Description

This mock test of Arun Sharma Test: HCF & LCM for UPSC helps you for every UPSC entrance exam.
This contains 10 Multiple Choice Questions for UPSC Arun Sharma Test: HCF & LCM (mcq) to study with solutions a complete question bank.
The solved questions answers in this Arun Sharma Test: HCF & LCM quiz give you a good mix of easy questions and tough questions. UPSC
students definitely take this Arun Sharma Test: HCF & LCM exercise for a better result in the exam. You can find other Arun Sharma Test: HCF & LCM extra questions,
long questions & short questions for UPSC on EduRev as well by searching above.

QUESTION: 1

Find the lowest common multiple of 24, 36 and 40.

Solution:

QUESTION: 2

The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is:

Solution:

QUESTION: 3

Solution:

QUESTION: 4

The least number which when divided by 5, 6 , 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is:

Solution:

QUESTION: 5

A, B and C start at the same time in the same direction to run around a circular stadium. A completes a round in 252 seconds, B in 308 seconds and c in 198 seconds, all starting at the same point. After what time will they again at the starting point ?

Solution:

L.C.M. of 252, 308 and 198 = 2772.

So, A, B and C will again meet at the starting point in 2772 sec. *i.e.,* 46 min. 12 sec.

QUESTION: 6

The H.C.F. of two numbers is 11 and their L.C.M. is 7700. If one of the numbers is 275, then the other is:

Solution:

QUESTION: 7

What will be the least number which when doubled will be exactly divisible by 12, 18, 21 and 30 ?

Solution:

QUESTION: 8

The ratio of two numbers is 3 : 4 and their H.C.F. is 4. Their L.C.M. is:

Solution:

Let the numbers be 3*x* and 4*x*. Then, their H.C.F. = *x*. So, *x* = 4.

So, the numbers 12 and 16.

L.C.M. of 12 and 16 = 48.

QUESTION: 9

The smallest number which when diminished by 7, is divisible 12, 16, 18, 21 and 28 is:

Solution:

Required number = (L.C.M. of 12,16, 18, 21, 28) + 7

= 1008 + 7

= 1015

QUESTION: 10

252 can be expressed as a product of primes as:

Solution:

Clearly, 252 = 2 x 2 x 3 x 3 x 7.

### HCF & LCM: Worksheet

Doc | 1 Page

### HCF & LCM - Basics

Video | 30:12 min

### HCF & LCM: Notes

Doc | 18 Pages

### HCF & LCM Questions

Doc | 3 Pages

- Arun Sharma Test: HCF & LCM
Test | 10 questions | 10 min

- Practice Test: HCF & LCM
Test | 10 questions | 10 min

- Olympiad Test: LCM And HCF - 1
Test | 20 questions | 40 min

- HCF And LCM - MCQ 1
Test | 10 questions | 20 min

- HCF And LCM - MCQ 2
Test | 20 questions | 15 min