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HOTs for Maths Olympiad - 4 - Class 5 MCQ


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10 Questions MCQ Test Math Olympiad for Class 5 - HOTs for Maths Olympiad - 4

HOTs for Maths Olympiad - 4 for Class 5 2025 is part of Math Olympiad for Class 5 preparation. The HOTs for Maths Olympiad - 4 questions and answers have been prepared according to the Class 5 exam syllabus.The HOTs for Maths Olympiad - 4 MCQs are made for Class 5 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for HOTs for Maths Olympiad - 4 below.
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HOTs for Maths Olympiad - 4 - Question 1

Read the given statements carefully and select the correct option.
Statement-I: The value of 482.65 + 317.85 when rounded to the nearest tenths is 800.5.
Statement-II: The product of 56 × 23 is greater than 1300.

Detailed Solution for HOTs for Maths Olympiad - 4 - Question 1

Statement-I: The value of 482.65 + 317.85 when rounded to the nearest tenths is 800.5.

First, let's add the two numbers:
482.65 + 317.85 = 800.5.
Now, rounding 800.5 to the nearest tenth gives 800.5 because the digit in the hundredths place is 5. So, the value remains 800.5 after rounding.

Therefore, Statement-I is true.

Statement-II: The product of 56 × 23 is greater than 1300.

Let's calculate the product of 56 and 23:
56 × 23 = 1288.
Since 1288 is less than 1300, Statement-II is false.

Thus, the correct option is C: Statement-I is true but Statement-II is false.

HOTs for Maths Olympiad - 4 - Question 2

Fill in the blanks and select the correct option.
(i) The greatest common divisor (GCD) of 54 and 90 is P.
(ii) The sum of 789 and 1234 when rounded to the nearest hundred is Q.
(iii) The product of 25 × 12 is R.

Detailed Solution for HOTs for Maths Olympiad - 4 - Question 2

(i) The greatest common divisor (GCD) of 54 and 90 is P:

The divisors of 54 are: 1, 2, 3, 6, 9, 18, 27, 54.

The divisors of 90 are: 1, 2, 3, 5, 6, 9, 15, 18, 30, 45, 90.

The greatest common divisor (GCD) of 54 and 90 is 18.

So, P = 18.

(ii) The sum of 789 and 1234 when rounded to the nearest hundred is Q:

First, calculate the sum:
789 + 1234 = 2023.

Rounding 2023 to the nearest hundred gives 2000.

So, Q = 2000.

(iii) The product of 25 × 12 is R:

25 × 12 = 300.

So, R = 300.

Thus, the correct answer is A: (P)-18, (Q)-2000, (R)-300.

HOTs for Maths Olympiad - 4 - Question 3

Nina made a chart showing the distance she traveled each day. Based on the given information, select the incorrect option.

Detailed Solution for HOTs for Maths Olympiad - 4 - Question 3

Option A: Let's calculate the total distance traveled by Nina in 5 days:
Total = 12 km 350 m + 15 km 600 m + 10 km 750 m + 8 km 500 m + 13 km 400 m
= 60 km 600 m.
So, Statement A is correct.

Option B: The distance traveled on Thursday is 8 km 500 m, and on Tuesday, it is 15 km 600 m. The difference is:

15 km 600 m - 8 km 500 m = 7 km 100 m.
So, Nina traveled 7 km 100 m less on Thursday than on Tuesday, not 7 km 250 m.
Statement B is incorrect.

Option C: The distance traveled on Wednesday is 10 km 750 m, and on Thursday, it is 8 km 500 m.
The difference is:
10 km 750 m - 8 km 500 m = 2 km 250 m.
Statement C is correct.

Option D: Nina traveled 13 km 400 m on Friday, as stated in the table.
Statement D is correct.
The incorrect option is B: Nina traveled 7 km 250 m less on Thursday than on Tuesday.

HOTs for Maths Olympiad - 4 - Question 4

A shopkeeper sold goods worth ₹458000 in a month. If his expenses were ₹389560, how much profit did he make?

Detailed Solution for HOTs for Maths Olympiad - 4 - Question 4

To calculate the profit, subtract the expenses from the sales:

  • Sales = ₹458000
  • Expenses = ₹389560

Profit = Sales - Expenses
Profit = ₹458000 - ₹389560 = ₹68440

Thus, the profit made by the shopkeeper is ₹68440. Therefore, the correct answer is A: ₹68440.

HOTs for Maths Olympiad - 4 - Question 5

Read the given statements carefully and select the correct option.
Statement-I: The value of 345.78 + 654.22 when rounded to the nearest whole number is 1000.
Statement-II: The difference between 987 and 512 is greater than 470.

Detailed Solution for HOTs for Maths Olympiad - 4 - Question 5

Statement-I: The value of 345.78 + 654.22 when rounded to the nearest whole number is 1000.

Let's first add the two numbers:
345.78 + 654.22 = 1000.00.

Now, rounding 1000.00 to the nearest whole number gives 1000.
Statement-I is true.

Statement-II: The difference between 987 and 512 is greater than 470.

Let's calculate the difference:
987 - 512 = 475.

Since 475 is greater than 470, Statement-II is true.

Thus, Statement-I is true, and Statement-II is true.

So, the correct option is D: Both Statement-I and Statement-II are true.

HOTs for Maths Olympiad - 4 - Question 6

Read the given statements carefully and select the correct option.
Statement-I: The sum of the first five prime numbers is 28.
Statement-II: The difference between 729 and 245 is less than 490.

Detailed Solution for HOTs for Maths Olympiad - 4 - Question 6

Statement-I: The sum of the first five prime numbers is 28. The first five prime numbers are 2, 3, 5, 7, and 11.
The sum of these numbers is:
2 + 3 + 5 + 7 + 11 = 28.
Therefore, Statement-I is true.

Statement-II: The difference between 729 and 245 is less than 490.
Let's calculate the difference:
729 - 245 = 484.
Since 484 is less than 490, Statement-II is true.

Thus, the correct option is A: Both Statement-I and Statement-II are true.

HOTs for Maths Olympiad - 4 - Question 7

Fill in the blanks and select the correct option.
(i) The value of 874−349 when rounded to the nearest ten is ___ P.
(ii) The product of 23×45 is ___Q.
(iii) The LCM of 12 and 18 is ___R.

Detailed Solution for HOTs for Maths Olympiad - 4 - Question 7

(i) The value of 874 - 349 when rounded to the nearest ten is P:

First, calculate the difference:
874 - 349 = 525.

Now, rounding 525 to the nearest ten gives 530 because the digit in the ones place is 5, which rounds the number up.
So, P = 530.

(ii) The product of 23 × 45 is Q:

Calculate the product:
23 × 45 = 1035.
So, Q = 1035.

(iii) The LCM of 12 and 18 is R:

To find the LCM of 12 and 18, list their multiples:

Multiples of 12: 12, 24, 36, 48, 60, ...

Multiples of 18: 18, 36, 54, 72, ...

The smallest common multiple is 36.
So, R = 36.

Thus, the correct answer is B: (P)-530, (Q)-1035, (R)-36.

HOTs for Maths Olympiad - 4 - Question 8

A library had 7680 books. If 543 books were damaged, how many books are left?

Detailed Solution for HOTs for Maths Olympiad - 4 - Question 8

The total number of books in the library is 7680, and 543 books were damaged.

To find how many books are left, subtract the number of damaged books from the total number of books:

Books left = 7680 - 543 = 7137

Thus, the number of books left is 7137. Therefore, the correct answer is A: 7137.

HOTs for Maths Olympiad - 4 - Question 9

Read the given statements carefully and select the correct option.
Statement-I: The estimated value of 495 + 389 to the nearest hundred is 900.
Statement-II: The square of 12 is 144.

Detailed Solution for HOTs for Maths Olympiad - 4 - Question 9

Statement-I: The estimated value of 495 + 389 to the nearest hundred is 900.

First, calculate the sum:
495 + 389 = 884.

Now, rounding 884 to the nearest hundred gives 900 (because the tens digit is 8, which rounds the number up to the next hundred).
Statement-I is true.

Statement-II: The square of 12 is 144.

The square of 12 is:
12 × 12 = 144.
Statement-II is true.

Thus, both statements are true, so the correct option is C: Both Statement-I and Statement-II are true.

HOTs for Maths Olympiad - 4 - Question 10

A farmer sold 1240 kg of wheat and 768 kg of rice. How much total weight did he sell?

Detailed Solution for HOTs for Maths Olympiad - 4 - Question 10

Weight of wheat = 1240 kg

Weight of rice = 768 kg

Total weight = 1240 kg + 768 kg = 2008 kg

Thus, the total weight the farmer sold is 2008 kg.

So, the correct answer is A: 2008 kg.

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