Time And Work - MCQ 1 - SSC CGL MCQ

# Time And Work - MCQ 1 - SSC CGL MCQ

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## 20 Questions MCQ Test Quantitative Aptitude for SSC CGL - Time And Work - MCQ 1

Time And Work - MCQ 1 for SSC CGL 2024 is part of Quantitative Aptitude for SSC CGL preparation. The Time And Work - MCQ 1 questions and answers have been prepared according to the SSC CGL exam syllabus.The Time And Work - MCQ 1 MCQs are made for SSC CGL 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Time And Work - MCQ 1 below.
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Time And Work - MCQ 1 - Question 1

### A is twice efficient as B. A and B together do the same work in as much time as C and D can do together. If the ratio of the number of alone working days of C to D is 2:3 and if B worked 16 days more than C then no of days which A worked alone?

Detailed Solution for Time And Work - MCQ 1 - Question 1

The ratio of efficiencies of A and B = 2 : 1

Then the ratio of the number of days taken by A and B will be 1 : 2 (∵ Time is inversely proportional to efficiency)

Let the working days for A, B, C, and D are,

A = x, B = 2x, C = 2y, D = 3y

Now, 1/x + 1/2x = 1/2y + 1/3y

⇒ 3/2x = 5/6y

⇒ 18y = 10x

⇒ x : y = 9 : 5

And 2x – 2y = 16

Now, solving both the equations, we get,

⇒ x = 18 days.

∴Number of days which A worked alone is 18 days.

Time And Work - MCQ 1 - Question 2

### A can do a piece of work in 40 days B can do the same piece of work in 60 days. A and B started the work together in the first 15 days A worked with 50% of his efficiency, in the next 15days B worked with 50% of his efficiency. Now in how many days does the remaining work will be completed if both of them work with their full efficiencies?

Detailed Solution for Time And Work - MCQ 1 - Question 2

15*(1/80+1/60) + 15*(1/120+1/40) + x*(1/40+1/60) = 1 X= 3/2 = 1.5

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Time And Work - MCQ 1 - Question 3

### A can do a piece of work in 30 days, B can do in 45 days and C can do same work alone in 60 days. If on the first day A worked alone and on the second day A and B worked together and on the third day A and C worked together. If they repeat the cycle as follows then in how many days total work can be completed?

Detailed Solution for Time And Work - MCQ 1 - Question 3

First day = 1/30
Second day = 1/30+1/45
Third day = 1/30+1/60
3 days work = 3/30+1/45+1/60 = 25/180
3*7 = 21 days work = 175/180
Now 1/36 work is left which can be completed by A alone
1/36*30 = 5/6
21+5/6 = 21 5/6 Days

Time And Work - MCQ 1 - Question 4

Ramu completes 30% of work in 7.5 days. Raju is 50% as efficient as Ramu, Venu is 50% as efficient as Raju. Now Raju and Venu joined with Ramu for the rest of the work then in how many days will take to complete the work?

Detailed Solution for Time And Work - MCQ 1 - Question 4

Ramu takes 25 days to complete work.
Raju = 50 days Venu = 100 days
Now 70% work is left
They can complete whole work in = 1/ 1/25+1/50+1/100
100/7 days then 70% in 10 days

Time And Work - MCQ 1 - Question 5

A can do a piece of work in 21days. B is 50% more efficient than A. C is twice efficient than B. A started the work alone and worked for some days and left the work then B and C joined together and completed the work in 2 days. Then how many days does A worked alone?

Detailed Solution for Time And Work - MCQ 1 - Question 5

Time required by B = 2/3 × 21 = 14 days

C will take 7 days (As C is twice efficient than B)

Let total work be = LCM of 21, 14, 7 = 42 units and let A worked for x days alone.

Efficiency of A = 2

Efficiency of B = 3

Efficiency of A = 6

ATQ,

⇒ 2x + 9 × 2 = 42

⇒ 2x = 24

⇒ X = 12 days

∴ A works for 12 days alone.

Time And Work - MCQ 1 - Question 6

A can do a piece of work in 60days working 14 hours. B has the same efficiency as of A. A and B started working together. A works 5,6,7 and 8 hours respectively on first four days and repeats the cycle again. Then B has to work how many hours daily if they together completed the work in 80 days?

Detailed Solution for Time And Work - MCQ 1 - Question 6

Time And Work - MCQ 1 - Question 7

Sruthi, Swetha and Swati together can cut 216 Apples of the same size in 3 hours. Number of Apples cut by Sruthi in 9 hours is same as the number of Apples cut by Swati in 7 hours. In one hour, Swati can cut as many Apples more than Swetha as Swetha can cut more than Sruthi.Then the number of Apples cut by Swetha in one hour?

Detailed Solution for Time And Work - MCQ 1 - Question 7

Let's denote:

• Sruthi's efficiency as 'S' apples/hour
• Swetha's efficiency as 'W' apples/hour
• Swati's efficiency as 'T' apples/hour

Given information:

1. S * 9 = T * 7 => S = (7/9)T
2. T - W = W - S => T = 2W - S

Total work done in 3 hours:

• (S + W + T) * 3 = 216
• S + W + T = 72

Substituting S and T in terms of W:

• (7/9)T + W + 2W - (7/9)T = 72
• 3W = 72
• W = 24

Therefore, Swetha can cut 24 apples in one hour.

So, the correct answer is option B: 24.

Time And Work - MCQ 1 - Question 8

A can type 100 letters in 5 minutes. B and C typing together can type 50 letters in 2 minutes. If all of them working together then can type 90 letters in how many minutes?

Detailed Solution for Time And Work - MCQ 1 - Question 8

Time And Work - MCQ 1 - Question 9

A, B and C together can complete a work in 8 days. If A is 50% more efficient than B and B is 50% less efficient than C, then B alone will complete the same work in:

Detailed Solution for Time And Work - MCQ 1 - Question 9

Let the efficiency of C be 10 units a day.

B's efficiency = 10 - 10 × 50% = 5 units

A's efficiency = 5 + 5 × 50% = 7.5 units

So, the total work = 8 × (10 + 5 + 7.5)

⇒ 8 × 22.5 = 180 units

Now, B alone will complete the work in = 180/5

⇒ 36 days

∴ B alone will complete the work in 36 days.

Time And Work - MCQ 1 - Question 10

A piece of work is to be completed in 100days, 11 Men are employed to do the work it is found that after 50 days only 1/3 rd work is completed. Now additionally how many more Men are to be employed to work to finish the work in time?

Detailed Solution for Time And Work - MCQ 1 - Question 10

11*50/1/3 = (11+x)*50/2/3
X = 11

Time And Work - MCQ 1 - Question 11

Arun can do a piece of work in 40 days, but Bala can do the same work in 5 days less, than Arun, when working alone. Arun and Bala both started the work together but Bala left after some days and Arun finished the remaining work in 30 days with half of his efficiency but he did the work with Bala with his complete efficiency. For how many days they had worked together?

Detailed Solution for Time And Work - MCQ 1 - Question 11

1 day work of Arun and Bala = 1/40 + 1/35 = 15/280
Arun finished the remaining work in 30 days = 30 * 1/40 * 2 = 3/8
Remaining work done by Arun and Bala = 5/8
Worked together = (5/8)/(15/280) = 35/3 days.

Time And Work - MCQ 1 - Question 12

Kiran can do a work in 20 days, while Karan can do the same work in 25 days. They started the work jointly. Few days later Suman also joined them and thus all of them completed the whole work in 10 days. All of them were paid total Rs.1000. What is the share of Suman?

Detailed Solution for Time And Work - MCQ 1 - Question 12

Efficiency of Kiran = 5%
Efficiency of Karan = 4%
They will complete only 90% of the work = [(5+4)*10] = 90
Remaining work done by Suman = 10%.
Share of Suman = 10/100 * 1000 = 100

Time And Work - MCQ 1 - Question 13

7 Indian and 4 American finish a job in 6 days. 7 African and 3 American finish the same job in 8 days. The efficiency of each person of a particular nationality is same but different from others. One Indian One American and One African will complete the work in:

Detailed Solution for Time And Work - MCQ 1 - Question 13

7I + 4Am = 1/6
7Af + 4Am = 1/8
7I + 7Af + 7Am = 7/24
1I + 1Af + 1Am = 1/24
One Indian One American and One African will complete the work in – 24 days.

Time And Work - MCQ 1 - Question 14

Chitra is twice efficient as Arun. Bala takes thrice as many days as Chitra. Arun takes 12 days to finish the work alone. If they work in pairs(i.e Arun-Bala, BalaChitra, Chitra-Arun) starting with Arun – Bala on the first day, Bala – Chitra on the second day and Chitra – Arun on the third day and so on, then how many days are required to finish the work?

Detailed Solution for Time And Work - MCQ 1 - Question 14

No of days taken by Arun = 12 days
No of days(Arun:Bala:Chitra) = 2:3:1
1 day work of (Arun+Bala) = 5/36
1 day work of (Bala+Chitra) = 8/36
1 day work of (Chitra+Arun) = 9/36
5 days total work – 35/36
1/36 is done by Arun-Chitra
Number of days taken by Arun-Chitra for the rest of the work = (1/36)/(9/36) = 1/9
Total time taken to complete the work = 5 + 1/9 = 46/9 days

Time And Work - MCQ 1 - Question 15

A work is done by 30 workers not all of them have the same capacity to work. Every day exactly 2 workers, do the work with no pair of workers working together twice. Even after all possible pairs have worked once, all the workers together works for six more days to finish the work. Find the number of days in which all the workers together will finish the work?

Detailed Solution for Time And Work - MCQ 1 - Question 15

30 workers work in pairs, with no same pair of workers working together twice
29[1/w1 + 1/w2 ….. + 1/w30] + 6[1/w1 + 1/w2 ….. + 1/w30] = 1
[1/w1 + 1/w2 ….. + 1/w30] = 1/35
35 days.

Time And Work - MCQ 1 - Question 16

Arun can do a piece of work in 10 days, Bala in 15 days. They work together for 5 days, the rest of the work is finished by Chitra in two more days. If they get Rs.3000 as wages for the whole work, what are the daily wages of Arun, Bala and Chitra respectively (in Rs)?

Detailed Solution for Time And Work - MCQ 1 - Question 16

Time And Work - MCQ 1 - Question 17

A Contractor employed a certain number of workers to finish constructing a building in a certain scheduled time. Some time later, when a part of work had been completed, he realized that the work would get delayed by half of the scheduled time, so he at once doubled the no of workers and thus he managed to finish the building on the scheduled time. How much work he had been completed, before increasing the number of workers?

Detailed Solution for Time And Work - MCQ 1 - Question 17

D * x +(100- D) * 2x= 150x
⇒ D = 50 days
work done in 50 days = 50x
Total work = 150x
50x/150x * 100 = 100/3

Time And Work - MCQ 1 - Question 18

(x-2) person can do a work in x days and (x+7) person can do 75% of the same work in (x-10)days. Then in how many days can (x+10) person finish the work?

Detailed Solution for Time And Work - MCQ 1 - Question 18

3/4 * (x-2)x = (x+7)(x-10)
x – 6x – 280 = 0
x = 20; x = -14
(x-2)x = 18 * 20 = 360
360 = 30 * y
y = 12 days

Time And Work - MCQ 1 - Question 19

The ratio of efficiency of Arun is to Chitra is 5:3. The ratio of number of days taken by Bala is to Chitra is 2:3. Arun takes 6 days less than Chitra, when Arun and Chitra complete the work individually. Bala and Chitra started the work and left after 2 days. The number of days taken by Arun to finish the remaining work is?

Detailed Solution for Time And Work - MCQ 1 - Question 19

Ratio of number of days = 9:10:15
Work done By B and C in first two days = 2*1/6 = 1/3
Rest of the work = 2/3
Number of days = (2/3)/(1/9) = 6 days

Time And Work - MCQ 1 - Question 20

Arun is twice efficient as Bala and together they do the same work in as much time as Chitra and David together. If Chitra and David can complete the work in 20 and 30 days respectively, working alone, then in how many days A can complete the work individually?

Detailed Solution for Time And Work - MCQ 1 - Question 20

1/x + 1/2x = 1/20 + 1/30
3/2x = 1/12
Number of days taken by Arun = 18 days

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## Quantitative Aptitude for SSC CGL

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