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This mock test of Rigid Body Dynamics MCQ Level - 1 for Physics helps you for every Physics entrance exam.
This contains 10 Multiple Choice Questions for Physics Rigid Body Dynamics MCQ Level - 1 (mcq) to study with solutions a complete question bank.
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QUESTION: 1

A uniform rod of length * L* and weight

Solution:

The forces on rod hinged at * O*, which cause torque about

Since net torque on rod about hinge at * O* is zero

QUESTION: 2

Moment of inertia of a disc object * OO'* is :

Solution:

(by perpendicular axis theorem)

by applying parallel axis theorem

The correct answer is:

QUESTION: 3

A uniform circular disc placed on a horizontal rough surface has initially a velocity **v**_{0} and an angular velocity ω_{0} as shown in the figure :

The disc comes to rest after moving some distance in the direction of motion. Then

Solution:

The correct answer is: r/2

QUESTION: 4

The moment of inertia of a door of mass * m*, length 2ℓ and width ℓ about its longer side is :

Solution:

Using parallel axis theorem : *I _{AD}* =

*I* (about *AD*)

The correct answer is:

QUESTION: 5

Three identical uniform rods, each of length ℓ, are joined to form a rigid equilateral triangle. Its radius of gyration about an axis passing through a corner and perpendicular to the plane of the triangle is :

Solution:

** MI** of the system w.r.t. an axis ⊥ to plane and passing through one corner

Now, the radius of gyration is

The correct answer is:

QUESTION: 6

A wheel is rolling uniformly along a level road (see fig.) The speed of translational motion of the wheel axis is * v*. What are the speed of the points

Solution:

The correct answer is: * V_{A}* = 0,

QUESTION: 7

A uniform cube of side * a* and mass

Solution:

Taking moments abut point **O****:**

Moment of * N* (normal reaction) and

The correct answer is:

QUESTION: 8

A thin wire of length * L* and uniform density ρ is bent into a circular loop with centre at

Solution:

(by parallel axis theorem)

by putting value of * m* and

The correct answer is:

QUESTION: 9

A particle performs uniform circular motion with an angular momentum * L*. If the frequency of particle’s motion is doubled and its kinetic energy is halved, the angular momentum becomes :

Solution:

Kinetic energy

The correct answer is: L/4

QUESTION: 10

Three rings each of mass * m* and radius

Solution:

* I* =

Moment of inertia = 3**mk**^{2} where * k* is radius of gyration.

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