In the figure given, the potential difference (in Volts) between A and B in steady state will be
The correct answer is: 25
Three capacitors are connected as shown in figure. Then the charge (in µC) on capacitor plate C1 is :
let q1 be the charge on C1
The correct answer is: 6
A capacitor of capacitance 10µF is charged to a potential of 100V. Now connecting it in parallel with an uncharged capacitor, the resultant potential difference becomes 40volt. The capacitance of this capacitor (in µF) is.
The correct answer is: 15
A 4µF capacitor is charged to 400volts and then its plates are joined through a resistor of resistance 1kΩ. The heat (in Joules) produced in the resistor is
Heat produced in the resistor = energy stored in capacitor
The correct answer is: 0.32
The equivalent capacitance (in µF) in the circuit shown in figure will be.
The correct answer is: 8
Two capacitors of 2µF and 3µF are connected in series. The potential at point A is 1000Volt and the outer plate of 3µF capacitor is earthed. The potential at point B is (in Volts).
The correct answer is: 400
The equivalent capacitance (in µF) of the circuit shown, between points A and B will be.
The correct answer is: 2.667
What percentage of the energy drawn from the charging battery is stored in a capacitor.
Energy drawn from the charge battery = QE
Energy stored in capacitor
So % of energy stored
The correct answer is: 50
In the circuit shown in the figure, each capacitor has a capacity of 3µF. The equivalent capacity (in µF) between A and B is.
The correct answer is: 5
For the circuit shown in the diagram find the value of Va – Vb (in Volts) after long time closing the switch S1.
The correct answer is: 4