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Class 5 Exam  >  Class 5 Tests  >  Math Olympiad for Class 5  >  HOTs for Maths Olympiad - 4 - Class 5 MCQ

HOTs for Maths Olympiad - 4 - Class 5 MCQ


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10 Questions MCQ Test Math Olympiad for Class 5 - HOTs for Maths Olympiad - 4

HOTs for Maths Olympiad - 4 for Class 5 2024 is part of Math Olympiad for Class 5 preparation. The HOTs for Maths Olympiad - 4 questions and answers have been prepared according to the Class 5 exam syllabus.The HOTs for Maths Olympiad - 4 MCQs are made for Class 5 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for HOTs for Maths Olympiad - 4 below.
Solutions of HOTs for Maths Olympiad - 4 questions in English are available as part of our Math Olympiad for Class 5 for Class 5 & HOTs for Maths Olympiad - 4 solutions in Hindi for Math Olympiad for Class 5 course. Download more important topics, notes, lectures and mock test series for Class 5 Exam by signing up for free. Attempt HOTs for Maths Olympiad - 4 | 10 questions in 10 minutes | Mock test for Class 5 preparation | Free important questions MCQ to study Math Olympiad for Class 5 for Class 5 Exam | Download free PDF with solutions
HOTs for Maths Olympiad - 4 - Question 1
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Read the given statements carefully and select the correct option.
Statement-I: The value of 482.65+317.85 when rounded to the nearest tenths is 800.5.
Statement-II: The product of 56×23 is greater than 1300.

Detailed Solution for HOTs for Maths Olympiad - 4 - Question 1
For Statement-I, the sum of 482.65 + 317.85 = 800.50, which when rounded to the nearest tenths gives 800.5. So, Statement-I is true.
For Statement-II, 56 × 23 = 1288, which is less than 1300, so Statement-II is false.
HOTs for Maths Olympiad - 4 - Question 2
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Fill in the blanks and select the correct option.
(i) The greatest common divisor (GCD) of 54 and 90 is P.
(ii) The sum of 789 and 1234 when rounded to the nearest hundred is Q.
(iii) The product of 25 × 12 is R.

Detailed Solution for HOTs for Maths Olympiad - 4 - Question 2

P is the GCD of 54 and 90, which is 18.The sum of 789 + 1234=2023, and when rounded to the nearest hundred, it becomes 2020.
The product of 25 × 12 = 300.

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HOTs for Maths Olympiad - 4 - Question 3
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A shopkeeper sold goods worth ₹458000 in a month. If his expenses were ₹389560, how much profit did he make?

Detailed Solution for HOTs for Maths Olympiad - 4 - Question 3
Profit is calculated by subtracting the expenses from the total sales.
458000 − 389560 = 68440.
So, the profit made by the shopkeeper is ₹68440.
HOTs for Maths Olympiad - 4 - Question 4
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Read the given statements carefully and select the correct option.
Statement-I: The sum of the first five prime numbers is 28.
Statement-II: The difference between 729 and 245 is less than 490.
Detailed Solution for HOTs for Maths Olympiad - 4 - Question 4

The first five prime numbers are 2,3,5,7,11 and their sum is 28, so Statement-I is true.
The difference between 729 and 245 is 484, which is less than 490, so Statement-II is true.

HOTs for Maths Olympiad - 4 - Question 5
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Nina made a chart showing the distance she traveled each day. Based on the given information, select the incorrect option.
Detailed Solution for HOTs for Maths Olympiad - 4 - Question 5

The correct answer is option B: Nina traveled 7 km 250 m less on Thursday than on Tuesday.

HOTs for Maths Olympiad - 4 - Question 6
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Read the given statements carefully and select the correct option.
Statement-I: The value of 345.78 + 654.22 when rounded to the nearest whole number is 1000.
Statement-II: The difference between 987 and 512 is greater than 470.
Detailed Solution for HOTs for Maths Olympiad - 4 - Question 6
The sum of 345.78 + 654.22 = 1000, which rounds to 1000, so Statement-I is true.
The difference between 987 − 512 = 475, which is greater than 470, so Statement-II is also true.
HOTs for Maths Olympiad - 4 - Question 7
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Fill in the blanks and select the correct option.
(i) The value of 874−349 when rounded to the nearest ten is ___ P.
(ii) The product of 23×45 is ___Q.
(iii) The LCM of 12 and 18 is ___R.
Detailed Solution for HOTs for Maths Olympiad - 4 - Question 7

874 − 349 = 525, and when rounded to the nearest ten, it becomes 530.
The product of 23 × 45 = 1035.
The LCM of 12 and 18 is 36.

HOTs for Maths Olympiad - 4 - Question 8
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A library had 7680 books. If 543 books were damaged, how many books are left?
Detailed Solution for HOTs for Maths Olympiad - 4 - Question 8
The number of books left is calculated by subtracting the damaged books from the total number of books.
7680 − 543 = 7137.
So, the library has 7137 books left.
HOTs for Maths Olympiad - 4 - Question 9
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Read the given statements carefully and select the correct option.
Statement-I: The estimated value of 495 + 389 to the nearest hundred is 900.
Statement-II: The square of 12 is 144.
Detailed Solution for HOTs for Maths Olympiad - 4 - Question 9
The sum of 495 + 389 = 884, which rounds to 900 when rounded to the nearest hundred, so Statement-I is true.
The square of 12 = 144, so Statement-II is also true.
HOTs for Maths Olympiad - 4 - Question 10
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A farmer sold 1240 kg of wheat and 768 kg of rice. How much total weight did he sell?
Detailed Solution for HOTs for Maths Olympiad - 4 - Question 10
The total weight sold by the farmer is 1240 kg + 768 kg, which equals 2008 kg.
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