Maxwell's Equation MCQ Level - 2


10 Questions MCQ Test Topic wise Tests for IIT JAM Physics | Maxwell's Equation MCQ Level - 2


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This mock test of Maxwell's Equation MCQ Level - 2 for IIT JAM helps you for every IIT JAM entrance exam. This contains 10 Multiple Choice Questions for IIT JAM Maxwell's Equation MCQ Level - 2 (mcq) to study with solutions a complete question bank. The solved questions answers in this Maxwell's Equation MCQ Level - 2 quiz give you a good mix of easy questions and tough questions. IIT JAM students definitely take this Maxwell's Equation MCQ Level - 2 exercise for a better result in the exam. You can find other Maxwell's Equation MCQ Level - 2 extra questions, long questions & short questions for IIT JAM on EduRev as well by searching above.
QUESTION: 1

A parallel plate capacitor is being discharged. What is the direction of the energy flow in terms of the Poynting vector in the space between the plates?

Solution:

As the capacitor is being discharged, field is decreasing

Using expression for curl in cylindrical coordinates, we get


Since there is φ symmetry

Thus, magnetic field in  direction will be induced, since,
∴ Direction of poynting vector 

 radially outward

The correct answer is: Radially outward 

QUESTION: 2

Magnetic field in a region is  the induced electric field due to this time varying magnetic field is

Solution:

The induced electric field lines are concentric circles with clockwise direction.
Physical argument for the direction is that if we put a conducting loop in the magnetic field current will flow in clockwise direction.
∴  Along a circle of radius r, we get

Here  means  is in each a direction to oppose change in flux.
The correct answer is:  

QUESTION: 3

Consider a capacitor placed in free space, consisting of two concentric circular parallel plate of radii r. The separation  between the plates. The capacitor is connected to an oscillating voltage source of voltage  v(t) = V0 sin(ωt). The magnetic field vector between the plate at a distance r/2 from the axis of the capacitor.

Solution:


Let us take a loop of radius x with centre on the axis 
Current enclosed

Applying Maxwell’s equation

The correct answer is: 

QUESTION: 4

Consider the following


where E = electric field and B = magnetic field. Which of the above equations predict(s) the electric field E to be zero?

Solution:


Electric flux is zero. It may happen for E ⊥ ds.

Potential difference is zero.
E is not necessarily zero.


⇒ E is produced, if magnetic flux changes with time. Thus, no equation gives E as zero.

The correct answer is: None of these

QUESTION: 5

The magnetic field associated with the electric field vector  is given by

Solution:

Let us use the equation



 (After integration)

The correct answer is:  

QUESTION: 6

Differential form of Gauss’s law in magnetostatics is _____________ 

Solution:

Gauss’s law in magnetostatics states that the surface integration of magnetic fields over a closed surface is zero. Its differential form is: div B = 0.

QUESTION: 7

Which of the following four equations show that (i) the magnetic field lines cannot start from a point nor end at a point and (ii) the electrostatic field lines cannot form closed loops?

Select the correct answer using the codes given below :

Solution:

The magnetic field lines cannot start from a point nor end at a point, i,e., there are no magnetic mono poles. Magnetic filed lines have no source or sink to start or stop.
Thus,  If electric field lines cannot form 

The correct answer is: 2 and 3, respectively

QUESTION: 8

An electromagnetic wave travels along z-axis. Which of the following pair of space and time varying fields would generate such a wave?

Solution:

Ex and By would generate a plane electromagnetic wave travelling in z-direction. E, B and k form a right handed system where k is along z-axis. (As, i x j = k) ∴ E is along x-axis and B is along y-axis

QUESTION: 9

LASER are light source which give almost perfectly parallel beam of high intensity. If a 2kW laser beam is concentrated by a lens into cross-sectional area about 10–6 cm2, then the value of Poynting vector

Solution:

Power = 2 kW = 2 × 103 W
Cross-sectional area = 106 cm2
Poynting vector S = P/A

The correct answer is: 2 × 1013 W/m2

QUESTION: 10

Which of the following is the expression for Lorentz force?

Solution:

Lorentz force is the force on a particle when it moves through a medium where both magnetic and electric fields are present.

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