Test: Squares And Square Roots- 1 - UPSC MCQ

The answer is 1681 because it is the only number which has it's last digit as a number which a perfect square can have . 9×9=81 the last digit is 1.

Option B is correct because the unit digit of 161 is 1 and if unit digit of any digit ends with 1 the its square will also end with 1.

Option 1:
√576 = 24

Option 2:
√841 = 29

Option 3:
√778 = 27.89 It is not perfect square

Option D:
√529 = 23

Hence, the answer is option C.

The next smallest perfect square is 4.
The next smallest perfect cube is 8.
Since 4 is even, it is the smallest even number whose square root and cube root both exists as a natural number.
Therefore, the answer is (D) 64.

Since, 1 x 1 = 1

         2 x 2 = 4

         3 x 3 = 9

         4 x 4 = 16

         5 x 5 = 25

         6 x 6 = 36

         7 x 7 = 49

Thus, 36 is a perfact square number between 30 and 40.

The numbers ending with 0 gives 0,numbers ending with 1,9 gives 1, numbers ending with 2,8 gives 4, numbers ending with 3,7 gives 9, numbers ending with 5 gives 5 and numbers ending with 4,6 gives 6. Hence we get only 0,1,4,5,6,9 at the unit's place.

√0.053361
= √(5.3361 × 10^(-2))
= √(5.3361) × √(10^(-2))
= ±2.31 × 0.1
= ±0.231

12² = 12*12 = 144

13² = 13*13 = 169

Now numbers are between144 and 169 are:

145, 146, 147,.............168

Total number = 24

So total numbers lies between 144 and 169 is 24