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This mock test of Test: Arun Sharma Based Level 3: Number Series for Banking Exams helps you for every Banking Exams entrance exam.
This contains 15 Multiple Choice Questions for Banking Exams Test: Arun Sharma Based Level 3: Number Series (mcq) to study with solutions a complete question bank.
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QUESTION: 1

**Directions for questions: **Based on the series of numbers given in the question, find the next / missing number in the series.

3, 9, 36, 180, ?

Solution:

The given series follows the pattern x 3 , x 4 , x 5 and so on.

Hence last term will be **180 x 6 = 1080. **

QUESTION: 2

**Directions for questions: **Based on the series of numbers given in the question, find the next / missing number in the series.

100, 50, ? , 12.5, 6.25

Solution:

Each term is divided by 2 to get the next term.

Hence missing term will be **50 / 2 = 25. **

QUESTION: 3

**Directions for questions:** Based on the series of numbers given in the question, find the next / missing number in the series.

5, 7, 11, 13, 17, ?

Solution:

Here the pattern is + 2, + 4 , + 2, + 4 and so on.

Hence last term will be **17 + 2 = 19. **

QUESTION: 4

**Directions for questions:** Based on the series of numbers given in the question, find the next / missing number in the series.

81, 100, 121, 144, ?

Solution:

The given series is set of perfect squares starting from 9.

Hence last term will be **13 ^{2} = 169. **

QUESTION: 5

**Directions for questions: **Based on the series of numbers given in the question, find the next / missing number in the series.

99, 91, 75, 67, 51, 43, ?

Solution:

The terms are formed by subtracting 8 and 16 alternately from the previous term.

Hence the required term will be **(43 – 16)= 27.**

QUESTION: 6

**Directions for questions:** Based on the series of numbers given in the question, find the next / missing number in the series.

2, 0, 3, 1, 4, ?

Solution:

Alternate terms of the given series form two different series.

First, 2, 3, 4, 5 and the second 0 , 1, 2, 3 .

Hence last term will be **2.**

QUESTION: 7

**Directions for questions:** Based on the series of numbers given in the question, find the next / missing number in the series.

6, 15, 33, 69, ?, 285

Solution:

Pattern is (x 2 + 3).

Hence missing term will be **69 x 2 + 3 = 141.**

QUESTION: 8

**Directions for questions: **Based on the series of numbers given in the question, find the next / missing number in the series.

0, 6, 24, 60, ?

Solution:

Pattern is (1^{3} – 1) ; (2^{3} – 2) ; (3^{3} – 3) and so on.

Hence last term will be **(5 ^{3} – 5) = 120.**

QUESTION: 9

**Directions for questions:** Based on the series of numbers given in the question, find the next / missing number in the series.

2, 3, 10, 15, 26, ?

Solution:

Pattern is (1^{2} + 1) ; (2^{2} – 1) ; (3^{2} + 1) ; (4^{2} – 1) and so on.

Hence last term will be **(6 ^{2} -1) = 35.**

QUESTION: 10

**Directions for questions:** Based on the series of numbers given in the question, find the next / missing number in the series.

500, 379, 548, 323, ?

Solution:

Pattern is (- 11^{2} ; + 13^{2}; - 15^{2} ; + 17^{2 }and so on).

Hence next term will be **(323 + 17 ^{2}) = 612**.

QUESTION: 11

**Directions for questions:** Based on the series of numbers given in the question, find the next / missing number in the series.

6, 22, 34, 78, ?

Solution:

Pattern is (2x + 10 ; 2x_{ }– 10 ; 2x + 10 ; 2x - 10).

Hence next term will be **(78 x 2 - 10) = 146.**

QUESTION: 12

**Directions for questions:** Based on the series of numbers given in the question, find the next / missing number in the series.

1, 2, 6, 33, 289, ?

Solution:

Difference between consecutive terms are 1^{1}, 2^{2}, 3^{3}, 4^{4}.

Hence next term will be **(289 + 5 ^{5}) = 3414**.

QUESTION: 13

**Directions for questions: **Based on the series of numbers given in the question, find the next / missing number in the series.

6, 14, 36, 98, 276, ?

Solution:

Pattern is 1^{1} + 2^{1} + 3^{1} ; 1^{2 }+ 2^{2 }+ 3^{2} ; 1^{3 }+ 2^{3 }+ 3^{3} and so on.

Hence next term will be **(1 ^{6} + 2^{6} + 3^{6 }= 1 + 64 + 729) = 794.**

QUESTION: 14

**Directions for questions:** Based on the series of numbers given in the question, find the next / missing number in the series.

5, 7, 17, 55, 225, ?

Solution:

Pattern is (x 1 + 2 ; x 2 + 3 ; x 3 + 4 and so on).

Hence next term will be **(225 x 5 + 6) = 1131. **

QUESTION: 15

**Directions for questions:** Based on the series of numbers given in the question, find the next / missing number in the series.

0, 7, 26, 63, ?

Solution:

The given series follows the pattern (1^{3} – 1); (2^{3} – 1) ; (3^{3} – 1) and so on.

Hence last term will be** (5 ^{3} – 1) = 124.**

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