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Mechanical Engineering Exam  >  Mechanical Engineering Tests  >  Topicwise Question Bank for Mechanical Engineering  >  Test: Velocity & Acceleration Analysis - 3 - Mechanical Engineering MCQ

Test: Velocity & Acceleration Analysis - 3 - Mechanical Engineering MCQ


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10 Questions MCQ Test Topicwise Question Bank for Mechanical Engineering - Test: Velocity & Acceleration Analysis - 3

Test: Velocity & Acceleration Analysis - 3 for Mechanical Engineering 2024 is part of Topicwise Question Bank for Mechanical Engineering preparation. The Test: Velocity & Acceleration Analysis - 3 questions and answers have been prepared according to the Mechanical Engineering exam syllabus.The Test: Velocity & Acceleration Analysis - 3 MCQs are made for Mechanical Engineering 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Velocity & Acceleration Analysis - 3 below.
Solutions of Test: Velocity & Acceleration Analysis - 3 questions in English are available as part of our Topicwise Question Bank for Mechanical Engineering for Mechanical Engineering & Test: Velocity & Acceleration Analysis - 3 solutions in Hindi for Topicwise Question Bank for Mechanical Engineering course. Download more important topics, notes, lectures and mock test series for Mechanical Engineering Exam by signing up for free. Attempt Test: Velocity & Acceleration Analysis - 3 | 10 questions in 30 minutes | Mock test for Mechanical Engineering preparation | Free important questions MCQ to study Topicwise Question Bank for Mechanical Engineering for Mechanical Engineering Exam | Download free PDF with solutions
Test: Velocity & Acceleration Analysis - 3 - Question 1
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Consider a four-bar mechanism shown in the given figure. The driving link DA is rotation uniformly at a speed of 100 rpm clockwise

Q. The velocity of A will be

Detailed Solution for Test: Velocity & Acceleration Analysis - 3 - Question 1


V = rω

Test: Velocity & Acceleration Analysis - 3 - Question 2
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The directions of Coriolis component of acceleration, 2 ωV, of the slider A with respect to the coincident point B is shown in figure 1,2, 3 and 4. Directions shown by figures

Detailed Solution for Test: Velocity & Acceleration Analysis - 3 - Question 2

fcor = 2Vω
2 and 4 are wrong according to above equation. These should be as show below.

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Test: Velocity & Acceleration Analysis - 3 - Question 3
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In the figure shown, the relative velocity of link 1 with respect of link 2 is 12 m/sec. Link 2 rotates at a constant speed of 120 rpm. The magnitude of Coriolis component of acceleration of link 1 is

Detailed Solution for Test: Velocity & Acceleration Analysis - 3 - Question 3

Velocity of link 1 with respect to 2

∴ Coriolis component of acceleration

Test: Velocity & Acceleration Analysis - 3 - Question 4
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The number of links in a planer mechanism with revolute joints having 10 instantaneous centre is
Detailed Solution for Test: Velocity & Acceleration Analysis - 3 - Question 4

Number of instantaneous centre

for n = 5
we get Number of instantaneous centre = 10

Test: Velocity & Acceleration Analysis - 3 - Question 5
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The figure below shows a planer mechanism with single degree of freedom. The instant center 24 for the given configuration in located at a position
Test: Velocity & Acceleration Analysis - 3 - Question 6
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Figure shows a quick return mechanism. The crank OA rotates clockwise uniformly.

OA = 2 cm; OO' = 4 cm
Q. The ratio of time for forward motion to that for return motion is
Detailed Solution for Test: Velocity & Acceleration Analysis - 3 - Question 6


sin α = 2/4
α = 30°
∴ β = 60°

Test: Velocity & Acceleration Analysis - 3 - Question 7
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A slider sliding at 10 cm/s on a link which is rotating at 60 rpm is subjected to Coriolis acceleration of magnitude
Detailed Solution for Test: Velocity & Acceleration Analysis - 3 - Question 7

Coriolis acceleration

Test: Velocity & Acceleration Analysis - 3 - Question 8
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In the figure given the link 2 rotates at an angular velocity of 2 rad/s. What is the magnitude of Coriolis acceleration experienced by the link 4?
Detailed Solution for Test: Velocity & Acceleration Analysis - 3 - Question 8

Since link 2 and link 3 are perpendicular each other
ω = 0
∴ fcor = 0

Test: Velocity & Acceleration Analysis - 3 - Question 9
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A simple quick return mechanism is shown in the figure. The forward to return ratio of the quick return mechanism is 2 : 1. If the radius of the crank O1P is 125 mm, then the distance ‘of’ (in mm) between the crank centre to lever pivot centre point should be
Detailed Solution for Test: Velocity & Acceleration Analysis - 3 - Question 9



O1P = 125mm
Quick return mechanism


The extreme position of the crank (O1P) are shown in figure.
From right angle triangle O2O1P1, we find that

Test: Velocity & Acceleration Analysis - 3 - Question 10
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For the configuration shown, the angular velocity of link AB is 10 rad/s counter clockwise. The magnitude of the relative sliding velocity (in ms-1) of slider B with respect to rigid link CD is
Detailed Solution for Test: Velocity & Acceleration Analysis - 3 - Question 10

As AB is perpendicular to slider for given condition, so sliding velocity of slider equals to velocity of link AB
= ω x AB = 10 x 0.25
= 2.5 m/s

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