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Electrical Engineering (EE) Exam  >  Electrical Engineering (EE) Tests  >  Network Theory (Electric Circuits)  >  Test: Unbalanced Three Phase Circuits - Electrical Engineering (EE) MCQ

Test: Unbalanced Three Phase Circuits - Electrical Engineering (EE) MCQ


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10 Questions MCQ Test Network Theory (Electric Circuits) - Test: Unbalanced Three Phase Circuits

Test: Unbalanced Three Phase Circuits for Electrical Engineering (EE) 2025 is part of Network Theory (Electric Circuits) preparation. The Test: Unbalanced Three Phase Circuits questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: Unbalanced Three Phase Circuits MCQs are made for Electrical Engineering (EE) 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Unbalanced Three Phase Circuits below.
Solutions of Test: Unbalanced Three Phase Circuits questions in English are available as part of our Network Theory (Electric Circuits) for Electrical Engineering (EE) & Test: Unbalanced Three Phase Circuits solutions in Hindi for Network Theory (Electric Circuits) course. Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free. Attempt Test: Unbalanced Three Phase Circuits | 10 questions in 30 minutes | Mock test for Electrical Engineering (EE) preparation | Free important questions MCQ to study Network Theory (Electric Circuits) for Electrical Engineering (EE) Exam | Download free PDF with solutions
Test: Unbalanced Three Phase Circuits - Question 1
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If the system is a three-wire system, the currents flowing towards the load in the three lines must add to ___ at any given instant.

Detailed Solution for Test: Unbalanced Three Phase Circuits - Question 1

If the system is a three-wire system, the currents flowing towards the load in the three lines must add to zero at any given instant.

Test: Unbalanced Three Phase Circuits - Question 2
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The three impedances Z1 = 20∠30⁰Ω, Z2 = 40∠60⁰Ω, Z3 = 10∠-90⁰Ω are delta-connected to a 400V, 3 – Ø system. Find the phase current IY.

Detailed Solution for Test: Unbalanced Three Phase Circuits - Question 2

The voltage VYB is VYB = 400 ∠ -120⁰V. The impedance Z2 is Z2 = 40 ∠ 60⁰Ω

⇒ IY = (400 ∠ -120o)/(40 ∠ 60o)=(-10 + j0)A.

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Test: Unbalanced Three Phase Circuits - Question 3
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The three impedances Z1 = 20∠30⁰Ω, Z2 = 40∠60⁰Ω, Z3 = 10∠-90⁰Ω are delta-connected to a 400V, 3 – Ø system. Find the line current I1.

Detailed Solution for Test: Unbalanced Three Phase Circuits - Question 3

The line current I1 is the difference of IR and IB. So the line current I1 is I1 = IR – IB = (51.96 + j10) A.

Test: Unbalanced Three Phase Circuits - Question 4
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The three impedances Z1 = 20∠30⁰Ω, Z2 = 40∠60⁰Ω, Z3 = 10∠-90⁰Ω are delta-connected to a 400V, 3 – Ø system. Find the line current I3.
Detailed Solution for Test: Unbalanced Three Phase Circuits - Question 4

The line current I3 is the difference of IB and IY. So the line current I3 is I3 = IB – IY = (-24.646 - j20) A.

Test: Unbalanced Three Phase Circuits - Question 5
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The three impedances Z1 = 20∠30⁰Ω, Z2 = 40∠60⁰Ω, Z3 = 10∠-90⁰Ω are delta-connected to a 400V, 3 – Ø system. Find the power in the Y phase.
Detailed Solution for Test: Unbalanced Three Phase Circuits - Question 5

The term power is defined as the product of square of current and the impedance. So the power in the Y phase = 102 x 20 = 2000W.

Test: Unbalanced Three Phase Circuits - Question 6
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The three impedances Z1 = 20∠30⁰Ω, Z2 = 40∠60⁰Ω, Z3 = 10∠-90⁰Ω are delta-connected to a 400V, 3 – Ø system. Find the power in the B phase.
Detailed Solution for Test: Unbalanced Three Phase Circuits - Question 6

The term power is defined as the product of square of current and the impedance. So the power in the B phase = 402 x 0 = 0W.

Test: Unbalanced Three Phase Circuits - Question 7
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The three impedances Z1 = 20∠30⁰Ω, Z2 = 40∠60⁰Ω, Z3 = 10∠-90⁰Ω are delta-connected to a 400V, 3 – Ø system. Find the power in the R phase.
Detailed Solution for Test: Unbalanced Three Phase Circuits - Question 7

The term power is defined as the product of square of current and the impedance. So the power in the R phase = 202 x 17.32 = 6928W.

Test: Unbalanced Three Phase Circuits - Question 8
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The three impedances Z1 = 20∠30⁰Ω, Z2 = 40∠60⁰Ω, Z3 = 10∠-90⁰Ω are delta-connected to a 400V, 3 – Ø system. Find the line current I2.
Detailed Solution for Test: Unbalanced Three Phase Circuits - Question 8

The line current I2 is the difference of IY and IR. So the line current I2 is I2 = IY – IR = (-27.32 + j10) A.

Test: Unbalanced Three Phase Circuits - Question 9
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The three impedances Z1 = 20∠30⁰Ω, Z2 = 40∠60⁰Ω, Z3 = 10∠-90⁰Ω are delta-connected to a 400V, 3 – Ø system. Find the phase current IB.
Detailed Solution for Test: Unbalanced Three Phase Circuits - Question 9

The voltage VBR is VBR = 400 ∠ -240⁰V. The impedance Z3 is Z3 = 10 ∠ -90⁰Ω
⇒ IB = (400 ∠ 240o)/(10 ∠ -90o) = (-34.64-j20)A.

Test: Unbalanced Three Phase Circuits - Question 10
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The three impedances Z1 = 20∠30⁰Ω, Z2 = 40∠60⁰Ω, Z3 = 10∠-90⁰Ω are delta-connected to a 400V, 3 – Ø system. Determine the phase current IR.
Detailed Solution for Test: Unbalanced Three Phase Circuits - Question 10

Taking VRY = V∠0⁰ as a reference phasor, and assuming RYB phase sequence, we have VRY = 400∠0⁰V Z1 = 20∠30⁰Ω = (17.32 + j10)Ω IR = (400∠0o)/(20∠30o) = (17.32 - j10) A.

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