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# Test: Sinusoidal Steady‐state Analysis Part - 3

## 10 Questions MCQ Test Networking Theory | Test: Sinusoidal Steady‐state Analysis Part - 3

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This mock test of Test: Sinusoidal Steady‐state Analysis Part - 3 for Electrical Engineering (EE) helps you for every Electrical Engineering (EE) entrance exam. This contains 10 Multiple Choice Questions for Electrical Engineering (EE) Test: Sinusoidal Steady‐state Analysis Part - 3 (mcq) to study with solutions a complete question bank. The solved questions answers in this Test: Sinusoidal Steady‐state Analysis Part - 3 quiz give you a good mix of easy questions and tough questions. Electrical Engineering (EE) students definitely take this Test: Sinusoidal Steady‐state Analysis Part - 3 exercise for a better result in the exam. You can find other Test: Sinusoidal Steady‐state Analysis Part - 3 extra questions, long questions & short questions for Electrical Engineering (EE) on EduRev as well by searching above.
QUESTION: 1

Solution:

Apparent power

QUESTION: 2

Solution:

QUESTION: 3

### The power factor seen by the voltage source is

Solution:

QUESTION: 4

The average power supplied by the dependent source is

Solution:

QUESTION: 5

In the circuit of fig. P1.7.38 the maximum power absorbed by ZL is

Solution:

QUESTION: 6

The value of the load impedance, that would absorbs the maximum average power is

Solution:

QUESTION: 7

In a balanced Y–connected three phase generator Vab = 400 Vrms
Q. If phase sequence is abc then phase voltage Va, Vb,and Vc are respectively

Solution:

QUESTION: 8

In a balanced Y–connected three phase generator Vab = 400 Vrms
Q. If phase sequence is acb then phase voltage are

Solution:

For the acb sequence

QUESTION: 9

A balanced three-phase Y-connected load has one phase voltage Vc = 277∠450V. The phase sequence is abc. The line to line voltage VAB is

Solution:

QUESTION: 10

A three-phase circuit has two parallel balanced Δ loads, one of the 6Ω resistor and one of 12 Ω resistors. The magnitude of the total line current, when the line-to-line voltage is 480 Vrms ,is

Solution:

Z A = 6 ||12 = 4,