The equation of the plane passing through the point (3, – 3, 1) and perpendicular to the line joining the points (3, 4, – 1) and (2, – 1, 5) is:
The equation of the plane, which is at a distance of 5 unit from the origin and has as a normal vector, is:
1 Crore+ students have signed up on EduRev. Have you? Download the App 
The length of the perpendicular from the origin to the plane 3x + 2y – 6z = 21 is:
If l, m, n are the direction cosines of the normal to the plane and p be the perpendicular distance of the plane from the origin, then the equation of the plane is:
If is the normal from the origin to the plane, and is the unit vector along . P(x, y, z) be any point on the plane and is perpendicular to . Then
The length of the perpendicular from the origin to the plane 2x – 3y + 6z = 21 is:
The angle between two lines whose direction ratios are 1,2,1 and 2,3,4 is:
The equation of the plane passing through the points (2, 1, 0), (3, – 2, – 2) and (3, 1, 7) is:
209 videos443 docs143 tests

209 videos443 docs143 tests
