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*Answer can only contain numeric values

QUESTION: 1

A block of mass 4*kg* is kept on ground. The coefficient of friction between the block and the ground is 0.80. An external force of magnitude 30*N* is applied parallel to the ground. The resultant force (in *N*) exerted by the ground on the block is : (*g *=10 *m*/*s*^{2})

Solution:

The correct answer is: 50

*Answer can only contain numeric values

QUESTION: 2

A block of mass 15*kg* is resting on a rough inclined plane as shown in figure. The block is tied up by a horizontal string which has a tension of 50*N*. The coefficient of friction between the surface of contact is (*g *= 10 *m*/*s*^{2})

Solution:

The free body diagram of the block is

*N* is the normal reaction exerted by inclined plane on the block.

Applying Newton’s second law to the block along the normal to the incline.

Solving we get μ = 1/2

The correct answer is: 0.5

*Answer can only contain numeric values

QUESTION: 3

An external force of 6 *N* is applied on body at rest at time t = 0. At t = 1 *sec* direction of force is reversed. Find the speed *ms*^{–1} of body when it comes back to the initial position.

Solution:

The correct answer is: 1.095

*Answer can only contain numeric values

QUESTION: 4

Figure shows a block kept on a rough inclined plane. The maximum external force along the plane downwards for which the block remains at rest is 1*N* while the maximum external force along the incline upwards for which the block is at rest is 7*N*. The coefficient of static friction μ is :

Solution:

When block is about to slide down

When block in about to slide up

From (1) and (2)

The correct answer is: 0.769

*Answer can only contain numeric values

QUESTION: 5

What is the maximum value of the force *F* (in *N*) such that the block shown in the arrangement does not move?

Solution:

The correct answer is: 20

*Answer can only contain numeric values

QUESTION: 6

A block is given velocity 10 *m/s* along the fixed inclined as shown in figure from the bottom of the inclined plane. Find the total distance traveled (in *meter*) along the inclined plane, if the coefficient of friction is equal to 0.5 :

Solution:

distance traveled along inclined plane till it stops

But friction force is not sufficient to stop there, so it will come back to the bottom of the inclined plane.

Total distance traveled 5 + 5 = 10*m*

The correct answer is: 10

*Answer can only contain numeric values

QUESTION: 7

A uniform rope so lies on a table that part of it lays over. The rope begins to slide when the length of hanging part is 25% of entire length. The coefficient of friction between rope and table is :

Solution:

The correct answer is: 0.33

*Answer can only contain numeric values

QUESTION: 8

With reference to the figure shown, if the coefficient of friction at the surface is 0.42, then the forces *F* (in *N*) required to pull out the 6.0*kg* block with an acceleration of 1.50 *m/s*^{2} will be :

Solution:

The correct answer is: 51

*Answer can only contain numeric values

QUESTION: 9

Starting from rest a body slides down a 45° inclined plane in twice the time it takes to slide down the same distance in the absence of friction. The coefficient of friction between the body and the inclined plane is :

Solution:

Let acceleration in 1st case is a_{1} and that in second case is a_{2}

From (1), (2) and (3), we get

μ = 0.75

The correct answer is: 0.75

*Answer can only contain numeric values

QUESTION: 10

A body of mass 10*kg* lies on a rough horizontal surface. When a horizontal force of *F* *newtons* acts on it, it gets an acceleration of 5 *m/s*^{2}. When the horizontal force is doubled, it gets an acceleration of 18 *m/s*^{2}. The coefficient of friction between he body and the horizontal surface is :

Solution:

From (1) and (2)

μ = 0.8

The correct answer is: 0.8

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