If shear force diagram between two sections is constant, BM diagram between those two section varies
A simply supported beam of length ‘l’ is subjected to a point load at mid-span. The shape of BMD is
Between point loads the shear varies
The shear force diagram for a cantilever subjected to uniformly distributed load over its entire span is
SFX−X = wx
A beam is said to be in general stable and statically determinate for general loading when number of reaction components is
The reaction at a hinged support of a beam is
For overhanging beams, the point of contra flexure
→ Point of contraflexure is a point where bending moment changes its sign.
→ As from the BMD it is clear that in between the supports the BM is changing the sign.
At a point of contra flexure
Maximum bending moment occurs in simply supported beam, where the [
In a beam under loading
For a beam subjected to a constant bending moment throughout its length
The difference in ordinate of the shear curve between any two sections is equal to the area under
A lever is supported on two hinges at A and C. It carries a force of 3 kN as shown in the above figure. The bending moment at B will be
The shear force at the free end of an overhanging beam (with udl) is equal to
Shear force will increase linearly from end D to support B starting from zero.
A wooden log of length 5mm is floating in water. First it’s self-weight is 1kN/m. The maximum B.M at the center is
Bending moment in a simply supported beam is maximum at
Bending moment in a cantilever beam shown below will be zero at
When a SSB is subjected to a concentrated moment at a distance of L/4 from the right end, the maximum bending moment occurs at
Shear force at any section is the algebraic sum of the following force on the either side
For a simply supported beam of length ‘l’ subjected to downward load of uniform intensity w,