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Test: Equilibrium Diagrams & Phase Changes - 1 - Mechanical Engineering MCQ


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10 Questions MCQ Test Topicwise Question Bank for Mechanical Engineering - Test: Equilibrium Diagrams & Phase Changes - 1

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Test: Equilibrium Diagrams & Phase Changes - 1 - Question 1

A material of unknown composition at atmospheric pressure (arbitrarily chosen) exhibit four phase at 987 K, what is the minimum number of components in the system?

Detailed Solution for Test: Equilibrium Diagrams & Phase Changes - 1 - Question 1

Modified form of phase rule, F = C - P + 1
The minimum number of components correspond . - to minimum degrees of freedom, which is zero
∴ 0 = C - 4 + 1 or C = 3

Test: Equilibrium Diagrams & Phase Changes - 1 - Question 2

The percentage of pro-eutectoid ferrite and pearlite in a slowly cooled 0.5% carbon steel is

Detailed Solution for Test: Equilibrium Diagrams & Phase Changes - 1 - Question 2

Let fulcrum is at 0.5% carbon to apply lever rule. % Proeutectoid ferrite

% Pearlite = 100 - 37.5 = 62.5%

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Test: Equilibrium Diagrams & Phase Changes - 1 - Question 3

Microstructure of pearlite is composed of X% ferrite and Y% cementite. The value of X and Y is

Detailed Solution for Test: Equilibrium Diagrams & Phase Changes - 1 - Question 3

Test: Equilibrium Diagrams & Phase Changes - 1 - Question 4

In which of the following phases'of steel cementite is in particle form?

Detailed Solution for Test: Equilibrium Diagrams & Phase Changes - 1 - Question 4

Bainite: When austenite is cooled rapidly past the nose of C-curve and kept isothermally in a constant temperature bath, it transforms to a nonlamellar product known as bainite. It is an extremely fine mixture of ferrite and carbide. Bainite is present in two forms: the feathery bainite obtained in the upper part of temperature range and needie-like or accicular bainite produced by lower reaction temperature.

Test: Equilibrium Diagrams & Phase Changes - 1 - Question 5

In which of the following phases of steel, cementite is in lamellar form?

Detailed Solution for Test: Equilibrium Diagrams & Phase Changes - 1 - Question 5

Pearlite phase in steel is made up of alternate layers of ferrite and cementite.

Test: Equilibrium Diagrams & Phase Changes - 1 - Question 6

The maximum number of co-existing phases in a C- system is

Test: Equilibrium Diagrams & Phase Changes - 1 - Question 7

Hardness of martensite is about

Detailed Solution for Test: Equilibrium Diagrams & Phase Changes - 1 - Question 7

0.2% C Martensite →50 RC
0.4% C Martensite →58 RC
0.8% C Martensite→ 65 RC

Test: Equilibrium Diagrams & Phase Changes - 1 - Question 8

Hardness of steel depends

Detailed Solution for Test: Equilibrium Diagrams & Phase Changes - 1 - Question 8

Increasing the carbon content in steel alloys causes the material to become harder. This is because the carbon sits in the interstitial sites of the lattice structure and hinders the movement of dislocation lines. It also increases the strength of the material but it decreases the ductility, carbide is hard phase,

Test: Equilibrium Diagrams & Phase Changes - 1 - Question 9

The reaction that on heating one solid phase yields another solid phase together with one liquid phase is termed

Test: Equilibrium Diagrams & Phase Changes - 1 - Question 10

Eutectic product in Fe-C system is called

Detailed Solution for Test: Equilibrium Diagrams & Phase Changes - 1 - Question 10

A eutectic reaction occurs at 1146°C

On cooling through the eutectic temperature, the lowest melting liquid of the system decomposes to solid phases, austenite and cementite. This eutectic mixture is knonw as ledeburite.

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