Class 5 Exam  >  Class 5 Tests  >  Math Olympiad for Class 5  >  Olympiad Test: Area, Perimeter And Volume - Class 5 MCQ

Olympiad Test: Area, Perimeter And Volume - Class 5 MCQ


Test Description

20 Questions MCQ Test Math Olympiad for Class 5 - Olympiad Test: Area, Perimeter And Volume

Olympiad Test: Area, Perimeter And Volume for Class 5 2025 is part of Math Olympiad for Class 5 preparation. The Olympiad Test: Area, Perimeter And Volume questions and answers have been prepared according to the Class 5 exam syllabus.The Olympiad Test: Area, Perimeter And Volume MCQs are made for Class 5 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Olympiad Test: Area, Perimeter And Volume below.
Solutions of Olympiad Test: Area, Perimeter And Volume questions in English are available as part of our Math Olympiad for Class 5 for Class 5 & Olympiad Test: Area, Perimeter And Volume solutions in Hindi for Math Olympiad for Class 5 course. Download more important topics, notes, lectures and mock test series for Class 5 Exam by signing up for free. Attempt Olympiad Test: Area, Perimeter And Volume | 20 questions in 40 minutes | Mock test for Class 5 preparation | Free important questions MCQ to study Math Olympiad for Class 5 for Class 5 Exam | Download free PDF with solutions
Olympiad Test: Area, Perimeter And Volume - Question 1

Find the area of the triangle shown.

Detailed Solution for Olympiad Test: Area, Perimeter And Volume - Question 1

Area of triangle = 1/2 (b*h)

= 1/2 (13*5)

= 65/2

= 32.5 cm2

Olympiad Test: Area, Perimeter And Volume - Question 2

Find the perimeter of the triangle shown in the previous question.

Detailed Solution for Olympiad Test: Area, Perimeter And Volume - Question 2

The perimeter of a triangle is calculated by adding up all its side lengths. Given the sides are:

  • 7 metres
  • 11 metres
  • 13 metres

We can calculate the perimeter as follows:

  • 7 + 11 = 18
  • 18 + 13 = 31

Therefore, the perimeter is 31 metres.

Olympiad Test: Area, Perimeter And Volume - Question 3

Find the area of the parallelogram shown.

Detailed Solution for Olympiad Test: Area, Perimeter And Volume - Question 3

area of parallelogram = base x height = 10 x 20 = 200 cm2

Olympiad Test: Area, Perimeter And Volume - Question 4

Find the perimeter of the parallelogram shown in the previous question.

Detailed Solution for Olympiad Test: Area, Perimeter And Volume - Question 4

The perimeter of a parallelogram is calculated by adding all its sides. Given two pairs of equal sides:

  • First pair: 14 m
  • Second pair: 20 m

The calculation for the perimeter is as follows:

  • 14 m + 20 m + 14 m + 20 m = 68 m

Thus, the perimeter of the parallelogram is 68 metres.

Olympiad Test: Area, Perimeter And Volume - Question 5

Find the area of the trapezoid shown.

Detailed Solution for Olympiad Test: Area, Perimeter And Volume - Question 5

To find the area of a trapezoid, use the formula:

  • Area = (Base1 + Base2) / 2 × Height

Steps to calculate:

  • Identify the two parallel bases. Let's call them Base1 and Base2.
  • Find the height (distance between the bases).
  • Plug the values into the formula.

In this question:

  • Base1 = 18 cm and Base2 = 14 cm.
  • If the height is 8 cm, the calculation would be:
  • (18 + 14) / 2 × 8 = 32 / 2 × 8 = 16 × 8 = 128 cm2

Therefore, correct answer- 128  cm2

Olympiad Test: Area, Perimeter And Volume - Question 6

Find the perimeter of the trapezoid shown in the previous question.

Detailed Solution for Olympiad Test: Area, Perimeter And Volume - Question 6

The perimeter of the trapezoid can be calculated by summing the lengths of all its sides. Here’s how it breaks down:

  • Length of side 1: 18 cm
  • Length of side 2: 10 cm
  • Length of side 3: 14 cm
  • Length of side 4: 9 cm

To find the total perimeter:

Perimeter of the trapezoid = sum of all sides = 18 cm + 10 cm + 14 cm + 9 cm

This gives:

Perimeter = 51 cm

Olympiad Test: Area, Perimeter And Volume - Question 7

Find the area of the circle shown.(approx. value)

Detailed Solution for Olympiad Test: Area, Perimeter And Volume - Question 7

To find the area of the circle:

  • Use the formula for the area of a circle: Area = πr²
  • Given the radius (r) is 4 m, substitute the value into the formula:
  • Area = π(4)²
  • Calculate: Area = 16π
  • Using π ≈ 3.14, compute the area:
  • Area ≈ 16 × 3.14 = 50.24 m²
Olympiad Test: Area, Perimeter And Volume - Question 8

Find the perimeter of the circle (approx value).

A circle is inscribed in a square as shown. If the radius of the circle is  4cm, then the perimeter of the square is\n \n \n \n \n A. 28 cm B.

Detailed Solution for Olympiad Test: Area, Perimeter And Volume - Question 8

To find the perimeter of the circle:

  • The formula for the perimeter (circumference) of a circle is 2πr.
  • Given the radius r is 4 cm, we can substitute this value into the formula.
  • Calculating the perimeter:
    • 2π × 4 = 8π
    • Using the approximate value of π (3.14):
    • 8 × 3.14 = 25.12 cm
Olympiad Test: Area, Perimeter And Volume - Question 9

Find the area of the figure shown.

Detailed Solution for Olympiad Test: Area, Perimeter And Volume - Question 9

Olympiad Test: Area, Perimeter And Volume - Question 10

Find the perimeter of the figure shown in the below

Detailed Solution for Olympiad Test: Area, Perimeter And Volume - Question 10

To find the perimeter of the figure, follow these steps:

  • Identify all the sides of the shape.
  • Add up the lengths of all sides to get the total perimeter.
  • Ensure all measurements are in the same unit, typically centimetres.

    Therefore, 5+6+5+8+6+8+(2π r /4) (where r = 6cm)
    = 5+6+5+8+6+8+9.42
    = 47.42cm

In this case, the calculated perimeter is 47.42 cm.

Olympiad Test: Area, Perimeter And Volume - Question 11

A square has an area of 64 cm2. What is the length of each side?

Detailed Solution for Olympiad Test: Area, Perimeter And Volume - Question 11

To find the length of each side of a square with an area of 64 cm2:

  • The formula for the area of a square is: Area = side × side.
  • Given that the area is 64 cm2, we can write: side × side = 64.
  • To find the length of one side, take the square root of the area: side = √64.
  • Calculating this gives: side = 8 cm.
Olympiad Test: Area, Perimeter And Volume - Question 12

The figure below is made up of 3 squares of sides 5 cm. What is the perimeter of the figure?

Detailed Solution for Olympiad Test: Area, Perimeter And Volume - Question 12

To find the perimeter of the figure made up of three squares, follow these steps:

  • Each square has a side length of 5 cm.
  • The area covered by the squares can affect how we calculate the perimeter.
  • To determine the perimeter, we need to account for the external sides of the figure, not the internal connections.
  • Considering the arrangement of the squares, the total external sides can be calculated as follows:
    • Each square contributes some sides to the perimeter while others are internal.
    • Count the external sides: for three squares arranged in a certain manner, typically one would find that the total length sums up to 30 cm.

The perimeter of the figure is therefore 30 cm.

Olympiad Test: Area, Perimeter And Volume - Question 13

The figure below is made up of three squares. Find the perimeter of the figure.

Detailed Solution for Olympiad Test: Area, Perimeter And Volume - Question 13

To find the perimeter of the figure made up of three squares:

  • Each square has a side length of 6 cm.
  • There are a total of 8 boundary lines contributing to the perimeter.
  • To calculate the perimeter, multiply the number of boundary lines by the side length:
  • 8 lines × 6 cm = 48 cm.
Olympiad Test: Area, Perimeter And Volume - Question 14

The area of the figure above is _____ 
m2.

Detailed Solution for Olympiad Test: Area, Perimeter And Volume - Question 14

first break it into a rectangle and square


rectangle of LxB=9x7
square of side=5
so area of rectangle = 9x7 =63
area of square = 5x5 = 25
so total  area = 63 +25
                      = 88

Olympiad Test: Area, Perimeter And Volume - Question 15

The perimeter of a square is 20 cm. What is the length of each side of the square?

Detailed Solution for Olympiad Test: Area, Perimeter And Volume - Question 15

To find the length of each side of the square:

  • The perimeter of a square is calculated using the formula: Perimeter = 4 × side length.
  • Given that the perimeter is 20 cm, set up the equation:
  • 4 × side length = 20 cm
  • To find the side length, divide both sides by 4:
  • side length = 20 cm / 4
  • Thus, the length of each side is 5 cm.
Olympiad Test: Area, Perimeter And Volume - Question 16

Which of the following figures have the same shaded area?

Detailed Solution for Olympiad Test: Area, Perimeter And Volume - Question 16

Figures R and each have 7 black squares, so they have the same area.

Olympiad Test: Area, Perimeter And Volume - Question 17

Which one of the following rectangles had the biggest perimeter?

Detailed Solution for Olympiad Test: Area, Perimeter And Volume - Question 17

A) Area = 96m2

Breadth = 8m

Area = l*b

96 = l*8

l =12

Perimeter = 2(l+b)

= 2(12+8) = 40

 

B) Area = 110m2

Breadth = 10cm = 0.1m

Area = l*b

110 = l*0.1

l =1100

Perimeter = 2(l+b)

= 2(1100+0.1) = 2200.2

 

C) Area = 90m2

Length = 15cm = 0.15m

Area = l*b

90 = 0.15*b

b = 600m

Perimeter = 2(l+b)

= 2(0.15+600) = 1200.3

 

D) Area = 100m2

Length = 25cm = 0.25m

Area = l*b

100 = 0.25*b

b = 400m

Perimeter = 2(l+b)

= 2(0.25+400) = 800.5

Olympiad Test: Area, Perimeter And Volume - Question 18

The perimeter of the figure shown below is 36 m. What is the length of DE?

Detailed Solution for Olympiad Test: Area, Perimeter And Volume - Question 18

The perimeter of the figure is 36 m. To find the length of DE, follow these steps:

  • Identify all known side lengths of the figure.
  • Add the lengths of the known sides.
  • Subtract this sum from the total perimeter (36 m) to find the length of DE.

For example, if the total length of the other sides is 29 m, then:

  • Length of DE = 36 m - 29 m = 7 m

Thus, the length of DE is 7 metres.

Olympiad Test: Area, Perimeter And Volume - Question 19

Calculate the area of rectangle if one square represents an area of 1 cm.

Detailed Solution for Olympiad Test: Area, Perimeter And Volume - Question 19

There are 6×4=24 squares and each square has an area of = 1cm2. So, the area of rectangle = 6×4×1=24cm2.

Olympiad Test: Area, Perimeter And Volume - Question 20

A rectangular garden measures 25 m by 20 m. What is the cost of erecting a wooden fence around it if every 5 metres of wooden fencing cost $ 27?

Detailed Solution for Olympiad Test: Area, Perimeter And Volume - Question 20

Let's take perimeter of recatngular garden=
2(20m+25m)= 90m

Cost of fencing every 5 m= Rs 27
Cost of fencing 90 m= $ 27/5 ×90
= $ 27× 18= $ 486

37 videos|81 docs|57 tests
Information about Olympiad Test: Area, Perimeter And Volume Page
In this test you can find the Exam questions for Olympiad Test: Area, Perimeter And Volume solved & explained in the simplest way possible. Besides giving Questions and answers for Olympiad Test: Area, Perimeter And Volume, EduRev gives you an ample number of Online tests for practice
37 videos|81 docs|57 tests
Download as PDF