Test: Sinusoidal Steady‐state Analysis Part - 2


10 Questions MCQ Test Networking Theory | Test: Sinusoidal Steady‐state Analysis Part - 2


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This mock test of Test: Sinusoidal Steady‐state Analysis Part - 2 for Electrical Engineering (EE) helps you for every Electrical Engineering (EE) entrance exam. This contains 10 Multiple Choice Questions for Electrical Engineering (EE) Test: Sinusoidal Steady‐state Analysis Part - 2 (mcq) to study with solutions a complete question bank. The solved questions answers in this Test: Sinusoidal Steady‐state Analysis Part - 2 quiz give you a good mix of easy questions and tough questions. Electrical Engineering (EE) students definitely take this Test: Sinusoidal Steady‐state Analysis Part - 2 exercise for a better result in the exam. You can find other Test: Sinusoidal Steady‐state Analysis Part - 2 extra questions, long questions & short questions for Electrical Engineering (EE) on EduRev as well by searching above.
QUESTION: 1

The circuit is as shown in fig. P1.7.17-18

Q.i2(t) = ?

Solution:


QUESTION: 2

I x = ?

Solution:


QUESTION: 3

Vx = ?

Solution:

Let Vo be the voltage across current source

QUESTION: 4

Determine the complex power for the given values in question.
Q. P = 269 W, Q = 150 VAR (capacitive)

Solution:

S = P - jQ = 269 - j150 VA

QUESTION: 5

Determine the complex power for the given values in question.
Q. Q = 2000 VAR, pf = 0.9 (leading)

Solution:


QUESTION: 6

Determine the complex power for the given values in question.
Q. S = 60 VA, Q = 45 VAR (inductive)

Solution:


QUESTION: 7

Determine the complex power for the given values in question.
Q. Vrms = 220 V, P = 1 kW, |Z| = 40 Ω (inductive)

Solution:


QUESTION: 8

Determine the complex power for the given values in question.
Q. Vrms = 21∠ 200V, Vrms = 21∠200V, I rms = 8.5∠-500A

Solution:


= 61+ j167.7VA

QUESTION: 9

Determine the complex power for the given values in question.
Q. Vrms = 120∠ 300V, Z = 40 + j 80Ω

Solution:

QUESTION: 10

Vo = ?

Solution:


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