Choose the alternative that will complete the series.
Q. aab – ab – cabcca – bcab – c
The series is aa/bcab/bcab/ccaa/bcab/bc Thus, the pattern ccaa followed by bcab repeated twice, makes up the series.
Choose the alternative that will complete the series.
Q. bc – b – c – b – ccb
The series is bccb/bccb/bccb
Thus, the pattern bccb is repeated.
Choose the alternative that will complete the series.
Q. aaa – bb – aab – baaa – bb
The series is aaa/bbb/aaa/bbb/aaa/bbb
Thus, the pattern aaa, bbb is repeated.
Choose the alternative that will complete the series.
Q. Aab – bbaaa – cbba – abc – ba
The series is aabcbba/aabcbba/aabcbba Thus, the pattern aabcbba is repeated.
Choose the alternative that will complete the series.
Q. Adb – ac – da – cddcd – dbc – cbda
The series is adbca/cbdabc/ddcd/adbca/cbda. Here, the letters equidistant from the beginning and the end of the series are the same.
Choose the alternative that will complete the series.
Q. A – abbb – ccccd – ddccc – bb – ba
The series is aaa/bbbb/cccc/dddd/cccc/bbbb/a.
Choose the alternative that will complete the series.
Q. – aba – cabc – dcba – bad – a
The series is aaba/bcabc/ddbac/babaa Thus, the letters equidistant from the beginning and the end of the series are the same.
Choose the alternative that will complete the series.
Q. Sr – tr – srs – r – srst –
The series is tsr/str/tsr/str/tsr/str.
Thus,the pattern tsr/str is repeated.
Choose the alternative that will complete the series.
Q. B – a – aab – ab –
The series is baa/baa/baa/baa. Thus, the pattern baa is repeated.
Choose the alternative that will complete the series.
Q. A – ab – bcbc –caca –
The series is ababc/bcbca/cacab.
Choose the alternative that will complete the series.
Q. 13, 31, 63, 127, 255, …….
Each number is double the preceding one plus 1.
So, the next number is (255 x 2) + 1 = 511.
Choose the alternative that will complete the series.
Q. 2, 6, 12, 20, 30, 42, 56, …?….
The sequence is 1 x 2, 2 x 3, 3 x 4, 4 x´ 5, 5 x 6, 6 x 7, 7 x 8.
∴ Next number = 8 x 9 = 72
Choose the alternative that will complete the series.
Q. 165, 195, 255, 285, 345, …?….
Each number is 15 multiplied by a prime number i.e. 15 x 11, 15 x 13, 15 x 17, 15 x 19, 15 x 23
∴ Missing term = 15 x 29 = 435
Choose the alternative that will complete the series.
Q. 10, 5, 13, 10, 16, 20, 19, …?….
There are two series: 10, 13, 16, 19 and 5, 10, 20, …….
∴ Missing number = 40
Choose the alternative that will complete the series.
Q. 71, 76, 69, 74, 67, 72, …?….
Alternately 5 is added and 7 is subtracted.
Thus, 71, 74 - 7 = 67 and so on
∴ Missing number = 72 - 7 = 65
Choose the alternative that will complete the series.
Q. 3, 15, 35, …?…, 99, 143
The terms of the series are 22 - 1, 42 - 1, 62 - 1, ……, 102 - 1, 122 - 1.
Choose the alternative that will complete the series.
Q. 6, 24, 12, …?…, 18 , 8, 24
The given sequence is a combination of two series 6, 12, 18 24 and 24, ……, 8.
Clearly, the first series consists of consecutive multiples of 6 and the second series consists of multiples of 8. Thus,
∴ Missing number 25 + 4 = 29
Choose the alternative that will complete the series.
Q. 97, 86, 73, 58, 45, …?….
The sequence is -11, -13, -15, -13, ……
∴ Missing number = 45 - 11 = 34
Choose the alternative that will complete the series.
Q. 2, 6, 11, 17, …?…, 32.
The sequence is + 4, + 5, + 6, ……
∴ Missing number = 17 + 7 = 24
Choose the alternative that will complete the series.
Q. 11, 13, 17, 19, 23, 25, …?….
The sequence is + 2, + 4, + 2, + 4, +2, ……
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