Test: Basic Nodal & Mesh Analysis - 1

# Test: Basic Nodal & Mesh Analysis - 1

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## 10 Questions MCQ Test GATE Electrical Engineering (EE) 2023 Mock Test Series | Test: Basic Nodal & Mesh Analysis - 1

Test: Basic Nodal & Mesh Analysis - 1 for Electrical Engineering (EE) 2023 is part of GATE Electrical Engineering (EE) 2023 Mock Test Series preparation. The Test: Basic Nodal & Mesh Analysis - 1 questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: Basic Nodal & Mesh Analysis - 1 MCQs are made for Electrical Engineering (EE) 2023 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Basic Nodal & Mesh Analysis - 1 below.
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Test: Basic Nodal & Mesh Analysis - 1 - Question 1

### Of the two methods of loop and node variable analysis

Test: Basic Nodal & Mesh Analysis - 1 - Question 2

### Which of the following is ​​​​true about the circuit shown below? Detailed Solution for Test: Basic Nodal & Mesh Analysis - 1 - Question 2

Number of junction point for the given circuit is 6.

Test: Basic Nodal & Mesh Analysis - 1 - Question 3

### For the circuit shown below, the current through the 1 Ω resistor is Detailed Solution for Test: Basic Nodal & Mesh Analysis - 1 - Question 3

Using source transformation, the current source is converted to a voltage source as shown below. Applying nodal analysis at node (x), we get Test: Basic Nodal & Mesh Analysis - 1 - Question 4

An electric circuit with 8 branches and 4 nodes will have

Detailed Solution for Test: Basic Nodal & Mesh Analysis - 1 - Question 4

Number of loop equation
= b - ( n - 1)
= 8 - ( 4 - 1 )
= 8 - 3 = 5

Test: Basic Nodal & Mesh Analysis - 1 - Question 5

For the circuit shown below, the current through the 10 V battery is Detailed Solution for Test: Basic Nodal & Mesh Analysis - 1 - Question 5

Using source transformation, first we convert the current source into an equivalent voltage source Applying KVL in loop-1, we get Applying KVL in loop-2, we get On solving equations (i) and (//). we get

i1 = 2.36 A and i2 = 4.91 A

Hence, the current through the battery of 10 V is

i2 = 4.91 A

Test: Basic Nodal & Mesh Analysis - 1 - Question 6

Find the value of the currents I1 and I2 flowing clockwise in the first and second mesh respectively. Detailed Solution for Test: Basic Nodal & Mesh Analysis - 1 - Question 6

The two mesh equations are:
5I1 - 3I2 = 10
-3I1 + 7I2 = -15
Solving the equations simultaneously, we get I1 = 0.96A and I2 = -1.73A.

Test: Basic Nodal & Mesh Analysis - 1 - Question 7

The value of V in volts for the circuit shown below is Detailed Solution for Test: Basic Nodal & Mesh Analysis - 1 - Question 7

The equivalent resistance across the 5 A current source is Test: Basic Nodal & Mesh Analysis - 1 - Question 8

The number of KVL and KCL equations for the circuit shown below are Detailed Solution for Test: Basic Nodal & Mesh Analysis - 1 - Question 8

Number of nodes, n = 5
Number of branchs, b = 6
Hence, number of KCL equation
= n - 1 = 5 - 1 = 4
and, number of KVL equations = b - ( n - 1)
= 6 - (5-1) = 6- 4 = 2

Test: Basic Nodal & Mesh Analysis - 1 - Question 9

The current l flowing in the given figure is Test: Basic Nodal & Mesh Analysis - 1 - Question 10

The value of dependent source for the circuit shown below is Detailed Solution for Test: Basic Nodal & Mesh Analysis - 1 - Question 10

Applying KVL in the loop,
5 = 2i — 2i + i or i = 5 A
∴ Value of dependent source
= 2i = 2 x 5 = 10 volt

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