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Test: Linear Programming (CBSE Level) - 1 - JEE MCQ


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25 Questions MCQ Test Mathematics (Maths) Class 12 - Test: Linear Programming (CBSE Level) - 1

Test: Linear Programming (CBSE Level) - 1 for JEE 2024 is part of Mathematics (Maths) Class 12 preparation. The Test: Linear Programming (CBSE Level) - 1 questions and answers have been prepared according to the JEE exam syllabus.The Test: Linear Programming (CBSE Level) - 1 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Linear Programming (CBSE Level) - 1 below.
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Test: Linear Programming (CBSE Level) - 1 - Question 1

In a LPP, the objective function is always

Detailed Solution for Test: Linear Programming (CBSE Level) - 1 - Question 1

In a LPP, the objective function is always linear.

Test: Linear Programming (CBSE Level) - 1 - Question 2

Maximize Z = – x + 2y, subject to the constraints: x ≥ 3, x + y ≥ 5, x + 2y ≥ 6, y ≥ 0.

Detailed Solution for Test: Linear Programming (CBSE Level) - 1 - Question 2

Objective function is Z = - x + 2 y ……………………(1).
The given constraints are : x ≥ 3, x + y ≥ 5, x + 2y ≥ 6, y ≥ 0.

Corner points Z =  - x + 2y

Here , the open half plane has points in common with the feasible region .
Therefore , Z has no maximum value.

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Test: Linear Programming (CBSE Level) - 1 - Question 3

Two godowns A and B have grain capacity of 100 quintals and 50 quintals respectively. They supply to 3 ration shops, D, E and F whose requirements are 60, 50 and 40 quintals respectively. The cost of transportation per quintal from the godowns to the shops are given in the following table:


How should the supplies be transported in order that the transportation cost is minimum? What is the minimum cost?

Detailed Solution for Test: Linear Programming (CBSE Level) - 1 - Question 3

Let the number of units of grain transported from godown A to D = x And the number of units of grain transported from godown A to E = y Therefore , the number of units of grain transported from godown A to F = 100 – (x+y) Therefore , the number of units of grain transported from godown B to D = 60 – x The number of units of grain transported from godown B to E = 50 – y The number of units of grain transported from godown B to F = x + y – 60 . Here , the objective function is :Minimise Z = 2.5x + 1.5y + 410 . , subject to constraints : 60 - x ≥ 0,50 - y ≥ 0 ,100 – (x + y) ≥ 0 , (x + y) - 60 ≥ 0 , x,y ≥ 0.

Here Z = 510 is minimum.i.e. From A : 10,50, 40 units; From B: 50,0,0 units to D, E and F respectively and minimum cost = Rs 510 .

Test: Linear Programming (CBSE Level) - 1 - Question 4

Corner points of the feasible region for an LPP are (0, 2), (3, 0), (6, 0), (6, 8) and (0, 5). Let F = 4x + 6y be the objective function. Maximum of F – Minimum of F =

Detailed Solution for Test: Linear Programming (CBSE Level) - 1 - Question 4

Here the objective function is given by : F = 4x +6y .

Maximum of F – Minimum of F = 72 – 12 = 30 .

Test: Linear Programming (CBSE Level) - 1 - Question 5

A linear programming problem is one that is concerned with

Detailed Solution for Test: Linear Programming (CBSE Level) - 1 - Question 5

A linear programming problem is one that is concerned with finding the optimal value (maximum or minimum) of a linear function of several variables .

Test: Linear Programming (CBSE Level) - 1 - Question 6

Which of the following types of problems cannot be solved by linear programming methods

Detailed Solution for Test: Linear Programming (CBSE Level) - 1 - Question 6

Traffic signal control types of problems cannot be solved by linear programming methods .

Test: Linear Programming (CBSE Level) - 1 - Question 7

The optimal value of the objective function Z = ax + by may or may not exist, if the feasible region for a LPP is

Detailed Solution for Test: Linear Programming (CBSE Level) - 1 - Question 7

The optimal value of the objective function Z = ax + by may or may not exist, if the feasible region for a LPP is unbounded.

Test: Linear Programming (CBSE Level) - 1 - Question 8

One kind of cake requires 200g of flour and 25g of fat, and another kind of cake requires 100g of flour and 50g of fat. Find the maximum number of cakes which can be made from 5kg of flour and 1 kg of fat assuming that there is no shortage of the other ingredients used in making the cakes.

Detailed Solution for Test: Linear Programming (CBSE Level) - 1 - Question 8

Let number of cakes of first type = x 
And number of cakes of second type = y 
Therefore , the above L.P.P. is given as :
Minimise , Z = x +y , subject to the constraints : 200x +100y ≤ 5000 and. 25x +50y ≤ 1000, i.e. 2x + y ≤ 50 and x +2y ≤ 40 x, y ≥ 0.

i.e Maximum number of cakes = 30 , 20 of kind one and 10 cakes of another kind .

Test: Linear Programming (CBSE Level) - 1 - Question 9

An oil company has two depots A and B with capacities of 7000 L and 4000 L respectively. The company is to supply oil to three petrol pumps, D, E and F whose requirements are 4500L, 3000L and 3500L respectively. The distances (in km) between the depots and the petrol pumps is given in the following table:

Assuming that the transportation cost of 10 litres of oil is Re 1 per km, how should the delivery be scheduled in order that the transportation cost is minimum?What is the minimum cost?

Detailed Solution for Test: Linear Programming (CBSE Level) - 1 - Question 9

Here objective function is : Z = 3x + y + 39500 , subject to constraints : : x + y ≤ 7000, x ≤ 4500, x + y ≥ 3500, , y ≤ 3000x , x,y ≥ 0

Here Z = 4400 is minimum.i.e. . From A: 500, 3000 and 3500 litres; From B: 4000, 0, 0 litres to D, E and F respectively; Minimum cost = Rs 4400 .

Test: Linear Programming (CBSE Level) - 1 - Question 10

Corner points of the feasible region determined by the system of linear constraints are (0, 3), (1, 1) and (3, 0). Let Z = px+qy, where p, q > 0. Condition on p and q so that the minimum of Z occurs at (3, 0) and (1, 1) is

Detailed Solution for Test: Linear Programming (CBSE Level) - 1 - Question 10

We have Z = px + qy , At (3, 0) Z = 3p ……………………………….(1) At (1 , 1) Z = p + q …………………………(2) Therefore , from (1) and (2) : We have : p = q/2 .

Test: Linear Programming (CBSE Level) - 1 - Question 11

In linear programming feasible region (or solution region) for the problem is

Detailed Solution for Test: Linear Programming (CBSE Level) - 1 - Question 11

In linear programming feasible region (or solution region) for the problem is given by The common region determined by all the constraints including the non – negative constraints x ⩾0, y ⩾ 0

Test: Linear Programming (CBSE Level) - 1 - Question 12

In a LPP if the objective function Z = ax + by has the same maximum value on two corner points of the feasible region, then every point on the line segment joining these two points give the same

Detailed Solution for Test: Linear Programming (CBSE Level) - 1 - Question 12

In a LPP if the objective function Z = ax + by has the same maximum value on two corner points of the feasible region, then every point on the line segment joining these two points give the same maximum value .

Test: Linear Programming (CBSE Level) - 1 - Question 13

A factory makes tennis rackets and cricket bats. A tennis racket takes 1.5 hours of machine time and 3 hours of craftman’s time in its making while a cricket bat takes 3 hour of machine time and 1 hour of craftman’s time. In a day, the factory has the availability of not more than 42 hours of machine time and 24 hours of craftsman’s time. What number of rackets and bats must be made if the factory is to work at full capacity?

Detailed Solution for Test: Linear Programming (CBSE Level) - 1 - Question 13

Let number of rackets made = x 
And number of bats made = y 
Therefore , the above L.P.P. is given as : 
Maximise , Z = x +y , subject to the constraints : 1.5x +3y ≤ 42 and. 3x +y ≤ 24, i.e.0.5x + y ≤ 14 i.e. x +2y ≤ 28 and 3x +y ≤ 24 , x, y ≥ 0.

Here Z = 16 is maximum. i.e Maximum number of rackets = 4 and number of bats = 12.

Test: Linear Programming (CBSE Level) - 1 - Question 14

A fruit grower can use two types of fertilizer in his garden, brand P and brand Q. The amounts (in kg) of nitrogen, phosphoric acid, potash, and chlorine in a bag of each brand are given in the table. Tests indicate that the garden needs at least 240 kg of phosphoric acid, at least 270 kg of potash and at most 310 kg of chlorine.If the grower wants to minimise the amount of nitrogen added to the garden, how many bags of each brand should be used? What is the minimum amount of nitrogen added in the garden? should the delivery be scheduled in order that the transportation cost is minimum? 

Detailed Solution for Test: Linear Programming (CBSE Level) - 1 - Question 14

Let the number of bags used for fertilizer of brand P = x And the number of bags used for fertilizer of brand Q = y . Here , Z = 3x + 3.5y subject to constraints : :1.5 x +2 y ≤ 310, x + 2y ≥ 240, 3x + 1.5y ≥ 270 , x,y ≥ 0

Here Z = 470 is minimum i.e. 40 bags of brand P and 100 bags of brand Q; Minimum amount of nitrogen = 470 kg.

Test: Linear Programming (CBSE Level) - 1 - Question 15

In a LPP, the linear inequalities or restrictions on the variables are called

Detailed Solution for Test: Linear Programming (CBSE Level) - 1 - Question 15

In a LPP, the linear inequalities or restrictions on the variables are called Linear constraints

Test: Linear Programming (CBSE Level) - 1 - Question 16

In linear programming infeasible solutions

Detailed Solution for Test: Linear Programming (CBSE Level) - 1 - Question 16

In linear programming infeasible solutions fall outside the feasible region .

Test: Linear Programming (CBSE Level) - 1 - Question 17

In linear programming problems the function whose maxima or minima are to be found is called

Detailed Solution for Test: Linear Programming (CBSE Level) - 1 - Question 17

In linear programming problems the function whose maxima or minima are to be found is called Objective function .

Test: Linear Programming (CBSE Level) - 1 - Question 18

A factory makes tennis rackets and cricket bats. A tennis racket takes 1.5 hours of machine time and 3 hours of craftman’s time in its making while a cricket bat takes 3 hour of machine time and 1 hour of craftman’s time. In a day, the factory has the availability of not more than 42 hours of machine time and 24 hours of craftsman’s time. If the profit on a racket and on a bat is Rs 20 and Rs 10 respectively, find the maximum profit of the factory when it works at full capacity?

Detailed Solution for Test: Linear Programming (CBSE Level) - 1 - Question 18

Let number of rackets made = x 
And number of bats made = y 
Therefore , the above L.P.P. is given as : 
Maximise , Z = x +y , subject to the constraints : 1.5x +3y ≤ 42 and. 3x +y ≤ 24, i.e.0.5x + y ≤ 14 i.e. x +2y ≤ 28 and 3x +y ≤ 24 , x, y ≥ 0.

Here Z = 16 is maximum. i.e Maximum number of rackets = 4 and number of bats = 12.
Here , profit function is P = 20x + 10y 
Profit is maximum at x = 4 and y = 12 . 
Therefore , maximum profit = 20(4) + 10 ( 12) = 200.i.e. Rs.200.

Test: Linear Programming (CBSE Level) - 1 - Question 19

A fruit grower can use two types of fertilizer in his garden, brand P and brand Q. The amounts (in kg) of nitrogen, phosphoric acid, potash, and chlorine in a bag of each brand are given in the table. Tests indicate that the garden needs at least 240 kg of phosphoric acid, at least 270 kg of potash and at most 310 kg of chlorine.

If the grower wants to maximise the amount of nitrogen added to the garden, how many bags of each brand should be added? What isthe maximum amount of nitrogen added?

Detailed Solution for Test: Linear Programming (CBSE Level) - 1 - Question 19

Let the number of bags used for fertilizer of brand P = x And the number of bags used for fertilizer of brand Q = y . Here , Z = 3x + 3.5y subject to constraints : :1.5 x +2 y ≤ 310, x + 2y ≥ 240, 3x + 1.5y ≥ 270 , x,y ≥ 0

Here Z = 595 is maximum i.e. 140 bags of brand P and 50 bags of brand Q; Maximum amount of nitrogen = 595 kg .

Test: Linear Programming (CBSE Level) - 1 - Question 20

Determine the maximum value of Z = 3x + 4y if the feasible region (shaded) for a LPP is shown in Figure above. 

Detailed Solution for Test: Linear Programming (CBSE Level) - 1 - Question 20

Test: Linear Programming (CBSE Level) - 1 - Question 21

In linear programming, optimal solution

Detailed Solution for Test: Linear Programming (CBSE Level) - 1 - Question 21

In linear programming, optimal solution satisfies all the constraints as well as the objective function .

Test: Linear Programming (CBSE Level) - 1 - Question 22

In linear programming problems the optimum solution

Detailed Solution for Test: Linear Programming (CBSE Level) - 1 - Question 22

In linear programming problems the optimum solution satisfies a set of linear inequalities (called linear constraints) .

Test: Linear Programming (CBSE Level) - 1 - Question 23

A manufacturer produces nuts and bolts. It takes 1 hour of work on machine A and 3 hours on machine B to produce a package of nuts. It takes 3 hours on machine A and 1 hour on machine B to produce a package of bolts. He earns a profit of Rs17.50 per package on nuts and Rs 7.00 per package on bolts. How many packages of each should be produced each day so as to maximise his profit, if he operates his machines for at the most 12 hours a day?

Detailed Solution for Test: Linear Programming (CBSE Level) - 1 - Question 23

Let number of packages of nuts produced = x 
And number of packages of bolts produced = y 
Therefore , the above L.P.P. is given as : 
Maximise , Z = 17.50x +7y , subject to the constraints : x +3y ≤ 12 and. 3x +y ≤ 12, x, y ≥ 0.

i.e 3 packages of nuts and 3 packages of bolts;
Maximum profit = Rs 73.50.

Test: Linear Programming (CBSE Level) - 1 - Question 24

A toy company manufactures two types of dolls, A and B. Market tests and available resources have indicated that the combined production level should not exceed 1200 dolls per week and the demand for dolls of type B is at most half of that for dolls of type A. Further, the production level of dolls of type A can exceed three times the production of dolls of other type by at most 600 units. If the company makes profit of Rs 12 and Rs 16 per doll respectively on dolls A and B, how many of each should be produced weekly in order to maximise the profit?

Detailed Solution for Test: Linear Programming (CBSE Level) - 1 - Question 24

Here , Maximise Z = 12x + 16y , subject to constraints : : x + y ≤ 1200, x - 2y ≥ 0, x - 3y ≤ 600 , x,y ≥ 0

Here Z = 16000 is maximum.i.e. 800 dolls of type A and 400 dolls of type B; Maximum profit = Rs 16000 .

Test: Linear Programming (CBSE Level) - 1 - Question 25

Feasible region (shaded) for a LPP is shown in Figure. Maximize Z = 5x + 7y. 

Detailed Solution for Test: Linear Programming (CBSE Level) - 1 - Question 25

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