Olympiad Test: Direction Sense Test - 1 - Class 5 MCQ

So, Anusha's home is in South-East direction from the school.

The logic follows here is:

If 'South-East' is called 'East', 'North-West' is called 'West', 'South-West' is called 'South'

Now, North will be called as North-West.

So, the correct answer is "North-West".

Manish is 5 m in South-West direction with respect to his starting point.

It is clear from the adjoining diagram that Rakesh lies to the east of Rajesh.
 

Let's break down the directions:

• Pravin starts from his home in the east.
• At the crossing, the road to the left ends in a theatre, which means the road to the left is heading North.
• The road straight ahead leads to the hospital, which means straight ahead is West from his current position.

Since the only remaining direction for the college is North, the college must be in the North direction.
So, the college will be to the north.
 

The movments of the Naresh are as shown in fig.

∴ Naresh’s distance from initial position A
= AE = (AB + BE) = (AB + CD) 
= (30 + 20) m
= 50m  
So, "50 meters" is the correct answer.

The movements of Manoj are as shown in figure (O to P, P to Q, Q to R, R to S and S to T).

Since TS = OP + QR, so T lies with O.
∴ Required distance
OT = (RS – PQ)
= (15 – 10) m = 5 m
So, "5 meters" is the correct answer.

The movements of Nilesh are as shown in fig.

∴ Nilesh distance from his house at A.
AE = (BE – BA) 
= (CD – BA) 
= (25 – 15) m = 10 m  
So, "10 meters" is the correct answer. 

The movements of Geeta are as shown in figure. Clearly she is finally walking in the direction DE i.e, west.
 

The movements of Kishan are as shown in figure (A to B, B to C, C to D).

Clearly his final position is D which is to south-east of starting point A. 

The movements of Mahesh are as shown in fig. (A to B, B to C, C to D, D to E).

∴ Mahesh distance from his original position A = AE = (AB – BE) 
= (AB – CD)
= (30 – 20)m = 10 m 
So, "10 meters" is the correct answer. 

So, "10 Km" is the correct answer. 

Clearly comparing the direction of P w.r.t.
R in second diagram with that in the first diagram, P will be south – west of R.
 

The posture of the Ramesh is as shown. Clearly, the left hand points towards north.

Clearly, the positions of the minute and hour hands at 12 noon and 1.30 p.m. are as shown in the diagram. So, as shown, the hour hand A at 1.30 p.m. points towards the east.

Rohan initially faces in the direction OA. On moving 135° anti clockwise, he faces in the direction OB. On further moving 180° clockwise, he faces on the direction OC, which is south west, as shown in figure.
 

Ritesh moves from his village at O to his uncle’s village at A and thereon to his father in law village at B.
Clearly, ∆OBA is right-angled at B.

So, OA² = OB² + AB²
⇒ OB² = OA² – AB²

So, B is 3 km to the east of his initial position O. 

The movements of Ankur are as shown in figure (P to Q, Q to R and R to S). Clearly, his final position is S which is to the south east of the starting point P.

Given:

Man is facing towards the east.

then he turns north and walks for 5 km.

then he turns 270 degrees anticlockwise.

and finally walks for 12 km more.

Thus the minimum distance between his initial and final position

= √ (5) ² + (12)² 

= √ 25 + 144 = √ 169 = 13 

So, the correct answer is " Option B ".

As per the given information;

Distance between initial and final point = √(20² + 15²)

= √(400 + 225)

= √625

= 25 km

So, "25 km, South-East" is the correct answer.