Percentage - MCQ 5 - SSC CGL

Answer – a) 50/3 % Solution: x = 120y/100 or x = 6y/5 y = 5x/6. Percentage by which y is smaller Than x is [(x – 5x/6)/x]*100 = 50/3 %

Answer – c) 600 kg Solution: Let X kg of alloy is needed. So, 15/100 of X = 90. So X =600 kg

Answer – c) 12.5 ltr Solution: Initially alcohol 2/5 * 25 = 10 ltr and water is 15 ltr.
To make a solution of 60% alcohol (10+x)/25+x = 60/100. X = 12.5

Answer – a) 600 and 150 Solution: 20% of X = P – 30 (X = Maximum marks and P = passing marks) 30% of X = P + 30. Solve for X and P.

Answer – c) 612 Solution: No of transistor sold = 900*(85/100)*(80/100) = 612

Answer – d) 660 Solution: Ratio b/w winner and loser 5:1 Total no of votes casted actually = 1000*(88/100)*(90/100) = 792 5x + x = 792, X =132 Votes of winner candidate = 5*132 = 660

Answer – c) 300/13 Solution: If commodity price is increased then reduction in consumption will be [(increase in price)/100 + increase in price]*100. (30/130)*100 = 300/13%

Answer – a) 10 Solution: No of students = T. Each student gets 10% of T.
So , T students get T^2/10 sweets.
T^2/10 = 1000. So T = 100. So each student gets 10 sweets

Answer – b) 10% Solution: Take 100 as rishi salary.
Increased by 20% percent = 120.
Then decreased by 25%, i.e = (75/100)*120 = 90.
So percentage decrease is 10%.

Answer – a) 5% Solution: Initially I-E = S (I = Income, E = expenditure, S = saving) 10000-6000 = 4000(saving) Now, I = 11000 and E = 7200. So saving = I – E = 3800. [(4000-3800)/4000]*100 = 5%

C) 20%
Explanation: n(M or E) = n(M) + n(E) – n(M and E) n(M or E) = 40+50-10 = 80 so % of the students who like neither English nor Mathematics = 100 – 80 = 20%

D) 16 kg Explanation: Let new weight be x kg Since the pulp is not being evaporated, the quantity of pulp should remain same in both cases. This gives (100-96)% of 20 = (100-95)% of x Solve, x = 16 kg

E) 50 kg Explanation: Let the original price = 100 Rs per kg Then money required to buy 49 kg = 49*100 = Rs 4900 New price per kg is (100-98)% of Rs 100 = 98 So quantity of wheat bought in 4900 Rs is 4900/98 = 50 kg

E) None of these Explanation: Let C’s monthly salary = Rs 100, then B’s = (100-20)% of 100 = 80, and A’s monthly = (100+30)% * 80 = 104
If difference between A and C’s monthly salary is Rs 4 then B’s monthly salary is Rs 80
So if difference is Rs 800, B’s monthly salary is (80/4) * 800 = 16,000 So annual salary = 12*16,000

B) 24 (2/7)%
Explanation: Water in new mixture from 1st mixture = (20/100) * 10 = 2 parts Water in new mixture from 2nd mixture = (35/100) * 4 = 7/5 parts Required % =[ [2+ (7/5)]/(10+4)] * 100

A) 1,77,366
Explanation: New population = 1,60,000 [(1 + (3/100)] [(1 + (2.5/100)] [(1 + (5/100)]

B) 1175
Explanation: Failed in 1st subject = (35/100) * 2500 = 875 Failed in 1st subject = (42/100) * 2500 = 1050 Failed in both = (15/100) * 2500 = 375 So failed in 1st subject only = 875 – 375 = 500 failed in 2nd subject only = 1050 – 375 = 675 passed in 1st only + passed In 2nd only = 675+500

C) 2/3
Explanation: Let original weight of bucket when it is filled with water = x Then weight of bucket = (25/100) * x = x/4 Original weight of water = x – (x/4) = 3x/4 Now when some water removed, new weight of bucket with remaining water = (50/100) * x = x/2 So new weight of water = new weight of bucket with remaining water – weight of bucket = [(x/2) – (x/4)] = x/4 So part of water removed = [(3x/4) – (x/4)]/(3x/4)

D) 3591
Explanation: Number of smokers after 3 months will be = 4000 * (1 + (5/100)) (1 – (5/100)) (1 – (10/100))
= 3591

B) 2000
Explanation: Let number of girls = x, then no of boys = (5000-x). then 10% of (1000-x) + 15% of x = (5600-5000) Solve, x = 2000