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# OP AMP MCQ Level – 2

## 10 Questions MCQ Test Topic wise Tests for IIT JAM Physics | OP AMP MCQ Level – 2

Description
This mock test of OP AMP MCQ Level – 2 for IIT JAM helps you for every IIT JAM entrance exam. This contains 10 Multiple Choice Questions for IIT JAM OP AMP MCQ Level – 2 (mcq) to study with solutions a complete question bank. The solved questions answers in this OP AMP MCQ Level – 2 quiz give you a good mix of easy questions and tough questions. IIT JAM students definitely take this OP AMP MCQ Level – 2 exercise for a better result in the exam. You can find other OP AMP MCQ Level – 2 extra questions, long questions & short questions for IIT JAM on EduRev as well by searching above.
QUESTION: 1

### The circuit connection of Op-Amp given in the figure (i) and (ii) represent

Solution:

The circuit connection of Op-Amp given in figure (i) and (ii) represents logarithmic amplifier for figure (i) and detector for figure (ii)
The correct answer is: Logarithmic amplifier for figure (i) and detector for figure (ii)

QUESTION: 2

### Given the circuit below, calculate the output voltage of the non-inverting Op-Amp summer:

Solution:

The output voltage of a non-inverting Op-Amp is.

= 12V

QUESTION: 3

### What should be the values of the component R and R2 such the frequency of the Wien bridge oscillator is 300Hz? (given C = 0.01 μf and R1 = 12kΩ.

Solution:

The frequency of oscillation f0 is exactly the resonant frequency of balanced Wien bridge and is given by

Assuming that the resistor are equal in value, and the capacitors are equal is value in the reactive lag of the wien bridge. At the frequency, the gain required for sustained oscillation is given by

QUESTION: 4

A non-inverting Op-Amp summer is shown in the figure. The output voltage V0 is

Solution:

V0 = -2(1 + 2R/R) + (2 + sin 100 t)(1 + 2R/R)

= – 6 + 6 + 3 sin 100 t

3 sin 100 t

QUESTION: 5

When negative feedback is used, then the gain bandwidth product of an Op-Amp.

Solution:

Applying the feedback will reduce the gain but increase the bandwidth hence, the gain bandwidth product = Ax f. he remains constant for any voltage feedback amplifier.
The correct answer is: stays the same

QUESTION: 6

The low-pass active filter shown in the figure has a cut-off frequency of 2kHz and a pass band gain of 1.5. The values of the resistors are :

Solution:

At f = fcc (cut o ff frequency at which gain falls to  of its low frequency value)

(i) Pass-Band gain = Amax = 1.5.
Hence,

QUESTION: 7

The circuit below represent a non-inverting integrator. Find the expression for the output voltage.

Solution:

Let the inverting terminal of Op-Amp is at potential ‘V and hence non-inverting terminal also appears to have the same potential ‘V due to virtual ground concept.
Input current to op-amp is zero. Hence at non-inverting terminal mode, we have

Input current to Op-Amp is zero. Hence at inverting terminal mode we have

Substituting the values and solving all the above equations, we get

QUESTION: 8

The transistor gain of the circuit shown in figure is given by

Solution:

A and B can be measured at the same potential. From figure;

or

Also

Combing (i) and (ii)

QUESTION: 9

The output voltage at the end of second amplifier V01  is :

The following circuit contains 3 Op-Amps and resistors.

Solution:

Similarly

QUESTION: 10

The output V02 (at the end of third Op-Amp) of the below circuit is :

Solution:

Similarly