1 Crore+ students have signed up on EduRev. Have you? |
Which of the following is not true relating to an ideal transformer?
In an ideal transformer there is no-loss (either in winding or core). The leakage reactance is also zero (as no-voltage drop).
Magnetizing current is zero due to infinite permeability of core.
The emf per turn of a single phase 10 kVA, 2200/220 V, 50 Hz transformer is 10 V. The net cross-sectional area of core for a maximum flux density of 1.5 T is
Maximum flux,
∴ New cross-sectional area of core,
A 1 kVA, 400 Hz transformer is desired to be used at a frequency of 60 Hz. The kVA rating of the transformer at this reduced frequency is
kVA rating of transformer,
or,
Since V ∝ f, therefore, S ∝ f
∴
A 2200 / 250 V transformer takes 0.5 A at a p.f. of 0.3 on open-circuit. The magnetising component of no-load primary current is
A 50 MVA, 76.2/33 kV, 1-φ, 50 Hz, two-winding transformer with tap changer has percentage impedance of (0.5 + j7.0). What tapping must be used to maintain rated voltage at the secondary on full load at 0.8 lagging power factor?
Hence, voltage to be raised, for maintaining rated voltage = 4.6%.
Thus, tap setting required on the HV side = -4.6% or 4.6 % down.
The ohmic drop of a transformer is 1% while the reactance drop is 5% of the voltage. The regulation of the transformer at 0.8 power factor leading and 0.8 power factor lagging are respectively
A 1 kV, 50 Hz supply to a transformer results in 650 W hysteresis loss and 400 W eddy current loss. If both the applied voltage and frequency are doubled, the new core loss would be
A transformer designed for operation of 60 Hz supply is working on 50 Hz supply system without changing its voltage and current ratings. When compared with full-load efficiency at 60 Hz, the transformer efficiency on full load at 50 Hz will
We know that, eddy current loss and hysteresis loss,
When V - constant, Pe = constant
and
When frequency is increased from 50 Hz to 60 Hz, Ph will increase. Thus, core loss will increase marginally, therefore efficiency will decrease marginally.
For a core-type power transformers, both primary and secondary windings have circular coil sections, because this section
Primary and secondary windings of a core type transformer have circular coil section to reduce the mean length of each turn so that it require minimum conductor material and thus have less copper loss which will increase the efficiency.
A 10 kVA, 400 V/ 200 V, 1 -phase transformer with a percentage resistance of 3% and percentage reactance of 6% is supplying a current of 50 A to a resistive load. The value of the load voltage is
Hence, load voltage = 194 volt
22 docs|274 tests
|
Use Code STAYHOME200 and get INR 200 additional OFF
|
Use Coupon Code |
22 docs|274 tests
|
|
|
|
|
|
|
|
|
|