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# Test: Coupled Circuits Part - 3

## 10 Questions MCQ Test Networking Theory | Test: Coupled Circuits Part - 3

Description
This mock test of Test: Coupled Circuits Part - 3 for Electrical Engineering (EE) helps you for every Electrical Engineering (EE) entrance exam. This contains 10 Multiple Choice Questions for Electrical Engineering (EE) Test: Coupled Circuits Part - 3 (mcq) to study with solutions a complete question bank. The solved questions answers in this Test: Coupled Circuits Part - 3 quiz give you a good mix of easy questions and tough questions. Electrical Engineering (EE) students definitely take this Test: Coupled Circuits Part - 3 exercise for a better result in the exam. You can find other Test: Coupled Circuits Part - 3 extra questions, long questions & short questions for Electrical Engineering (EE) on EduRev as well by searching above.
QUESTION: 1

### Leq =?

Solution:

Let I1 be the current through 4 H inductor and I2 and I3 be the current through 3 H, and 2 H inductor respectively

QUESTION: 2

Solution:

QUESTION: 3

### Consider the circuit shown in fig. P1.9.22–24. Q. The voltage vBG of terminal BD is

Solution:

QUESTION: 4

Consider the circuit shown in fig. P1.9.22–24.

Q. The voltage vCG of terminal CD is

Solution:

QUESTION: 5

In the circuit of fig. P1.9.33 the ω = 2 rad/s. The resonance occurs when C is

Solution:

QUESTION: 6

In the circuit of fig. P1.9.34, the voltage gain is zero at ω = 333.33 rad/s. The value of C is

Solution:

QUESTION: 7

In the circuit of fig. P1.9.35 at ω = 333.33 rad/s, the voltage gain vout/vin is zero. The value of C is

Solution:

The π  equivalent circuit of coupled coil is shown in fig. S1.9.35

QUESTION: 8

The Thevenin equivalent at terminal ab for the network shown in fig. P1.9.36 is

Solution:

Applying 1 V test source at ab terminal,

QUESTION: 9

In the circuit of fig. P1.9.37 the maximum power delivered to RL is

Solution:

Impedance seen by RL = 10 x 42 = 160 Ω
For maximum power RL = 160 Ω, Zo = 10Ω

QUESTION: 10

The average power delivered to the 8Ω load in the circuit of fig. P1.9.38 is

Solution: