Class 7 Exam  >  Class 7 Tests  >  Mathematics (Maths) Class 7  >  Olympiad Test: Perimeter and Area - 1 - Class 7 MCQ

Olympiad Test: Perimeter and Area - 1 - Class 7 MCQ


Test Description

10 Questions MCQ Test Mathematics (Maths) Class 7 - Olympiad Test: Perimeter and Area - 1

Olympiad Test: Perimeter and Area - 1 for Class 7 2024 is part of Mathematics (Maths) Class 7 preparation. The Olympiad Test: Perimeter and Area - 1 questions and answers have been prepared according to the Class 7 exam syllabus.The Olympiad Test: Perimeter and Area - 1 MCQs are made for Class 7 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Olympiad Test: Perimeter and Area - 1 below.
Solutions of Olympiad Test: Perimeter and Area - 1 questions in English are available as part of our Mathematics (Maths) Class 7 for Class 7 & Olympiad Test: Perimeter and Area - 1 solutions in Hindi for Mathematics (Maths) Class 7 course. Download more important topics, notes, lectures and mock test series for Class 7 Exam by signing up for free. Attempt Olympiad Test: Perimeter and Area - 1 | 10 questions in 20 minutes | Mock test for Class 7 preparation | Free important questions MCQ to study Mathematics (Maths) Class 7 for Class 7 Exam | Download free PDF with solutions
Olympiad Test: Perimeter and Area - 1 - Question 1

The area of triangle is

Detailed Solution for Olympiad Test: Perimeter and Area - 1 - Question 1

the area of a triangle is given by the formula: (1/2) × base × height

Olympiad Test: Perimeter and Area - 1 - Question 2

The height in the area of a triangle

Detailed Solution for Olympiad Test: Perimeter and Area - 1 - Question 2

we know that:

 area=(1/2) × base × height
so, height=(2×area)/base

1 Crore+ students have signed up on EduRev. Have you? Download the App
Olympiad Test: Perimeter and Area - 1 - Question 3

Find the area of following traingle:

Detailed Solution for Olympiad Test: Perimeter and Area - 1 - Question 3

Area of triangle= ½ *base*height
=½*4*3=6cm2

Olympiad Test: Perimeter and Area - 1 - Question 4

A door frame of dimensions 4m * 5m is fixed on the wall of dimension 11m * 11m. Find the total labour charges for painting the wall if the labour charges for painting 1m2 of the wall is Rs 2.50.

Detailed Solution for Olympiad Test: Perimeter and Area - 1 - Question 4

The total area of the wall can be calculated by subtracting the area of the door from the total area of the wall.

The area of the wall is 11×11=121m2.

The area of the door is 4m×5m=20m2.

Therefore, the remaining area to be painted is 1212−202=101m2.

Now, multiply the remaining area by the labor charges per square meter to find the total labor charges:

Total labor charges=Area to be painted×Labor charges per square meter

Total labor charges=101m2×Rs 2.50/m2

Total labor charges=Rs 252.50

So, the total labor charges for painting the wall would be Rs 252.50.

 

 

 

 

 

 

Olympiad Test: Perimeter and Area - 1 - Question 5

What is the circumference of a circle of diameter 10 cm?

Detailed Solution for Olympiad Test: Perimeter and Area - 1 - Question 5

use the formula of circumference: 2πr

given: diameter=2r=10cm

so, circumference 2πr=(3.14)10=31.4 cm

Olympiad Test: Perimeter and Area - 1 - Question 6

Find the breadth of a rectangular plot of land, if its area is 440 m2 and the length is 22 m.

Detailed Solution for Olympiad Test: Perimeter and Area - 1 - Question 6

The formula for the area of a rectangle is given by:

Area=Length×Breadth

In this case, the area is given as 440 m² and the length is given as 22 m. Let's denote the breadth as B. The formula can be rearranged to solve for the breadth:

Breadth=Area/Length

Substitute the given values:

Breadth=440 m2/22 m

Breadth=20 m

Olympiad Test: Perimeter and Area - 1 - Question 7

The ______ is the distance around a given two-dimensional object.

Detailed Solution for Olympiad Test: Perimeter and Area - 1 - Question 7

perimeter is the distance around a given two-dimensional object.

Olympiad Test: Perimeter and Area - 1 - Question 8

If we cut a square along one of its diagonals, two triangles are obtained. Area of each triangle obtained = __________.

Detailed Solution for Olympiad Test: Perimeter and Area - 1 - Question 8

The correct answer is A:

When a square is cut along one of its diagonals, it forms two congruent right-angled triangles. Each of these triangles has a base and height equal to one of the sides of the square. The area of a triangle is given by the formula:

Area of a triangle=(1/2)×base×height

In this case, the base and height of each triangle are the sides of the square. Therefore, the area of each triangle is:

Area of each triangle=(1/2)×side×side

Since the side of the square is the length of the diagonal, we can write the area of each triangle as:

Area of each triangle=(1/2)×diagonal×diagonal

So, the correct option is A: (1/2)×Area of the square.

 

 

 

 

 

 

Olympiad Test: Perimeter and Area - 1 - Question 9

Olympiad Test: Perimeter and Area - 1 - Question 10

A rectangular garden has a length of 12 meters and a width of 8 meters. What is the perimeter of the garden?

Detailed Solution for Olympiad Test: Perimeter and Area - 1 - Question 10

Perimeter of a rectangle = 2 * (Length + Width)

Given: Length = 12 meters Width = 8 meters

Perimeter = 2 * (12 meters + 8 meters) Perimeter = 2 * (20 meters) Perimeter = 40 meters

So, the perimeter of the garden is 40 meters.

76 videos|345 docs|39 tests
Information about Olympiad Test: Perimeter and Area - 1 Page
In this test you can find the Exam questions for Olympiad Test: Perimeter and Area - 1 solved & explained in the simplest way possible. Besides giving Questions and answers for Olympiad Test: Perimeter and Area - 1, EduRev gives you an ample number of Online tests for practice

Up next

76 videos|345 docs|39 tests
Download as PDF

Up next