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This mock test of Semiconductor Diode NAT Level - 2 for IIT JAM helps you for every IIT JAM entrance exam.
This contains 10 Multiple Choice Questions for IIT JAM Semiconductor Diode NAT Level - 2 (mcq) to study with solutions a complete question bank.
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*Answer can only contain numeric values

QUESTION: 1

Calculate form factor of halfwave rectifier ?

Solution:

The ratio of rms value to the average value is called form factor. Thus,

form factor

The correct answer is: 1.57

*Answer can only contain numeric values

QUESTION: 2

Calculate the zener current in the given circuit in mA?

Solution:

and

Now 130-60 = **IR
**

Now,

I

The correct answer is: 2

*Answer can only contain numeric values

QUESTION: 3

A 24V, 600mW, zener diode is to be used in for providing a 24 Vstabilized supply to variable load.

Assuming for a proper zener action, a minimum of 10mA must flow through the zener. If the input voltage is 32 V. What would be the value of R_{L} (in ohm).

Solution:

The correct answer is: 320

*Answer can only contain numeric values

QUESTION: 4

What is the potential difference across R_{1} (in volts) ?

Solution:

D_{2} is reverse biased, hence, no current flow through it.

6 - iR_{2 - }iR_{1}=0

Now potential difference across R_{1 }

**= 2V**

The correct answer is: 2

*Answer can only contain numeric values

QUESTION: 5

The 6 Volts zener diode shown in figure has zero zener resistance and knee current of 5mA. The minimum value of R (in Ω), so that the voltage across it does not fall below 6 Volts is ?

Solution:

The correct answer is: 80

*Answer can only contain numeric values

QUESTION: 6

Calculate the diffusion current density when the concentration of electron varies from the 1 * 10^{18} to 7 * 10^{17} cm^{-3} over a distance of 0.10 cm. D = 225cm^{2}/s

Solution:

J = eDdn / dx

J = 1.6 * 10^{-19} * 225 * (10^{18 }- (7 * 10^{17})) / 0.1

= 108A/cm^{2}.

*Answer can only contain numeric values

QUESTION: 7

The centre tap full-wave single phase rectifier circuit uses 2 diodes as shown in the given figure. The rms voltage across each diode is (in Volts)

Solution:

Peak inverse voltage (**PIV**) across each diode =_{}when diode is conducting (during half cycle) the voltage across the diode is zero.

Hence, rms value of voltage across the diode =

The correct answer is: 339.4

*Answer can only contain numeric values

QUESTION: 8

A half-wave rectifier employs a transformer with turn ratio n_{1} : n_{2 }= 12 : 1. If primary coil is connected to the power mains 220V, 50Hz. If the diode resistance in forward bias is negligible, what is the peak inverse voltage (in Volts) of the diode?

Solution:

The turn ratio of transform ation is 12:1. So if primary coil is connected to power mains o f 220V , then potential of secondary coil is Volts. In a half-wave rectifier,is the maximum voltage appearing across the transformer secondary coil. Now. peak inverse voltage, for half wave rectifier in given as V_{0
}

= 25.9V

The correct answer is: 25 .9

*Answer can only contain numeric values

QUESTION: 9

A 10V zener diode working as a voltage regulator operates from a source that varies from 5 V to 15V, the series resistance is 0.1kΩ and the load draws a current that varies from 0 to 20mA. The power dissipation in the zener diode under worst case (in Watts) is?

Solution:

For maximum power dissipation, current through zener diode should be maximum which is maximum when total current in the circuit is maximum i.e. V_{s} = 15V.

The correct answer is: 0.5

*Answer can only contain numeric values

QUESTION: 10

When three zener diodes of identical specification having 10W, 10 V, l000 mA are connected in series to a 45V~dc power supply. Calculate the series resistance required to obtain 30 V regulated output (in Ω)?

Solution:

Power of each diode = 10**W**

Potential = 10**V **

⇒ current = 1**A**

⇒ Resistance of each zener diode **R**

⇒ Equivalent resistance of three diodes connected in series

The correct answer is: 15

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