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Olympiad Test : Simplification - Class 6 MCQ


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10 Questions MCQ Test Maths Olympiad Class 6 - Olympiad Test : Simplification

Olympiad Test : Simplification for Class 6 2024 is part of Maths Olympiad Class 6 preparation. The Olympiad Test : Simplification questions and answers have been prepared according to the Class 6 exam syllabus.The Olympiad Test : Simplification MCQs are made for Class 6 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Olympiad Test : Simplification below.
Solutions of Olympiad Test : Simplification questions in English are available as part of our Maths Olympiad Class 6 for Class 6 & Olympiad Test : Simplification solutions in Hindi for Maths Olympiad Class 6 course. Download more important topics, notes, lectures and mock test series for Class 6 Exam by signing up for free. Attempt Olympiad Test : Simplification | 10 questions in 20 minutes | Mock test for Class 6 preparation | Free important questions MCQ to study Maths Olympiad Class 6 for Class 6 Exam | Download free PDF with solutions
Olympiad Test : Simplification - Question 1

David gets on an elevator at the 11th floor of a building and rides up at the rate of 57 floors per minute. At the same time, Albert gets on an elevator at the 51st floor of the same building and rides down at the rate of 63 floors per minute. If they continue travelling at these rates, then at which floor will their paths cross?

Detailed Solution for Olympiad Test : Simplification - Question 1

Suppose their paths cross after x minutes.
Then, 11 + 57x = 51 – 63x
⇒ 120x = 40
⇒ x =1/3
Number of floors covered by David in (1/3) min. =1/3 × 57= 19.
So, their paths cross at (11 +19) i.e., 30th floor.

Olympiad Test : Simplification - Question 2

Detailed Solution for Olympiad Test : Simplification - Question 2

Let a = 469
b = 469 there
given expression 
=  4ab/ab
=  4

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Olympiad Test : Simplification - Question 3

A man has some hens and cows. If the number of heads be 48 and the number of feet equals 140, then the number of hens will be:

Detailed Solution for Olympiad Test : Simplification - Question 3

Let the number of hens be x and the number of cows be y.
Then, x + y = 48.... (i) and 2x + 4y = 140
⇒ x + 2y = 70 .... (ii)
Solving (i) and (ii) we get: x = 26, y = 22.
∴ The required answer = 26.

Olympiad Test : Simplification - Question 4

Free notebooks were distributed equally among children of a class. The number of notebooks each child got was one-eighth of the number of children. Had the number of children been half, each child would have got 16 notebooks. Total how many notebooks were distributed?

Detailed Solution for Olympiad Test : Simplification - Question 4

Let total number of children be x.
Then, x × (1/8) x = x/2 × 16  ⇔ x = 64
∴ Number of notebooks = x2/8
=1/8 × 64 × 64 = 512

Olympiad Test : Simplification - Question 5

In a regular week, there are 5 working days and for each day, the working hours are 8. A man gets Rs 2.40 per hour for regular work and Rs 3.20 per hours for overtime. If he earns Rs 432 in 4 weeks, then how many hours does he work for?

Detailed Solution for Olympiad Test : Simplification - Question 5

Suppose the man works overtime for x hours.
Now, working hours in 4 weeks = (5 × 8 × 4) = 160
∴ 160 × 2.40 + x × 3.20 = 432
⇒ 3.20x = 432 – 384 = 48
⇒ x = 15
Hence, total hours of work = (160 + 15) = 175

Olympiad Test : Simplification - Question 6

To fill a tank, 25 buckets of water are required. How many buckets of water will be required to fill the same tank if the capacity of the bucket is reduced to two-fifth of its present?

Detailed Solution for Olympiad Test : Simplification - Question 6

Let the capacity of 1 bucket = x
Then, the capacity of tank = 25x
New capacity of bucket = 2x/5
∴ Required number of buckets
= 25x/ (2x/5) =125/2 = 62.5

Olympiad Test : Simplification - Question 7

Eight people are planning to share equally the cost of a rental car. If one person withdraws from the arrangement and the others share equally the entire cost of the car, then the share of each of the remaining persons is increased by:

Detailed Solution for Olympiad Test : Simplification - Question 7

Original share of 1 person =1/8
New share of 1 person =1/7
Increase = 1/7 – 1/8 = 1/56
∴ Required fraction = (1/56) / (1/8) = 1/7

Olympiad Test : Simplification - Question 8

A fires 5 shots to B’s 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, A has killed:

Detailed Solution for Olympiad Test : Simplification - Question 8

Let the total number of shots be x. Then,
Shots fired by A    = 5x/8
Shots fired by B    = 3x/8
Killing shots by A = 1/3 of 5x/8 = 5x/24
Shots missed by B = 1/2 of 3x/8 = 3x/16
∴ 3x/16= 27 or x = 144
Birds killed by A = 5x/24 = (5x 144)/24 = 30

Olympiad Test : Simplification - Question 9

One-third of Rahul’s savings in National Savings Certificate is equal to one-half of his savings in Public Provident Fund. If he has Rs 1, 50,000 as total savings, how much has he saved in Public Provident Fund?

Detailed Solution for Olympiad Test : Simplification - Question 9

Let savings in N.S.C and P.P.F. be Rs x and Rs.
(150000 – x) respectively. Then,
1/3x =1/2(150000 – x)
⇒ x/3 + x/2 = 75000
⇒ 5x/6 = 75000
⇒ x = (75000 × 6)/5 = Rs = 90000
∴ Savings in Public Provident Fund
= Rs (1 50000 – 90000) = Rs 60000

Olympiad Test : Simplification - Question 10

A sum of Rs 1360 has been divided among A, B and C such that A gets 2/3 of what B gets and B gets 1/4 of what C gets. B’s share is:

Detailed Solution for Olympiad Test : Simplification - Question 10

Let C’s share = Rs x
Then, B’s share = Rs x/4,
A’s share = Rs 2/3 × x/4    = Rs x/6
⇒ 17x/12 = 1360
⇒ x = (1360 × 12)/17= Rs 960
Hence, B’s share = Rs 960/4 = Rs 240

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