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This mock test of Newton's Law Of Motion – MSQ for Physics helps you for every Physics entrance exam.
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*Multiple options can be correct

QUESTION: 1

A painter is applying force himself to raise him and the box with an acceleration of 5 *m*/*s*^{2} by a massless rope and pulley arrangement as shown in figure. Mass of painter is 100*kg* and that of box is 50*kg*. If * g* = 10

Select one or more:

Solution:

For painter :

.....(1)

For the system;

..(2)

where; *m* = 100 *kg
*

and

The correct answers are: tension in the rope is 1125

*Multiple options can be correct

QUESTION: 2

Two blocks *A* and *B* of equal masses **m***kg* each are connected by a light thread, which passes over a massless pulley as shown in the figure. Both the blocks lies on wedge of mass **m***kg*. Assume friction to be absent everywhere and both the blocks to be always in contact with the wedge. The wedge lying over smooth horizontal surface is pulled towards right with constant acceleration * a* (

(* g* is acceleration due to gravity)

Select one or more:

Solution:

The *FBD* of *A* and *B* are

Applying Newton's second law to block *A* and *B* along normal to inclined surface

Solving

For *N _{A}* to be non zero

or

The correct answers are: Normal reaction on

*Multiple options can be correct

QUESTION: 3

A light inextensible string connects a block of mass *m* and top of wedge of mass *M*. The string is parallel to inclined surface and the inclined surface makes and angle θ with horizontal as show in the figure. All surfaces are smooth. Now a constant horizontal force of minimum magnitude F is applied to wedge towards right such that the normal reaction on block exerted by wedge just becomes zero.

Select one or more:

Solution:

If a is acceleration of wedge, from

*Multiple options can be correct

QUESTION: 4

Two smooth blocks are placed at a smooth corner as shown in the figure. Both the blocks are having mass * m*. We apply a force

Select one or more:

Solution:

For equilibrium of block (*A*)

To lift block *B* from ground

To keep regular contact

The correct answer is: a_{B} = 3a/4

*Multiple options can be correct

QUESTION: 5

Two blocks of mass * M* and

Select one or more:

Solution:

Let *F* be the force exerted by mass *m* on mass *M*.

*FBD* of mass *M*

*F = k*_{1}*x*_{1}* = *2 × 3 = 6**N**

FBD of mass *m*

k_{2}x_{2} = F = 6N to the left

Hence the force exerted on block of mass *m* be the right spring (*k*_{2}*x*_{2}) is 6 *N* to the left. From *FBD*, the normal reaction (*F*) between blocks is 6 *N*.

As system is at rest, net force on block of mass *m* is zero.

The correct answers are: The force exerted on block of mass * m* by the right spring is 6

*Multiple options can be correct

QUESTION: 6

Two blocks *A* and *B* of equal mass * m* are connected through a massless string and arrangement as shown in the figure. The wedge is fixed on horizontal surface. Friction is absent everywhere. When the system is released from rest.

Select one or more:

Solution:

Let *a* be acceleration of system and *T* be tension in, the string.

F.B.D. of block *A
*

F.B.D. of block

Adding equation (1) and (2) we get

from equation (1) ;

T = mg/4

The correct answers are: tension in string is **mg**/**4**, acceleration of *A* is **3 g**/

*Multiple options can be correct

QUESTION: 7

Figure shows two block *A* and *B* connected to an ideal pulley string system. In this system when bodies are released then : (neglect friction and take * g* = 10

Select one or more:

Solution:

Applying *NLM* on 40*kg* block

For 10*kg* block *T* = 10 × 4*a*

Solving a = 2m/s^{2}

*T* = 80 *N*

The correct answers are: Acceleration of block *A* is 2 *m*/*s*^{2}, Tension in string connected to block *B* is 80 *N*

*Multiple options can be correct

QUESTION: 8

In the figure shown all the surfaces are smooth. All the blocks *A*, *B* and *C* are movable, *x*-axis is horizontal and *y*-axis is vertical as shown. Just after the system is released from the position as shown.

Select one or more:

Solution:

There is no horizontal force on block *A*, therefore it does not move in *x*-direction, whereas there is net downwards force (*mg* – *N*) is acting on it, making its acceleration along negative *y*-direction.

Block *B* moves downwards as well as in negative *x*-direction. Downward acceleration of *A* and *B* will be equal due to constrain, thus w.r.t. *B*, *A* moves in positive *x*-direction.

Due to the component of normal exerted by *C* on *B*, it moves in negative *x*-direction.

The force acting vertically downwards on block *B* are mg and *N _{A}* (normal reaction due to block

The correct answers are: Acceleration of ‘*A*’ relative to ground is in negative *y*-direction, Acceleration of ‘*A*’ relative to *B* is in positive x-direction, The horizontal acceleration of ‘*B*’ relative to ground is in negative *x*-direction., The acceleration of ‘*B*’ relative to ground directed along the inclined surface of ‘*C*’ is greater than *g*sin*θ*

*Multiple options can be correct

QUESTION: 9

A block of mass * m* is placed on a wedge. The wedge can be accelerated in four manners marked as (1), (2), (3) and (4) as shown. If the normal reactions in situation (1), (2), (3) and (4) are

Select one or more:

Solution:

1.

Balancing forces perpendicular to incline

2.

Similarly for this case get

3.

Similarly for this case get

4.

Similarly for this case get,

The correct answers are: N_{3} > N_{1} > N_{2} > N_{4} , b_{2} > b_{3} > b_{4} > b_{1}

*Multiple options can be correct

QUESTION: 10

A cylinder of mass * M* and radius

Select one or more:

Solution:

The correct answers are:

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