A man can jump vertically to a height of 1.5m on the earth. Calculate the radius of a planet (in kms ) of the same mean density as that of the earth from whose gravitational field he could escape by jumping. Radius of earth is 6.41 × 106m.
For the asked planet this u should be equal to the escape velocity from its surface.
The correct answer is: 3.1
A particle is projected from point A that is at a distance 4R from the centre of the Earth will speed v1 in a direction making joining the centre of the Earth and point A as shown.find the speed v2 if particle passes grazing the surface of the earth Constant interaction only between these two Express you answer in the form (500 × √2X)m/s and write the value of X?
let v2 to be speed when it grazes earth
Conserving angular momentum we get
mv1sin30o4R = m.v2R.....(i)
Conserving total energy we get
1/2mV12 − GmM/4R
= 1/2 mV22 − GmM/R
putting V2 = V1sin30o × 4
= 2V1 we get
1/2mV12(1−4) = −3GmM/4R
X = (8000)/(500*2)
X = 8
A cord of length 64m is used to connect a 100kg astronaut. Estimate the value of the tension (in Newton) in the cord. Assume that the spaceship is orbiting near earth surface. Also assume that the spaceship and the astronaut fall on a straight line from the earth’s centre. The radius of the earth is 6400km.
As according to given problem the mass of satellite M is much greater than that of astronaut m so the centre of mass of the system will be close to satellite and as the satellite is orbiting close to the surface of earth, the equation of motion of the system (S + A) will be :
And the equation motion of the astronaut will be
So substituting the given data,
The correct answer is: 0.03
Ravi can throw a ball a speed on earth which can cross a river of width 10m. Ravi reaches on an imaginary planet whose mean density is twice of the earth. If maximum radius of planet so that if Ravi throws the ball at same speed it may escape from planet is xkm. then x is.
(Given radius of earth = 6.4 × 106m.)
Speed of the ball which can cross 10 m wide river is
Let the radius of planet is R,
Then, mass of planet
Escape velocity of planet
The correct answer is: 4
An earth satellite is revolving in a circular orbit of radius a with velocity v0. There is a gun in the satellite and is aimed directly towards the earth. A bullet is fired from the gun with muzzle velocity Neglecting resistance offered by cosmic dust and recoil of gun, the maximum and minimum distance of bullet from the centre of earth during its subsequent motion is na and Find the value of n.
Orbital speed of satellite is
From conservation of angular momentum at P and Q,
From conservation of mechanical energy at P and Q, we have
Substituting values of v and v0 from Eqs. (i) and (ii), we get
Hence, the maximum and minimum distance are 2a and 2a/3 respectively.
The correct answer is: 2
A body is projected vertically upwards from the surface of earth with a velocity sufficient to carry it to infinity. The time taken by it to reach height h is given by Find the value of n.
If at a distance r from the centre of the earth the body has velocity v, by conservation of mechanical energy,
The correct answer is: 1.5
A projectile of mass m is fired from the surface of the earth at an angle α = 60° from the vertical. The initial speed v0 is equal to The height projectile rises is given by nRe. Find the value of n. Neglect air resistance and the earth’s rotation.
Let v be the speed of the projectile at highest point and rmax its distance from the centre of the earth. Applying conservation of angular momentum and mechanical energy,
Solving these two equation with the given data we get,
or the maximum height
The correct answer is: 0.5
If a planet was suddenly stopped in its orbit supposed to be circular, it will fall onto the sun in a time times the period of the planet’s revolution. Find the value of n.
Consider and imaginary planet moving along a strongly extended flat ellipse, the extreme points of which are located on the planet’s orbit and at the centre of the sun. The semi-major axis of the orbit of such a planet would apparently be half the semi-major axis of the planet’s orbit. So the time period of the imaginary planet T' according to Kepler’s law will be given by
∴ Time taken by the planet to fall onto the sun is
The correct answer is: 8
An artificial satellite is moving in a circular orbit around the earth with a speed equal to half the magnitude of escape velocity from the surface of earth. (Radius of the earth = 6400km ). If the satellite is stopped suddenly in its orbit and allowed to fall freely on the earth, find the speed (in m/s) with which it hits the surface of earth.
or h - r - R = R or height = radius of earth.
Increase in kinetic energy = decrease in potential energy
Substituting the values we have,
The correct answer is: 7924
Two planets of equal mass orbit a much more massive star (figure). Planet m1 moves in a circular orbit of radius 1 × 108km with period 2year. Planet m2 moves in an elliptical orbit with closed distance r1 = 1 × 108km and farthest distance r2 = 1.8 × 108km, as shown.
Using the fact that the mean radius of an elliptical orbit is the length of the semi-major axis, find the period of m2's orbit.
Mean radius of planet,
The correct answer is: 3.31