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This mock test of Circuit Theorems - 1 for Electrical Engineering (EE) helps you for every Electrical Engineering (EE) entrance exam.
This contains 10 Multiple Choice Questions for Electrical Engineering (EE) Circuit Theorems - 1 (mcq) to study with solutions a complete question bank.
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QUESTION: 1

Superposition theorem is applicable only to network that are

Solution:

QUESTION: 2

In any lumped network with elements in b branches for all holds good according to

Solution:

means the total sum of instantenous power consumed in various elements in the branches of a network is zero, which is the statement of Tellegen’s theorem.

QUESTION: 3

The Theven's equivalent resistance to the left of AB in figure given below is given by

Solution:

For finding the Thevenin’s equivalent resistance, 8 A current source will be open circuited while v volt voltage source will be short circuited.

Hence,

QUESTION: 4

For which of the following, Thevenin’s and Norton’s equivalents can’t be developed?

Solution:

QUESTION: 5

The value of Z_{22} (Ω) for the circuit shown below is

Solution:

Applying KVL, we get

Putting the value of V_{1} from equation (ii) into equation (i), we get

QUESTION: 6

In which of the following it is not desired to attain the condition of maximum power transfer?

Solution:

QUESTION: 7

A simple equivalent circuit of the two terminal network shown in figure below is

Solution:

For the given circuit, R_{eq} across the given terminals = R.

QUESTION: 8

For the circuit shown below, a resistance R is to be connected across an active network, it is given that when

(i) R =∞, V = 5 volts

(ii) R = 0, current output of the active source is 2.5 A.

What would be the current through tfwhen the value of R is 5 Ω?

Solution:

When R = ∞, V_{oc}= V = 5 volts

When R = 0 , I_{SC} = 2 .5 A

Hence, the Thevenin's equivalent circuit will be drawn as shown below.

QUESTION: 9

A generator of internal impedance I Z_{g}I delivers maximum power to a load impedance Z_{p} , only if

Solution:

QUESTION: 10

In the circuit shown below, the current through the 5Ω resistor is

Solution:

An ideal voltage source is never short circuited. Hence, we should not use superposition theorem. The voltage across the 5Ω resistor will be 10 volts. Hence, current through the 5 Ω resistor

=10/5 = 2 A

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