Olympiad Test: Analogy and Classification - Class 6 MCQ

The relationship between 7 and 14 is that 14 is double of 7 (7 × 2 = 14). Similarly, following the same pattern, 9 doubled would be 18 (9 × 2 = 18). Therefore, 9 is to 18 in the same way that 7 is to 14.

To find the relationship between 6 and 19, we can analyze the pattern:
6 × 3 + 1 = 196
Now, applying the same pattern to 4: 4 × 3 + 1 = 13.
Therefore, 4 is related to 13 in the same way that 6 is related to 19.

To find the relationship between 8 and 28, we observe that 8 × 3 + 4 = 28.

Now, applying the same pattern to 27: 27 × 3 + 4 = 81 + 4 = 47.

Therefore, 27 is related to 47 in the same way that 8 is related to 28.

The logic followed here is:

Multiplication of digits of first number = Second number 

34 is related to 12

3 × 4 = 12

Similarly,

59 is related to

5 × 9 = 45

Hence, '45' is the correct answer.

The numbers 312, 432, and 234 are all divisible by 3, but 151 is not divisible by 3.

Let's check:

• 312: 3 + 1 + 2 = 6 (divisible by 3)
• 432: 4 + 3 + 2 = 9 (divisible by 3)
• 234: 2 + 3 + 4 = 9 (divisible by 3)
• 151: 1 + 5 + 1 = 7 (not divisible by 3)

Thus, 151 is different from the others.

To find the relationship between 12 and 144, observe that 12² = 144.

Applying the same pattern to 17: 17² = 289.

Therefore, 17 is related to 289 in the same way that 12 is related to 144.

The relationship between 1 and 1 could be 1³ = 1 (cubing the number).

Now applying the same pattern to 5: 5³ = 125.

Therefore, 5 is related to 125 in the same way that 1 is related to 1.

To find the relationship between 16 and 56, observe that 16 × 3 + 8 = 56.

Now, applying the same pattern to 32: 32 × 3 + 8 = 96 + 8 = 112.

Therefore, 32 is related to 112 in the same way that 16 is related to 56.

Each letter in the first set is moved three positions backward in the alphabet. So, R comes three places before U, A three places before D, and N three places before Q. Applying the same logic, RUN would become ORK by moving each letter three places backward in the alphabet.

The logic followed here is:

Figure a) → Slant and horizontal line is present.

Option b) → Vertical and horizontal line is present.

Option c) → Vertical and horizontal line is present.

Option d) → Vertical and horizontal line is present.

Thus, out of all the options, figure 'a' is the odd one out.

Hence, "Option A" is the correct answer.

Here all the polygon are of odd number of sides except hexagone.

Hendecagon is a polygon of 11 sides, Heptagon is a polygon of 7 sides and Pentagon is a polygon of 5 sides.

Only Hexagon is an odd one here as it has even number of sides i.e. 6 sides.

Hence, option B is the correct answer.

The logic followed here is:

All the numbers except option (c), the given numbers are the multiple of 11. 

Option A: 2321 → Multiple of 11

Option B: 825 → Multiple of 11

Option C: 1521 → Not a multiple of 11

Option D: 968 → Multiple of 11

Therefore, 1521 is the odd one option.

The odd one out is Spinach. As onion, radish and turnip grow underground but spinach doesn't grow underground.

Hence, option 1 is the correct answer.

By checking options:

(A) Sky : Cloud → Cloud is not a type of Sky. 

(B) Purse : Wallet → Wallet is a type of Purse.

(C) Cupboard : Almirah → Almirah is a type of Cupboard.

(D) Chair : Stool → Stool is a type of Chair.

Hence, Sky : Cloud is the odd one out.

The relationship between 124 and 248 is that 248 is double of 124 (124 × 2 = 248).

Now, applying the same logic to the second pair, we want to find the number that, when doubled, gives 5000: 5000 ÷ 2 = 2500

Therefore, the number related to 5000 in the same way that 124 is related to 248 is 2500.