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Test:- Permutations And Combinations - 7 - Mathematics MCQ


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20 Questions MCQ Test Topic-wise Tests & Solved Examples for Mathematics - Test:- Permutations And Combinations - 7

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Test:- Permutations And Combinations - 7 - Question 1

The number of 5 letters words that can be formed containing at least one vowel is 

Detailed Solution for Test:- Permutations And Combinations - 7 - Question 1

 5 letter of words formed with at least one vowel + words formed without any vowel = (26)5
Also not a single vowel words = (21)5
⇒ at least one vowel words = (26)5-(21)5

Test:- Permutations And Combinations - 7 - Question 2

The number of different message that can be represented by sequence of three dashes and two dots is :

Detailed Solution for Test:- Permutations And Combinations - 7 - Question 2

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Test:- Permutations And Combinations - 7 - Question 3

The number of intergeral solution of the equation x + y + z = 24 in which each integer is greater than 1 is:

Detailed Solution for Test:- Permutations And Combinations - 7 - Question 3

Test:- Permutations And Combinations - 7 - Question 4

If nCr-1 = 36, nCr = 84 and nC2r+1 = 36, than r is equal to

Detailed Solution for Test:- Permutations And Combinations - 7 - Question 4

Test:- Permutations And Combinations - 7 - Question 5

The number of positive integer which can be formed by using any number of digits from 0,1,2,3,4,5 but using each digit not more than once in each number is:

Detailed Solution for Test:- Permutations And Combinations - 7 - Question 5

Total natural number formed with the help of 0, 

Test:- Permutations And Combinations - 7 - Question 6

Using 7 consonant and 5 vowels, how many words consisting of 4 consonant and 3 vowels can be formed?

Detailed Solution for Test:- Permutations And Combinations - 7 - Question 6

Consonant 7
vowel 5
total words formed =  

Test:- Permutations And Combinations - 7 - Question 7

The value of the expression

Detailed Solution for Test:- Permutations And Combinations - 7 - Question 7

Test:- Permutations And Combinations - 7 - Question 8

Ten different letters of an alphabet are give. Words with five letters are formed from given letter. The numbers of words which have at least one letter repeated is:

Detailed Solution for Test:- Permutations And Combinations - 7 - Question 8

10 different letters word formed from 5 letter (105) - total word at least one letter repeated (10P5)

Test:- Permutations And Combinations - 7 - Question 9

Five balls of different colours are to be placed in three boxes of different size. Each box can hold all five balls. In how many ways can we place the balls so that no box remains empty

Detailed Solution for Test:- Permutations And Combinations - 7 - Question 9

Divide 5 into 3 groups(25 ways) and then arrange a long 3 boxes (3!ways). Total 150 ways.

Test:- Permutations And Combinations - 7 - Question 10

If n-1C3 + n-1C4>nC3,  then the least value of n is.

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Test:- Permutations And Combinations - 7 - Question 11

Six X’s have to be placed in the square of the figure given below such that each row contains at least one X. The number of ways in which his can be done is :

Detailed Solution for Test:- Permutations And Combinations - 7 - Question 11

Test:- Permutations And Combinations - 7 - Question 12

Four gents and two ladies can sit in a merry go round, and if the ladies are to sit side-by-side

Detailed Solution for Test:- Permutations And Combinations - 7 - Question 12

5!2!
= 120 x 2 = 240

Test:- Permutations And Combinations - 7 - Question 13

A candidate is required to answer 6 out of 10 questions which are divided into two groups each containing five questions and he is not permitted to attempt more than 4 from each group. The number of ways, he can make up his choice is:

Detailed Solution for Test:- Permutations And Combinations - 7 - Question 13

Test:- Permutations And Combinations - 7 - Question 14

The greatest possible number of points of intersection of 8 straight lines and 4 circle is: 

Detailed Solution for Test:- Permutations And Combinations - 7 - Question 14

Test:- Permutations And Combinations - 7 - Question 15

Delhi sub urban railway has 21 stations. Designating a ticket from one station to another station as distinct type of ticket, Calculate the number of types of tickets required for the railway services.

Detailed Solution for Test:- Permutations And Combinations - 7 - Question 15

2 x 21C2 = 420

Test:- Permutations And Combinations - 7 - Question 16

How many number can be formed with digits 1,2,3,4,3,2,1 so that odd digits always occupy the odd places?

Detailed Solution for Test:- Permutations And Combinations - 7 - Question 16

Test:- Permutations And Combinations - 7 - Question 17

The number of 3 digits numbers lying between 100 and 999 inclusive and having only odd digit occupy odd places?

Detailed Solution for Test:- Permutations And Combinations - 7 - Question 17

Number between 100 and 999 inclusive
= 5 x 10 x 5
= 250 

Test:- Permutations And Combinations - 7 - Question 18

In how many ways can examiner assign 30 marks to 8 questions giving not less than 2 marks to any questions?

Detailed Solution for Test:- Permutations And Combinations - 7 - Question 18

Test:- Permutations And Combinations - 7 - Question 19

There are five letter and 5 directed envelope. In how many ways can all the letter be put into the wrong envelope?

Detailed Solution for Test:- Permutations And Combinations - 7 - Question 19

Test:- Permutations And Combinations - 7 - Question 20

The number of odd integers between 1000 and 9909 with no digit repealed is :

Detailed Solution for Test:- Permutations And Combinations - 7 - Question 20

Odd integer between 1000 and 9999 
= 8 x 8 x 7 x 5
 = 468 x 5 = 2240

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