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QUESTION: 1

Three identical pipes of length L, diameter D and friction factor f, are connected in parallel between two reservoirs. The size of a pipe of length L and of same friction factor f, equivalent to the above pipes, is

Solution:

Equivalent pipe for the pipes in parallel:

or

or D_{e} = 1.5518 D

QUESTION: 2

A pipe of diameter D is to be replaced by n pipe each of diameter of laid in parallel. The value of d is given by

Solution:

or D^{5} = n^{2}d^{5}

or D = n^{2/5} D

∴ d = (D/n^{2/5})

QUESTION: 3

At a sudden expansion in a horizontal pipe

Solution:

QUESTION: 4

In a pipeline, the H.G.L is above the pipe center line in the longitudinal section at point A and below the pipe center line at another point B.

From this it can be inferred that

Solution:

QUESTION: 5

In network of pipes

Solution:

QUESTION: 6

Consider the following statements:

1. Pipe network analysis is normally necessary in analyzing flow in pipes at city water systems,

2. Hardy-cross method of solving pipe network is a method of successive approximations and is not a direct method.

3. The network must satisfy the momentum equation because the flow in each pipe satisfies the head loss equation.

4. Principle of continuity is satisfied in a pipe network..

Select the correct statments:

Solution:

QUESTION: 7

The diameter of the nozzle (d) for maximum transmission of power is given by

Where

D = Diameter of pipe

f = Darcy’s friction factor

l = Length of pipe

Solution:

For maximum power transmission through nozzle:

Nozzle diameter

A = area of supply pipe

a = area of Nozzle

QUESTION: 8

Maximum efficiency of transmission of power through a pipe is

Solution:

Efficiency of power transmission is given by

For maximum efficiency

We get

QUESTION: 9

Power transmitted through a pipe is maximum when

Where

H = total head supplied

H_{L} = head loss due to friction

Solution:

For maximum power transmission

QUESTION: 10

Power transmitted through a pipe is given by

where

w = specific weight of the fluid flowing through pipe

Q = discharge, m^{3}/s

Solution:

Power transmitted through a pipe (When H_{L} is frictional head)

P = wQ(H - H_{L})

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