Test: Principal Stress & Strain - 1 - Civil Engineering (CE) MCQ

# Test: Principal Stress & Strain - 1 - Civil Engineering (CE) MCQ

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## 10 Questions MCQ Test GATE Civil Engineering (CE) 2025 Mock Test Series - Test: Principal Stress & Strain - 1

Test: Principal Stress & Strain - 1 for Civil Engineering (CE) 2024 is part of GATE Civil Engineering (CE) 2025 Mock Test Series preparation. The Test: Principal Stress & Strain - 1 questions and answers have been prepared according to the Civil Engineering (CE) exam syllabus.The Test: Principal Stress & Strain - 1 MCQs are made for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Principal Stress & Strain - 1 below.
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Test: Principal Stress & Strain - 1 - Question 1

### The state of stress at a point in a loaded member is shown in figure. The magnitude of maximum shear stress is

Detailed Solution for Test: Principal Stress & Strain - 1 - Question 1

Test: Principal Stress & Strain - 1 - Question 2

### At a point in a strained body carrying two unequal unlike principal stresses p1 and p2 (p1 > p2), the maximum shear stress is given by

Detailed Solution for Test: Principal Stress & Strain - 1 - Question 2

The maximum shear stress is given by,

Now, σ1 = +p1
σ2 = -p2
∴

Test: Principal Stress & Strain - 1 - Question 3

### The radius of Mohr’s circle of stress of a strained element is 20 N/mm2 and minor principal tensile stress is 10 N/mm2; The major principal stress is

Detailed Solution for Test: Principal Stress & Strain - 1 - Question 3

Minor principal stress = C - r = 10
Centre of circle (C) = 10 + 20 =30 N/mm2
Major principal stress = C + r = 30 + 20 = 50 N/mm2

Test: Principal Stress & Strain - 1 - Question 4

The principal stresses σ1 , σ2  and σ3 at a point respectively are 80 MPa, 30 MPa and -40 MPa. The maximum shear stress is

Detailed Solution for Test: Principal Stress & Strain - 1 - Question 4

∴

Test: Principal Stress & Strain - 1 - Question 5

Plane stress at a point in a body is defined by principal stress 3σ and σ. The ratio of the normal stress to the maximum shear stress on the plane of maximum shear stress is

Detailed Solution for Test: Principal Stress & Strain - 1 - Question 5

∴

Test: Principal Stress & Strain - 1 - Question 6

A shaft subjected to torsion experiences a pure shear stress τ on the surface. The maximum principal stress on the surface which is at 45° to the axis will have a value

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Test: Principal Stress & Strain - 1 - Question 7

Principal strains at a point are 100 x 10-6 and -200 x 10-6. What is the maximum shear strain at the point?

Detailed Solution for Test: Principal Stress & Strain - 1 - Question 7

= 300 x 10-6  /  2
∴  φmax = 150 x 10-6

Test: Principal Stress & Strain - 1 - Question 8

In a plane stress problem there are normal tensile stresses σx and σy accompanied by shear stress τxy at a point along orthogonal Cartesian coordinates x and y respectively. If it is observed that the minimum principal stress on a certain plane is zero the

Detailed Solution for Test: Principal Stress & Strain - 1 - Question 8

Principal stresses,

Since minimum principal stress is zero, therefore

Test: Principal Stress & Strain - 1 - Question 9

A point in a strained body is subjected to a tensile stress of 100 MPa on one plane and a tensile stress of 50 MPa on a plane at right angle to it. If these planes are carrying shear stresses of 50 MPa, then the principal stresses are inclined to the larger normal stress at an angle of

Detailed Solution for Test: Principal Stress & Strain - 1 - Question 9

The angle of inclination of principal stress to the larger normal stress is given by,

⇒ 2θ = tan-1(2)
∴

Test: Principal Stress & Strain - 1 - Question 10

If the normal cross-section A of a member is subjected to a tensile force P, the resulting normal stress on an oblique plane inclined at angle θ to transverse plane will be

Detailed Solution for Test: Principal Stress & Strain - 1 - Question 10

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## GATE Civil Engineering (CE) 2025 Mock Test Series

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