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# Second Order RLC Circuits - 1

## 10 Questions MCQ Test Topicwise Question Bank for Electrical Engineering | Second Order RLC Circuits - 1

Description
This mock test of Second Order RLC Circuits - 1 for Electrical Engineering (EE) helps you for every Electrical Engineering (EE) entrance exam. This contains 10 Multiple Choice Questions for Electrical Engineering (EE) Second Order RLC Circuits - 1 (mcq) to study with solutions a complete question bank. The solved questions answers in this Second Order RLC Circuits - 1 quiz give you a good mix of easy questions and tough questions. Electrical Engineering (EE) students definitely take this Second Order RLC Circuits - 1 exercise for a better result in the exam. You can find other Second Order RLC Circuits - 1 extra questions, long questions & short questions for Electrical Engineering (EE) on EduRev as well by searching above.
QUESTION: 1

Solution:

QUESTION: 2

Solution:
QUESTION: 3

### For the parallel RLC circuit to be underdamped

Solution:

Characteristic equation of a parallel RLC circuit is

QUESTION: 4

For the circuit shown below, the switch K is closed at t = 0,

The value of the current and their derivatives for the above circuit at t = 0 were foundout and matched as given below:

Which of the above are correctly matched ?

Solution:

At t = 0+, inductor will act as open circuit therefore, i(0+) = 0 A.
Applying KVL in the loop, we have

QUESTION: 5

The energy in a network in Laplace domain is given by

​The initial and final values of power are respectively

Solution:

We know that,

QUESTION: 6

A voltage is given by

The value of V(t→ ∞) is

Solution:

QUESTION: 7

The voltage across a capacitor is given by

If the capacitor has the value of 2 F, initial value of current through it (at t = 0+) will be

Solution:

Hence, initial value of current through the capacitor = 2 A.

QUESTION: 8

The impedance Z(s) in the circuit shown below is

Solution:

The given circuit in Laplace domain is shown below.

QUESTION: 9

The voltage Vc1,Vc2 and Vc3 across the capacitors in the circuit shown below under steady-state, are respectively

Solution:

Under steady state condition inductors will act as short circuit while capacitors will act as open circuit.

QUESTION: 10

The value of Z(s) in the circuit shown below is given by

The values of R, L and Care respectively given by

Solution:

On comparing the two values of Z(s), we get