ (total number of sets)
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So it’s 20 ÷ 165, which simplifies by dividing numerator and denominator by 5:
20 ÷ 165 = 4 ÷ 33
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Final answer
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The probability of drawing three black balls at random is 4/33 (option b).
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