The Coriolis acceleration component is taken into account for
The Coriolis acceleration component
Consider a pin jointed 4-bar mechanism as shown in the figure below.
Which of the following are permanent instantaneous centers?
I12 and I14 are fixed instantaneous center.
I23 and I34 are permanent instantaneous center.
I13 and I24 are movable instantaneous center.
A crank of radius 15 cm is rotating at 50 rpm with an angular acceleration of 60 rad/sec2. The tangential acceleration of the crank is about
at = αr = 60 x 0.15 - 9 m/s
Two points A and B located along the radius of wheel as shown below, have velocities of 80 and 140 m/s respectively.
The distance between the points A and B is 300 mm. The radius of the wheel (in mm) is
The magnitude of the Coriolis component of acceleration of a slider moving at a velocity V on a link rotating at angular speed ω is
Magnitude of Coriolis component = 2 \/ω
Klein’s construction can be used when
Klein’s construction is used to determine the acceleration of various parts and this method is used when crank has uniform angular velocity.
Coriolis component of acceleration is always
Coriolis component of acceleration appears in the direction perpendicular to the link.
A constrained kinematic chain (mechanism) has n number of links. What is the number of instantaneous centres
There are two points P and Q on a planar rigid body. The relative velocity between the two points
Given any two points A and B on a rigid body, let line AB be passing through points A and B, then the components of velocity of A and B along the line AB are always equal as the distance between A and B never changes or we can say relative velocity along AB is always zero.
Hence the relative velocity of the points must be perpendicular to the line joining them.