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Test: Semiconductor Memories - 1 - Electronics and Communication Engineering (ECE) MCQ


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10 Questions MCQ Test Topicwise Question Bank for Electronics Engineering - Test: Semiconductor Memories - 1

Test: Semiconductor Memories - 1 for Electronics and Communication Engineering (ECE) 2024 is part of Topicwise Question Bank for Electronics Engineering preparation. The Test: Semiconductor Memories - 1 questions and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus.The Test: Semiconductor Memories - 1 MCQs are made for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Semiconductor Memories - 1 below.
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Test: Semiconductor Memories - 1 - Question 1

In a DRAM

Detailed Solution for Test: Semiconductor Memories - 1 - Question 1

DRAM:

  •  In a DRAM, a capacitor to store a bit of data is used along with a MOSFET (transfer device) which acts as a switch.
  • It requires only one transistor to store one-bit data whereas SRAM requires 6 transistors.
  • The information is stored in a capacitor.
  • Both read and write operations cannot be performed simultaneously.
  • To store one bit of data, DRAM needs one transistor and one capacitor.
  • Since the capacitor stores the data in the form of charge.
  • To keep the charge stored for a long duration, the capacitor needs to constantly be refreshed. So DRAM is slower and used for main memory.

 

Test: Semiconductor Memories - 1 - Question 2

Each NIC card is assigned a unique ________ that is burned into _________.

Detailed Solution for Test: Semiconductor Memories - 1 - Question 2

1. NIC is used to connect a computer to an Ethernet network.
2.The card usually contains the protocol control firmware and the Ethernet controller needed to support Medium Access control (MAC).
3. A MAC address is given to a network adapter. It is a hardware into the computer Network interface card (NIC) and is also unique.
4. It is a six-byte or 48-bit address that uniquely identifies the Ethernet-based connection.

Test: Semiconductor Memories - 1 - Question 3

Consider a memory chip with 24 address pins and 16 data pins. How many locations will it accommodate?

Detailed Solution for Test: Semiconductor Memories - 1 - Question 3

Concept:

Memory Chips:

  • The number of address pins is related to the number of memory locations.
  • The data pins are typically bi-directional in read-write memories. The number of data pins is related to the size of the memory location.

Given that, 

Address pins= 24 (is related to the number of memory locations)

Data pins= 16 (It is related to the size of the memory location)

So For 'N-Bits' address pins, the number of locations that will accommodate is 2N.

So For '24-Bits' address pins, the number of locations that will accommodate is 224.

Hence the correct answer is 224.

Test: Semiconductor Memories - 1 - Question 4

The storage capacity of a SONY pen drive is 16 GB. Here what does G mean in 16 GB?

Detailed Solution for Test: Semiconductor Memories - 1 - Question 4

The conversion of memory is given below.

1 TB = 1024 GB

1 GB = 1024 MB

1 MB = 1024 kB

1 kB = 1024 Byte

1 Byte = 8 bits

Test: Semiconductor Memories - 1 - Question 5

Both EPROM and EEPROM are

Detailed Solution for Test: Semiconductor Memories - 1 - Question 5

Concept:

  • EPROM and EEPROM is a type of ROM.
  • Data in ROM can be accessed randomly and hence EPROM and EEPROM are random access memory.

Important Points:

  • EPROM is an erasable programmable read-only memory.
  • It is a non-volatile memory that means its data will be retained even when the power is turned off.
  • EEPROM (electrically erasable programmable read-only memory) is a user-modifiable read-only memory (ROM) that can be erased and reprogrammed (written to) repeatedly through the application of higher than normal electrical voltage.
Test: Semiconductor Memories - 1 - Question 6

In a DRAM,

Detailed Solution for Test: Semiconductor Memories - 1 - Question 6

In a DRAM, a capacitor to store a bit of data is used along with a MOSFET (transfer device) which acts as a switch. The circuit is as shown –

In a DRAM:

  • Periodic refreshing is required.
  • The information is stored in a capacitor.
  • Both read and write operations cannot be performed simultaneously.
Test: Semiconductor Memories - 1 - Question 7

What are the advantages of a programmable logic device (PLD) over fixed-function ICs?

1. Reduction in board space requirement.

2. Reduction in power requirement.

3. Design security.

Detailed Solution for Test: Semiconductor Memories - 1 - Question 7

Programmable logic device (PLD):

It is an IC with a large number of logic gates, which is programmed by software to perform a specific digital logic function. And it can be changed according to the application.

Examples: PLA, PAL, FPLA, PROM, GAL, FPGA, etc.

Fixed functional ICS:

It is an ICs in a compact form that is designed to perform for fixed logic applications and it can not be changed after manufacture.

Examples: IC-555, IC-741, Johnson counter, full adder, parallel adder, etc.

Advantages of PLD over fixed functional ICs:

So, the correct option is D.

Test: Semiconductor Memories - 1 - Question 8

How many address inputs are required to access 256 Bytes memory?

Detailed Solution for Test: Semiconductor Memories - 1 - Question 8

Concept:

Address line: An address line is basically refers to a physical connection between a CPU/Chipset and memory. They specify which addresses to access in memory. When there are k address lines, then 2k memory word can be accessed.

Data line: Data lines provides the information to be stored in memory. It represents the number of bits in the word.

Calculation:

Here, it is given that memory unit size = 256 bytes

2k = 256

k = 8

Test: Semiconductor Memories - 1 - Question 9

How many bits are in a byte?

Detailed Solution for Test: Semiconductor Memories - 1 - Question 9

1. A bit is the smallest unit of storage.
2. A bit stores just a 0 or 1.
3. Computers are designed to store data and execute instructions in bit multiples called bytes.
4. One byte is equal to 8 bits.

Test: Semiconductor Memories - 1 - Question 10

EPROM is generally erased by using

Detailed Solution for Test: Semiconductor Memories - 1 - Question 10

EPROM (Erasable programmable read-only memory):

  • EPROM stands for erasable programmable read-only memory.
  • EPROM is a nonvolatile kind of memory.
  • If ultraviolet rays are exposing (Mercury –vapor light) to the EPROM chip, then this chip will release stored charge. The stored content in that EPROM chip will be lost or erased.

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