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Important Questions Test: Ratio & Proportion- 2 - UPSC MCQ


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15 Questions MCQ Test CSAT Preparation - Important Questions Test: Ratio & Proportion- 2

Important Questions Test: Ratio & Proportion- 2 for UPSC 2024 is part of CSAT Preparation preparation. The Important Questions Test: Ratio & Proportion- 2 questions and answers have been prepared according to the UPSC exam syllabus.The Important Questions Test: Ratio & Proportion- 2 MCQs are made for UPSC 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Important Questions Test: Ratio & Proportion- 2 below.
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Important Questions Test: Ratio & Proportion- 2 - Question 1

What is the angle in degrees made by a sector, the ratio of whose area with the area of the semicircle is equal to 1:10?

Detailed Solution for Important Questions Test: Ratio & Proportion- 2 - Question 1

Area of semicircle = (1/2)πr2
Area of sector = (θ/360)πr2

Important Questions Test: Ratio & Proportion- 2 - Question 2

The value of a diamond varies directly as the square of its weight. If a diamond worth Rs 10,000 is divided into 2 pieces in the ratio of 4:6, what is the loss in value?

Detailed Solution for Important Questions Test: Ratio & Proportion- 2 - Question 2

V ∝ W2, V = KW2
Where, V = Value of diamond, W = weight of diamond and K = constant
⇒ 10000 = K.(10)2
⇒ K = 100
Hence, V = 100 x 42 = 1600
also, V = 100 x 62 = 3600
Net loss = Rs.(10000 - 5200) = Rs 4800 i.e., 48%

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Important Questions Test: Ratio & Proportion- 2 - Question 3

The first, second and third class fares between two railway stations, Patna and Lucknow were 10:8:3 and the number of first, second and third class passengers between the two stations was is 3:4:10. If total sales of the ticket is Rs 16,100, find the money obtained by the sales of second class tickets.

Detailed Solution for Important Questions Test: Ratio & Proportion- 2 - Question 3

► Let the fare of 1st, 2nd and 3rd class be 10x, 8x, and 3x respectively.
► Let the no. of passengers of 1st, 2nd and 3rd class be 3y, 4y and 10y respectively. 
Then 30xy + 32xy + 30xy = 16100
⇒ 92xy = 16100
Hence xy = 175
Required amount = 32xy = 32 x 175 = 5600 

Important Questions Test: Ratio & Proportion- 2 - Question 4

Two horses cost as much as 5 dogs, 6 dogs as much as 8 oxen, 10 oxen as much as 50 sheep, 14 sheep as much as 9 goats. If the price of one goat is Rs 70, how much will one horse cost?

Detailed Solution for Important Questions Test: Ratio & Proportion- 2 - Question 4

► Price of one goat = Rs 70 ⇒ Price of 9 goats = 9 x 70 = Rs 630
► Price of 14 sheeps = Rs 630 
⇒ Price of 1 sheep = Rs 630/14 = Rs 45 ⇒ Price of 50 sheep = Rs 45 x 50 = Rs 2250
► Price of 10 oxen = 2250 ⇒ Price of 1 oxen = 225 ⇒ Price of 8 oxen  = 1800
► Price of 6 dogs = 1800 ⇒ Price of 1 dog = 300 ⇒ Price of 5 dog = 1500
► Price of two horses = 1500 ⇒ Price of one horse = 750

Important Questions Test: Ratio & Proportion- 2 - Question 5

A is proportional to B. B is inversely proportional to C. C is proportional to the square of D. D is directly proportional to the cube root of E. Assuming positive integers, if A increases then E

Detailed Solution for Important Questions Test: Ratio & Proportion- 2 - Question 5

Given,
B
B ∝ (1/C)
C ∝ D2
∛E
When A increases ⇒ B also increases ⇒ C decreases
Decrease in C results in decrease in D and decrease in D results decrease in E.

Important Questions Test: Ratio & Proportion- 2 - Question 6

The sum of four numbers is 253. The ratio of the first number to the second number is 2:3. The ratio of the second number to the third number is 5:6. The ratio of the third number to the fourth number is 8:9. What is the average of the second number and the third number?

Detailed Solution for Important Questions Test: Ratio & Proportion- 2 - Question 6

► Let the 1stno. = A = x
2nd no.= B , 3rd no.= C , 4th no. = D
► A:B = 2:3
    A/B = 2/3
    x/B = 2/3
    B = 3x/2
► B:C = 5:6
    (3x/2)/C = 5/6
    C = (6*3x)/2*5 = 9x/5
    C = 9x/5
► C:D = 8:9
    9x/5/D = 8/9
    D = (9x*9)/8*5 = 81x/40
    D = 81x/40
► A + B + C + D = 253. (Given)
    ⇒ x + 3x/2 + 9x/5 + 81x/40 = 253
    ⇒ (40x+ 60x+ 72x+81x)/40 = 253
    ⇒ 253x = 253*40
    ⇒ X = (253*40)/253 = 40
    ⇒ 1st no.(A) = X = 40
    ⇒ 2nd no.(B) = 3x/2 =( 3 × 40)/2 = 60
    ⇒ 3rd no.(C) = 9x/5 = (9×40)/5 = 72
    ⇒ 4th no.(D) = 81x/40 =( 81×40/)/40 = 81
► Average of numbers = sum of observations/ total no.of observations
► Average of 2nd no. & 3rd no.= (60+72)/2 = 132/2 = 66

Important Questions Test: Ratio & Proportion- 2 - Question 7

A man has rs.480 in the denominations of one-rupee notes, five-rupee notes and ten-rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has ?

Detailed Solution for Important Questions Test: Ratio & Proportion- 2 - Question 7

► Given that a man has Rs. 480 in the denominations of one-rupee notes, five-rupee notes and ten-rupee notes. The number of notes of each denomination is equal.
► We are to find the total number of notes he has.
► Let x represents the number of notes of each of the three denominations.
► Then, according to the given information, we have
⇒ 1.x + 5.x + 10.x = 480
⇒ x + 5x + 10x = 480
⇒ 16x = 480
⇒ x = 30
► Therefore, the total number of notes is given by 
⇒ x + x + x = 3x = 3*30 = 90

Important Questions Test: Ratio & Proportion- 2 - Question 8

Three friends A, B and C started a venture with capitals in the ratio of 4:1:15. At the end of every quarter A halves his capital, while B doubles his capital and C leaves his capital untouched. This process is repeated till the end of the year. If at the end of the year B ’ s share of the profit is Rs 22,000, what is the total profit?

Detailed Solution for Important Questions Test: Ratio & Proportion- 2 - Question 8

► Let A, B, C invested Rs 4x, Rs x, Rs 15x respectively.
► According to question, Ratio of their investments for 1 year
= (4x*3 + 2x*3 + x*3 + x/2*3) : (x*3 + 2x*3 + 4x*3 + 8x*3) : (15x*12)
⇒ 45x/2 : 45x : 180x
⇒ 45 : 90 : 360
⇒ 1 : 2 : 8
Total profit = (11/2)*22000 = Rs 121000

Important Questions Test: Ratio & Proportion- 2 - Question 9

Gandhiji owns cows, some black and some white. He finds that 4 black cows and 3 white cows gave the same amount of milk in 5 days as 3 black cows and 5 white cows gave in 4 days. What is the ratio of milk given by a black cow in a day to that given by a white cow in a day?

Detailed Solution for Important Questions Test: Ratio & Proportion- 2 - Question 9

► Let 1 black cow gives x litres milk in 1 day and 1 white cow gives y litres milk in 1 day.
► Then 5(4x + 3y) = 4(3x + 5y)
⇒ 20x + 15y = 12x + 20y 

Important Questions Test: Ratio & Proportion- 2 - Question 10

A metal trader buys 2 kinds of silver foils, the ratio of their prices being 1:4. He sells the alloy at Rs 90 per kg so that he can make a profit of 20%. If the ratio of their quantities present in a alloy is 6:1 respectively, find the purchase price of the foil present in lesser quantity.

Detailed Solution for Important Questions Test: Ratio & Proportion- 2 - Question 10

CP = 75

Important Questions Test: Ratio & Proportion- 2 - Question 11

Read the passage below and solve the questions based on it.
A book having pages between 4,000 and 5,000 is divided into four parts, each part being divided into chapters. The total number of pages in each of the four parts is the same. The ratio of the chapters across all the parts is 6:5:10:14. The number of chapters in the fourth part is 70

Q.What is the total number of pages in the book?

Detailed Solution for Important Questions Test: Ratio & Proportion- 2 - Question 11

► According to question, A:B:C:D = 6:5:10:14
► Now in D there are 70 chapters
Therefore, A:B:C:D = 30:25:50:70      [ Multiplying Each by 5 ]
L.C.M of 30, 25, 50, 70 is 1050
So each part should have 1050 pages.
So total pages = 4 x 1050 = 4200 ans.

Important Questions Test: Ratio & Proportion- 2 - Question 12

The ratio of the age of Sita and her mother is 2:3. N years from now, ratio of their ages will become 3:5. What is the value of N?

Detailed Solution for Important Questions Test: Ratio & Proportion- 2 - Question 12

► Let their present ages be 2x and 3x.
Given that

10x + 5N = 9x + 3N
X = -2N which 18 not possible.
Hence, correct option is (d).

Important Questions Test: Ratio & Proportion- 2 - Question 13

P works twice as fast as Q, whereas P and Q together can work three times as fast as R. If P, Q and R together work on a job, in what ratio should they share the earnings?

Detailed Solution for Important Questions Test: Ratio & Proportion- 2 - Question 13

► If P is taking 3 days to do some work, then Q takes 6 days to do the same work.
► Now, both of them will take 2 days to complete the work. So, R takes 6 days to complete the same work.
► Hence, earning should be distributed in the ratio of their efficiency, i.e., 2 : 1 : 1.

Important Questions Test: Ratio & Proportion- 2 - Question 14

Read the passage below and solve the questions based on it.
There are certain number of apples, guavas and oranges in a basket. The number of each variety is more than one. The ratio of the number of apples to the number of guavas is equal to the ratio of the number of guavas to the number of oranges.

Q.

If the total number of fruits is 61, then find the number of guavas.

Detailed Solution for Important Questions Test: Ratio & Proportion- 2 - Question 14

► Number of apples/Number of guavas = Number of guavas/Number of oranges
► (Number of guavas)2 = Number of apples x Number of oranges.
► This gives us a hint that Number of apples x Number of oranges should be a prefect square.
Now start using the options.
Option (b) satisfies the relationship (16/20 = 20/25)

Important Questions Test: Ratio & Proportion- 2 - Question 15

A man has 25 paise, 50 paise and 1 Rupee coins. There are 220 coins in all and the total amount is 160. If there are thrice as many 1 Rupee coins as there are 25 paise coins, then what is the number of 50 paise coins?

Detailed Solution for Important Questions Test: Ratio & Proportion- 2 - Question 15

Given:

Total coin = 220

Total money = Rs. 160

There are thrice as many 1 Rupee coins as there are 25 paise coins.

Concept used:

Ratio method is used.

Calculation:

Let the 25 paise coins be 'x'

So, one rupees coins = 3x

50 paise coins = 220 – x – (3x) = 220 – (4x)

According to the questions,

3x + [(220 – 4x)/2] + x/4 =160

⇒ (12x + 440 – 8x + x)/4 = 160

⇒  5x + 440 = 640

⇒ 5x = 200

⇒ x = 40

So, 50 paise coins = 220 – (4x) = 220 – (4 × 40) = 60

∴ The number of 50 paise coin is 60.

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