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Test: Respiration in Plants - 1 - NEET MCQ


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20 Questions MCQ Test Biology Class 11 - Test: Respiration in Plants - 1

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Test: Respiration in Plants - 1 - Question 1

The TCA cycle starts with:

Detailed Solution for Test: Respiration in Plants - 1 - Question 1

The TCA cycle begins with a condensation reaction. In this step, an acetyl group, derived from the breakdown of glucose or fatty acids, combines with oxaloacetic acid (OAA), a four-carbon molecule, in the presence of water. This condensation reaction forms a six-carbon compound called citric acid or citrate.

The complete reaction is as follows:
Acetyl-CoA + OAA + H2O → Citric Acid (Citrate)

The condensation step is significant because it marks the entry of the acetyl group into the TCA cycle and the beginning of a series of enzymatic reactions that ultimately lead to the release of energy and the regeneration of OAA.

Topic in NCERT: Tricarboxylic acid cycle

Line in NCERT: "The TCA cycle starts with the condensation of acetyl group with oxaloacetic acid (OAA) and water to yield citric acid."

Test: Respiration in Plants - 1 - Question 2

During anaerobic respiration less energy is produced than aerobic respiration because:

Detailed Solution for Test: Respiration in Plants - 1 - Question 2

During anaerobic respiration, less energy is produced compared to aerobic respiration because incomplete oxidation of glucose occurs. Anaerobic respiration occurs in the absence of oxygen, typically in situations where oxygen is not readily available or during strenuous exercise when oxygen demand exceeds supply.

Topic in NCERT: Fermentation

Line in NCERT: "In fermentation there is a net gain of only two molecules of ATP for each molecule of glucose degraded to pyruvic acid whereas many more molecules of ATP are generated under aerobic conditions."

Test: Respiration in Plants - 1 - Question 3

The enzyme that interconnects the glycolysis and kreb cycle is:

Detailed Solution for Test: Respiration in Plants - 1 - Question 3

The two molecules of pyruvic acid (produced from one glucose molecule during glycolysis). The acetyl CoA then enters a cyclic pathway, tricarboxylic acid cycle, more commonly called as Krebs’ cycle. Thus, acetyl-CoA interconnecting between two cyclic pathways.

Topic in NCERT: Tricarboxylic acid cycle

Line in NCERT: "The acetyl CoA then enters a cyclic pathway, tricarboxylic acid cycle,"

Test: Respiration in Plants - 1 - Question 4

In plants, the gaseous exchange take place in:
(a) Stomata
(b) Roots
(c) Stems
(d) Lenticels

Detailed Solution for Test: Respiration in Plants - 1 - Question 4

Plants unlike animals have no special systems for breathing or gaseous exchange. Stomata and lenticels allow gaseous exchange by diffusion.

(a) Stomata: Stomata are tiny openings present on the surface of leaves, primarily on the underside. These openings are surrounded by specialized cells called guard cells. Stomata regulate the exchange of gases, including the intake of carbon dioxide (CO2) for photosynthesis and the release of oxygen (O2) and water vapor (H2O) during transpiration. Stomata play a crucial role in the gas exchange process in plants.

(d) Lenticels: Lenticels are small openings or pores in the bark of woody plant stems. They allow for gaseous exchange between the internal tissues of the stem and the external environment. Lenticels facilitate the exchange of gases, such as oxygen (O2) and carbon dioxide (CO2), in stems and other woody parts of plants.

Topic in NCERT: Do plants breathe?

Line in NCERT: "Plants, unlike animals, have no specialised organs for gaseous exchange but they have stomata and lenticels for this purpose."

Test: Respiration in Plants - 1 - Question 5

Which of the following statements are correct?

(A) The oxidation of pyruvic acid molecules formed in glycolysis occurs inside the mitochondria.

(B) Acetyl CoA is a 3-carbon compound.

(C) Under anaerobic conditions, the pyruvic acid formed during glycolysis is reduced to either ethyl alcohol or lactic acid.

(D) Acetyl CoA molecules enter into cyclic reactions during Calvin cycle.

Detailed Solution for Test: Respiration in Plants - 1 - Question 5

The correct statements are:

(A) The oxidation of pyruvic acid molecules formed in glycolysis occurs inside the mitochondria.
(C) Under anaerobic conditions, the pyruvic acid formed during glycolysis is reduced to either ethyl alcohol or lactic acid.

Explanation:

  • (A) Correct: Pyruvic acid (a 3-carbon compound) produced in glycolysis enters the mitochondria, where it is oxidatively decarboxylated to form Acetyl CoA (a 2-carbon compound) before entering the Krebs cycle.

  • (B) Incorrect: Acetyl CoA is a 2-carbon compound, not 3-carbon.

  • (C) Correct: In anaerobic conditions, pyruvate is reduced to:

    • Lactic acid (in animal cells/muscles via lactate fermentation).

    • Ethanol + CO₂ (in yeast/plant cells via alcoholic fermentation).

  • (D) Incorrect: Acetyl CoA enters the Krebs cycle (in mitochondria), not the Calvin cycle (which fixes CO₂ in chloroplasts using RuBisCO).

Final Answer:

(A) and (C) are correct

 

Test: Respiration in Plants - 1 - Question 6

Which of the following reactions is catalysed by the enzyme phosphofructokinase?

Detailed Solution for Test: Respiration in Plants - 1 - Question 6

Phosphofructokinase is a kinase enzyme that phosphorylates fructose-6-phosphate in glycolysis. The enzyme catalysed transfer of a phosphoryl group from ATP is an important reaction in a wide variety of biological processes.

Test: Respiration in Plants - 1 - Question 7

In animal cells, the first stage of glucose break down is:

Detailed Solution for Test: Respiration in Plants - 1 - Question 7

In animal cells, like muscles during exercise, when oxygen is inadequate for cellular respiration pyruvic acid is reduced to lactic acid by lactate dehydrogenase. The reducing agent is NADH+ and H+ which is reoxidised to NAD+ in both the processes.

Topic in NCERT: Glycolysis

Line in NCERT: "The initial stage of cellular respiration takes place in the cytoplasm. Each glucose molecule is broken through a series of enzyme catalysed reactions into two molecules of pyruvic acid. This process is called glycolysis."

Test: Respiration in Plants - 1 - Question 8

In kreb cycle, isocitric acid is converted into α-keto glutaric acid by:

Detailed Solution for Test: Respiration in Plants - 1 - Question 8

Citrate is first isomerised to isocitrate and then followed by decarboxylation, leading to the formation of α-ketoglutaric acid.

Topic in NCERT: Tricarboxylic acid cycle

Line in NCERT: "The reaction is catalysed by the enzyme citrate synthase and a molecule of CoA is released. Citrate is then isomerised to isocitrate. It is followed by two successive steps of decarboxylation, leading to the formation of α-ketoglutaric acid."

Test: Respiration in Plants - 1 - Question 9

F0−F1 particles participate in the synthesis of:

Detailed Solution for Test: Respiration in Plants - 1 - Question 9
  • Oxysomes refer to small round structures present within the folds of the cristae of the inner mitochondrial membrane. It is also known as F0-F1 particles.
  • F0 and F1 particles are found in the inner mitochondrial region and are attached to the cristae and help in ATP production and oxidation.
Test: Respiration in Plants - 1 - Question 10

Cytochrome c is the first electron acceptor in the electron transport chain. Which of the following statements is false about cytochrome c?

Detailed Solution for Test: Respiration in Plants - 1 - Question 10

Cytochrome c is a water soluble protein.

Topic in NCERT: Cytochrome c

Line in NCERT: "Cytochrome c is a small protein attached to the outer surface of the inner membrane and acts as a mobile carrier for transfer of electrons between complex III and IV."

Test: Respiration in Plants - 1 - Question 11

Acetyl CoA forms a 6-C compound after combining with 

Detailed Solution for Test: Respiration in Plants - 1 - Question 11

Acetyl CoA is the connecting link between glycolysis and Kreb's cycle. The end product of glycolysis is pyruvate. It is converted to Acetyl CoA which enters the krebs cycle by combining with oxaloacetic acid (OAA) to form a 6 - C compound citric acid.

Topic in NCERT: Tricarboxylic acid cycle

Line in NCERT: "The TCA cycle starts with the condensation of acetyl group with oxaloacetic acid (OAA) and water to yield citric acid."

Test: Respiration in Plants - 1 - Question 12

Which of the following is performed by coenzyme A?

Detailed Solution for Test: Respiration in Plants - 1 - Question 12

CoA is acetylated to acetyl CoA by the breakdown of carbohydrates through glycolysis and by the breakdown of fatty acids through β-oxidation.

Topic in NCERT: Breakdown of pyruvate

Line in NCERT: "Pyruvic acid is transported into the mitochondria where it is converted into acetyl CoA with the release of CO2."

Test: Respiration in Plants - 1 - Question 13

The respiratory quotient(RQ) is defined as:

Detailed Solution for Test: Respiration in Plants - 1 - Question 13

The ratio of the volume of carbon dioxide evolved to the volume of oxygen consumed in respiration is called the respiratory quotient(RQ) or respiratory ratio

Topic in NCERT: Respiratory quotient

Line in NCERT: "The ratio of the volume of CO2 evolved to the volume of O2 consumed in respiration is called the respiratory quotient (RQ) or respiratory ratio."

Test: Respiration in Plants - 1 - Question 14

Choose the correct names of A, B, C and D

Detailed Solution for Test: Respiration in Plants - 1 - Question 14

Test: Respiration in Plants - 1 - Question 15

Which one is NOT a preparatory phase or energy spending phase of Glycolysis:

Detailed Solution for Test: Respiration in Plants - 1 - Question 15

Formation of pyruvate is not a prerparatory phase or energy spending phase of Glycolysis. In this phase one ATP molecule is released.

Topic in NCERT: Glycolysis phases

Line in NCERT: "Pyruvic acid is then the key product of glycolysis."

Test: Respiration in Plants - 1 - Question 16

The CORRECT  sequential order of pathway is:

Detailed Solution for Test: Respiration in Plants - 1 - Question 16

There is a sequential, orderly pathway functioning, with one substrate forming the next and with glycolysis, TCA cycle and ETS pathway following one after another.

Topic in NCERT: Glycolysis, TCA cycle and ETS pathway

Line in NCERT: "There is a sequential, orderly pathway functioning, with one substrate forming the next and with glycolysis, TCA cycle and ETS pathway following one after another."

Test: Respiration in Plants - 1 - Question 17

The respiratory quotient depends upon:

Detailed Solution for Test: Respiration in Plants - 1 - Question 17

The value of R.Q. depends upon the nature of the respiratory substrate (the organic food matter oxidised in respiration) and its oxidation.

Topic in NCERT: Respiratory quotient

Line in NCERT: "The respiratory quotient depends upon the type of respiratory substrate used during respiration."

Test: Respiration in Plants - 1 - Question 18

What is the number of ATP molecules that can be regarded as a net gain during aerobic respiration of one molecule of glucose? 

Detailed Solution for Test: Respiration in Plants - 1 - Question 18

There can be a net gain of 38 ATP molecules during aerobic respiration of one molecule of glucose. 

Topic in NCERT: Net gain of ATP in aerobic respiration

Line in NCERT: "Hence, there can be a net gain of 38 ATP molecules during aerobic respiration of one molecule of glucose."

Test: Respiration in Plants - 1 - Question 19
The chemiosmotic coupling hypothesis of oxidative phosphorylation proposes that Adenosine Triphosphate (ATP) is formed because:
Detailed Solution for Test: Respiration in Plants - 1 - Question 19
The chemiosmotic coupling hypothesis explains ATP synthesis in mitochondria. It states that ATP is produced as a result of a proton gradient formed across the inner mitochondrial membrane. This gradient powers ATP synthase, leading to the conversion of ADP into ATP. Hence, Option C is the correct answer.
Test: Respiration in Plants - 1 - Question 20

Match the following:

Detailed Solution for Test: Respiration in Plants - 1 - Question 20

A (Molecular oxygen): Oxygen is a hydrogen acceptor in the electron transport chain (ETC). Hence, A matches with 2 (Hydrogen acceptor).

B (Electron acceptor): Cytochrome-c acts as the electron acceptor in the ETC, so B matches with 3 (Cytochrome-c).

C (Pyruvate dehydrogenase): Pyruvate dehydrogenase converts pyruvate to acetyl Co-A, making C match with 4 (Acetyl Co-A).

D (Decarboxylation): Decarboxylation often occurs in metabolic processes, including the conversion of α-ketoglutaric acid to succinyl-CoA. Thus, D matches with 1 (α-ketoglutaric acid).

The correct matching is:

A - 2 (Hydrogen acceptor)

B - 3 (Cytochrome-c)

C - 4 (Acetyl Co-A)

D - 1 (α-ketoglutaric acid)

Therefore, the correct answer is Option C.

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