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This mock test of Polarization NAT for Physics helps you for every Physics entrance exam.
This contains 10 Multiple Choice Questions for Physics Polarization NAT (mcq) to study with solutions a complete question bank.
The solved questions answers in this Polarization NAT quiz give you a good mix of easy questions and tough questions. Physics
students definitely take this Polarization NAT exercise for a better result in the exam. You can find other Polarization NAT extra questions,
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*Answer can only contain numeric values

QUESTION: 1

Unpolarized light of intensity. I_{0}, is incident on a series of 3 polarizing filters, the axis of the second filter is oriented at 45° to that of the first filter, while the axis of the third filter is oriented at 90° to that of the first filter. What fraction of the incident light that is transmitted through the third filter?

Solution:

Light through the first filter is

I_{0}= Incident intensity.

Through the second filter

Through the third filter, intensity is

The correct answer is: 0.125

*Answer can only contain numeric values

QUESTION: 2

The critical angle of light in a certain substance is 45°. What is the polarising angle?

Solution:

** Answer :- 54.7degree**

**Solution :- If 'n' is refractive index and ic is critical velocity,**

** n = 1/Sin ic = 1 / Sin 45 = 1.414 **

**Now, According to Brewster's law , if ' ip ' is polarising angle then **

**n = tan ip **

**So , tan ip = 1.414 **

** i.e. ip = 54.7 ^{0}**

*Answer can only contain numeric values

QUESTION: 3

Unpolarized light is incident on two ideal polarizers in series, the polarizers are oriented so that no light emerges through the second polarizer. A third polarizer is now inserted between the first two and its orientation direction is continuously rotated through 180°.

What is the maximum fraction of the incident power transmitted through all three polarizers?

Solution:

Let incident intensity be I

Intensity after first polarizer =

Intensity after the second polarizer = I_{1} cos^{2 }Ø

where Ø s the angle between the polarizer pass axis of the second polarizer and first polarizer

Intensity of light through the 3rd polarizer is

Intensity of light through the 3rd polarizer is I_{3 }= I_{2} cos^{2} θ

where θ is the angle between pass axis polarizer 2 and 3. For I_{3} to be maximum.

Put because

the first and third polarizers are orthogonal

Put

Fraction is 0.125

The correct answer is: 0.125

*Answer can only contain numeric values

QUESTION: 4

The critical angle of a medium is 45° Find the polarizing angle.

Solution:

= 54.75°

The correct answer is: 54.75

*Answer can only contain numeric values

QUESTION: 5

A beam of light polarized in the x direction is travelling in the z direction. It passess through a polarizer, travels some distance, and reaches an analyser you can orient the pass axis of the analyzer only in the x or the y direction. You find that the intensity is three times smaller when the pass axis of the analyser is in the y direction than it was when the pass axis was in the x direction Find the angle between the pass axis of the polarizer and the x-axis (in degrees).

Solution:

If θ is the angle of polarizer’s pass axis with the x-axis and / is the intensity of the light beam between the polarizer and the analyzer.

The correct answer is: 30

*Answer can only contain numeric values

QUESTION: 6

Unpolarized light is incident on a pair of ideal linear polarizers whose transmission axis make an angle of 45° with each other, the transmitted light intensity through both polarizers in what percentage of the incident intensity?

Solution:

Light incident = **l _{0}**

Intensity of light through first polarizer =

Intensity of light through second polarizer =

Percentage =

= 25%

The correct answer is: 25

*Answer can only contain numeric values

QUESTION: 7

A beam of light polarized in the x direction is travelling in the z direction. It passess through a polarizer, travels some distance, and reaches an analyser you can orient the pass axis of the analyzer only in the x or the y direction. You find that the intensity is three times smaller when the pass axis of the analyser is in the y direction than it was when the pass axis was in the x direction Suppose that the original light beam were polarized in the / direction, everything else remaining the same. What value of would you observe?

Solution:

Using the polarized light would change the beam intensity / between the polarizer and analyser but it would not change the ratio

The correct answer is: 3

*Answer can only contain numeric values

QUESTION: 8

The refractive indices of glass and water are 1.54 and 1.33. Which will be greater: the polarising angle for a beam incident from water to glass or that for a beam incident from glass to water?

Solution:

By Brewster’s law, the polarising angle p is given by

tan p = μ,

Where μ is the refractive index of the second medium with respect to the first.

For water to glass,

p = tan^{-1} (1.158) = 49.2°

For glass to water,

p = tan^{-1 }(0.864) = 40.8°

Thus, p is larger from water to glass.

The correct answer is: 40.8

*Answer can only contain numeric values

QUESTION: 9

If the polarizing angle of a medium is 60°. Then find the angle of refraction, (in degrees)

Solution:

Polarizing angle is the angle of incidence for which the refracted and reflected rays are orthogonal.

θ_{i }= 60°

⇒ θ_{reflected }= 60°

⇒ θ_{reflected} = 90°- 60° = 30°

The correct answer is: 30

*Answer can only contain numeric values

QUESTION: 10

If the refractive index of a medium is 1.732, then find the polarizing angle (in degrees) of the medium.

Solution:

The correct answer is: 60

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