Description

This mock test of Test: Analysis of Stress & Strain Level - 1 for Mechanical Engineering helps you for every Mechanical Engineering entrance exam.
This contains 20 Multiple Choice Questions for Mechanical Engineering Test: Analysis of Stress & Strain Level - 1 (mcq) to study with solutions a complete question bank.
The solved questions answers in this Test: Analysis of Stress & Strain Level - 1 quiz give you a good mix of easy questions and tough questions. Mechanical Engineering
students definitely take this Test: Analysis of Stress & Strain Level - 1 exercise for a better result in the exam. You can find other Test: Analysis of Stress & Strain Level - 1 extra questions,
long questions & short questions for Mechanical Engineering on EduRev as well by searching above.

QUESTION: 1

Principal plane is one which has

Solution:

QUESTION: 2

For drawing Mohr’s circle, the required stresses are

Solution:

QUESTION: 3

Mohr’s circle can be used to determine, on an inclined surface

Solution:

QUESTION: 4

The extremities of any diameter on Mohr’s circle represent

Solution:
Any diameter on Mohr’s circle represents states of stress on any pair of mutually perpendicular planes.

QUESTION: 5

The shear stress along the principal plane subjected to maximum principal stress is

Solution:

QUESTION: 6

In Mohr’s circle, the center of circle from y-axis is taken as

Solution:

QUESTION: 7

Maximum shearing stress planes are inclined at the following angle to the principal planes

(!) 45°

Solution:

QUESTION: 8

When a body is subjected to a direct tensile stress (σ) in the one plane. Then tangential or shear stress on oblique section of the body inclined at angle θ to the normal of the section is

Solution:

QUESTION: 9

When a square or rectangular block subjected to a shear load is in equilibrium, the shear stress in one plane is always associated with a complementary shear stress (of equal value) in the other plane at __________ to it?

Solution:

QUESTION: 10

If an element of a specimen of brittle material is subjected to shear stress, the crack propagation if occurs, will be inclined to the sides of the element at

Solution:

QUESTION: 11

The maximum shear stress from a Mohr’s circle is given by

Solution:

QUESTION: 12

Principal plane is one which carries

Solution:

QUESTION: 13

For which one of the following two-dimensional states of stress will be Mohr’s stress circle degenerate into a point?

Solution:
Mohr’s circle will be a point.

Radius of the Mohr's circle

=

∴ τ_{xy} = 0 and σ_{x} = σ_{y} = σ

QUESTION: 14

Biaxial stress system is correctly shown in

Solution:

Complementary shear stresses are balanced Normal stress is balanced in x and y-direction.

QUESTION: 15

If the principal stresses at a point in a strained body are σ_{x} and σ_{y} (σ_{x} > σ_{y} ), then the resultant stress on a plane carrying the maximum shear stress is equal to

Solution:

σ_{r}^{2} =

=

=

QUESTION: 16

A solid cube is subjected to identical normal forces on all the faces. The ratio of volumetric strain to linear strain in any of the three axes is

Solution:
For a solid cube and identical normal stresses ε_{x} = ε_{y} = ε_{z} and ε_{v} = ε_{x} + ε_{y} + ε_{z} = 3ε_{x}

QUESTION: 17

For the given stress condition σ_{x} = 2 N ⁄ mm^{2}, σy = 0, τ_{xy} = 0, the correct Mohr’s circle is

Solution:
Cannot Mohr’s stress circle.

QUESTION: 18

If σ_{1} = 600N/mm^{2} (tensile) and σ_{2} = 400 N/mm^{2} (Compressive), the maximum shear stress is

Solution:
σ_{1} = 600 N/mm^{2} σ_{2} = −400 N/mm^{2}

τ_{max} =

= 500 N/mm^{2}

QUESTION: 19

The principal stress induced at a point in a machine element made of steel (S_{yt} = 460 MPa) are as follows σ_{1} = 210 MPa and σ_{2} = 145 MPa, the factor of safety according to Hencky’s theory of failure is

Solution:
σ_{1} = 210 MPa σ_{2} = 145 MPa According to Hencky’s Theory (Von-Mises)

(210)2 + (145)2 − 210 × 145 ≤

N = 2.47

QUESTION: 20

A bolt is subjected to an axial load of 10 kN with a transverse shear load 4 kN and crosssection area of bolt is 250 mm2 and yield strength of bolt material is 240 MPa the factor of safety according to Guest’s theory is

Solution:
σx = = 40 MPa

τ = = 16 MPa

N = 4.685

### Stress & Strain- 1

Video | 03:15 min

### Chapter - Stress, Strain, Stress-Strain

Doc | 42 Pages

### Transformation of Stress & Strain - 1

Doc | 6 Pages

### Stress & Strain

Doc | 3 Pages

- Test: Analysis of Stress & Strain Level - 1
Test | 20 questions | 25 min

- Test: Analysis of Stress & Strain Level - 3
Test | 20 questions | 60 min

- Test: Analysis of Stress & Strain Level - 2
Test | 20 questions | 40 min

- Test: Analysis of Stress & Strain - 2
Test | 10 questions | 30 min

- Test: Analysis of Stress & Strain - 3
Test | 10 questions | 30 min