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# Maxwell's Equation MCQ Level - 2

## 10 Questions MCQ Test Topic wise Tests for IIT JAM Physics | Maxwell's Equation MCQ Level - 2

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This mock test of Maxwell's Equation MCQ Level - 2 for IIT JAM helps you for every IIT JAM entrance exam. This contains 10 Multiple Choice Questions for IIT JAM Maxwell's Equation MCQ Level - 2 (mcq) to study with solutions a complete question bank. The solved questions answers in this Maxwell's Equation MCQ Level - 2 quiz give you a good mix of easy questions and tough questions. IIT JAM students definitely take this Maxwell's Equation MCQ Level - 2 exercise for a better result in the exam. You can find other Maxwell's Equation MCQ Level - 2 extra questions, long questions & short questions for IIT JAM on EduRev as well by searching above.
QUESTION: 1

### A parallel plate capacitor is being discharged. What is the direction of the energy flow in terms of the Poynting vector in the space between the plates? Solution: As the capacitor is being discharged, field is decreasing Using expression for curl in cylindrical coordinates, we get Since there is φ symmetry Thus, magnetic field in direction will be induced, since,
∴ Direction of poynting vector  radially outward

The correct answer is: Radially outward QUESTION: 2

### Magnetic field in a region is the induced electric field due to this time varying magnetic field is

Solution:

The induced electric field lines are concentric circles with clockwise direction.
Physical argument for the direction is that if we put a conducting loop in the magnetic field current will flow in clockwise direction.
∴  Along a circle of radius r, we get Here means is in each a direction to oppose change in flux.
The correct answer is: QUESTION: 3

### Consider a capacitor placed in free space, consisting of two concentric circular parallel plate of radii r. The separation d  between the plates. The capacitor is connected to an oscillating voltage source of voltage  v(t) = V0 sin(ωt). The magnetic field vector between the plate at a distance r/2 from the axis of the capacitor.

Solution: Let us take a loop of radius x with centre on the axis Current enclosed Applying Maxwell’s equation The correct answer is: QUESTION: 4

Consider the following where E = electric field and B = magnetic field. Which of the above equations predict(s) the electric field E to be zero?

Solution: Electric flux is zero. It may happen for E ⊥ ds. Potential difference is zero.
E is not necessarily zero. ⇒ E is produced, if magnetic flux changes with time. Thus, no equation gives E as zero.

The correct answer is: None of these

QUESTION: 5

The magnetic field associated with the electric field vector is given by

Solution: Let us use the equation   (After integration) The correct answer is: QUESTION: 6

Differential form of Gauss’s law in magnetostatics is _____________

Solution:

Gauss’s law in magnetostatics states that the surface integration of magnetic fields over a closed surface is zero. Its differential form is: div B = 0.

QUESTION: 7

Which of the following four equations show that (i) the magnetic field lines cannot start from a point nor end at a point and (ii) the electrostatic field lines cannot form closed loops? Select the correct answer using the codes given below :

Solution:

The magnetic field lines cannot start from a point nor end at a point, i,e., there are no magnetic mono poles. Magnetic filed lines have no source or sink to start or stop.
Thus, If electric field lines cannot form The correct answer is: 2 and 3, respectively

QUESTION: 8

An electromagnetic wave travels along z-axis. Which of the following pair of space and time varying fields would generate such a wave?

Solution:

Ex and By would generate a plane electromagnetic wave travelling in z-direction. E, B and k form a right handed system where k is along z-axis. (As, i x j = k) ∴ E is along x-axis and B is along y-axis QUESTION: 9

LASER are light source which give almost perfectly parallel beam of high intensity. If a 2kW laser beam is concentrated by a lens into cross-sectional area about 10–6 cm2, then the value of Poynting vector

Solution:

Power = 2 kW = 2 × 103 W
Cross-sectional area = 106 cm2
Poynting vector S = P/A The correct answer is: 2 × 1013 W/m2

QUESTION: 10

Which of the following is the expression for Lorentz force?

Solution:

Lorentz force is the force on a particle when it moves through a medium where both magnetic and electric fields are present.