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QUESTION: 1

The product of two matrics

Solution:

{(1*0, 2*2, 0*x) (2*0, 0*2, 1*x) (1*0, 0*2, 2*x)}

= {4, x, 2x}

QUESTION: 2

If A, B are, respectively m × n, k × l matrices, then both AB and BA are defined if and only if

Solution:

If A, B are, respectively m × n, k × l matrices, then both AB and BA are defined if and only if n = k and l = m. In particular, if both A and B are square matrices of the same order, then both AB and BA are defined.

QUESTION: 3

and 2A + B + X = 0, then the matrix X = ……

Solution:

QUESTION: 4

If then -5A = ?

Solution:

QUESTION: 5

If and , then AXB=?

Solution:

A = [2, 3, 4]

Therefore AXB = {(2*1) + (3*(-1)) + (4*2)}

AXB = {2 + (-3) + 8}

AXB = 7

QUESTION: 6

If and , then = 2A - B?

Solution:

QUESTION: 7

If and , then AB = ?

Solution:

A.B = [(-1(-1) + 2(-2) + 3(-3) -1(-3) + 2(1) + 3(2)]

A.B = [1 - 4 - 9 3 + 2 + 6]

A.B = [-12 11]

QUESTION: 8

Solution:

P(n) : A^{n} = {(1+2n, -4n), (n,(1 - 2n))}

= P(k + 1) = {(1+2(k+1), -4(k+1)), (k+1, (1 - 2(k+1)}

= {(1+2k+2, -4k-4) (k+1, 1-2k-2)}

= {(2k+3, -4k-4), (k+1, -2k-1)}

QUESTION: 9

Value of determinant is computed by adding multiples of one row to

Solution:

Value of Determinant remains unchanged if we add equal multiples of all the elements of row (column) to corresponding elements of another row (column) If, we have a given matrix A.

QUESTION: 10

If and , then AB = ?

Solution:

A = {(2),(3)} B = {-1,2,-2}

AB = {(-2,4,-4) (-3,6,-6)}

QUESTION: 11

For a skew symmetric even ordered matrix A of integers, which of the following will not hold true:

Solution:

Determinant of a skew symmetric even ordered matrix A is a perfect square.

QUESTION: 12

If A is a matrix of order 1×3 and B is a matrix of order 3×4, then order of the matrix obtained on multiplying A and B is

Solution:

In matrix 1*3 is one row and 3 columns and in 3*4 is three rows and four column hence multiplied matrix will be 1*4.

QUESTION: 13

If and , then A-2B is equal to

Solution:

A={(-1,2) (3,-2) (-4,3)} B={(1,3) (3,-2) (6,2)}

2B = {(2,6) (6,-6) (12,4)}

A - 2B = {(-1,2) (3,-2) (-4,3)} - {(2,6) (6,-6) (12,4)}

= {(-1-2, 2-6) (3-6, -2+4) (-4-12, 3-4)}

= {(-3,-4) (-3,2) (-16, -1)}

QUESTION: 14

If and then AB = ?

Solution:

QUESTION: 15

If A and B are two matrices conformable to multiplication such that their product AB = O(Zero matrix). Then which of the following is true

Solution:

AB = 0 does not necessarily imply that either A or B is a null matrix

- Both matrices need not be null matrices.

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