Test: Slope & Deflection Level - 1 - Mechanical Engineering MCQ

# Test: Slope & Deflection Level - 1 - Mechanical Engineering MCQ

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## 15 Questions MCQ Test Strength of Materials (SOM) - Test: Slope & Deflection Level - 1

Test: Slope & Deflection Level - 1 for Mechanical Engineering 2024 is part of Strength of Materials (SOM) preparation. The Test: Slope & Deflection Level - 1 questions and answers have been prepared according to the Mechanical Engineering exam syllabus.The Test: Slope & Deflection Level - 1 MCQs are made for Mechanical Engineering 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Slope & Deflection Level - 1 below.
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Test: Slope & Deflection Level - 1 - Question 1

### Other parameters being unchanged, if the span of a cantilever carrying end point load is doubled, the maximum slope is increased by

Detailed Solution for Test: Slope & Deflection Level - 1 - Question 1

(i)

θmax |1 =

(ii)

θmax |2 =

θmax |2 = 4 × θmax|1

Test: Slope & Deflection Level - 1 - Question 2

### A cantilever beam of span L is carrying a uniformly distributed load of intensity w/unit length on the entire span. The deflection at the free end is given by

Detailed Solution for Test: Slope & Deflection Level - 1 - Question 2

θB =

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Test: Slope & Deflection Level - 1 - Question 3

### A cantilever of length ‘L’ is carrying a uniformly distributed load ‘w’ per unit run for a distance of ‘b’ from fixed end. The slope at the free end is given as

Detailed Solution for Test: Slope & Deflection Level - 1 - Question 3

θB =

Test: Slope & Deflection Level - 1 - Question 4

A cantilever beam of span L, uniform flexural rigidity EI is subjected to a unit couple at its free end. The deflection at the Centre of the beam is

Detailed Solution for Test: Slope & Deflection Level - 1 - Question 4

δ =

Test: Slope & Deflection Level - 1 - Question 5

A cantilever of length of span ‘L’ carries a uniformly distributed load of w per unit length over its entire span. If its span is halved, then its slope will become

Detailed Solution for Test: Slope & Deflection Level - 1 - Question 5

θ1 =

θ2 =

Test: Slope & Deflection Level - 1 - Question 6

A cantilever beam of span ‘L’ is carrying a triangular load of zero intensity at its free end to W per unit length at its fixed end. the deflection at its free end will be

Detailed Solution for Test: Slope & Deflection Level - 1 - Question 6

YB =

Test: Slope & Deflection Level - 1 - Question 7

Slope at the end of the simply supported beam of span ‘L’ with uniformly distributed load w/unit length over the entire span is given by

Detailed Solution for Test: Slope & Deflection Level - 1 - Question 7

θmax =

Test: Slope & Deflection Level - 1 - Question 8

A beam of length ‘L’ simply supported at the ends carries a point load W at distance 'a' from the left end. Also L − a = b. The deflection under load is given by

Test: Slope & Deflection Level - 1 - Question 9

A simply supported beam of span L carries a UDL of w. N m−1. What is the magnitude of concentrated load to be supplied at the centre of this beam which would produce the same deflection as the UDL?

Detailed Solution for Test: Slope & Deflection Level - 1 - Question 9

P = 5/8 ∙ w ∙ L

Test: Slope & Deflection Level - 1 - Question 10

A simply supported beam of span L carries a concentrated load w at mid-span. The slope at the end is given by (EI = constant for total length)

Detailed Solution for Test: Slope & Deflection Level - 1 - Question 10

θA = θB =

Test: Slope & Deflection Level - 1 - Question 11

A simply supported beam of span ‘L’ carries a uniformly distributed load, 'w' per unit length over the entire span. The deflection at the center is 'y'. If the distributed load per unit length is doubled and also the depth of beam is doubled, the deflection at the center would be

Detailed Solution for Test: Slope & Deflection Level - 1 - Question 11

δmax = y

w2 = 2w

d2 = 2d

y2 = y / 4

Test: Slope & Deflection Level - 1 - Question 12

If the actual beam has both ends fixed, then the ends of the conjugate beam will be

Test: Slope & Deflection Level - 1 - Question 13

A cantilever beam AB is fixed at left end A and free at B. The corresponding conjugate beam will supports

Test: Slope & Deflection Level - 1 - Question 14

A beam simply supported at the ends carries a load W at the Centre, causing deflection y. If the depth of the section of the beam is doubled, the deflection at the Centre will be

Detailed Solution for Test: Slope & Deflection Level - 1 - Question 14

Deflection at C:

y =

y2 = 1/8 × y

Test: Slope & Deflection Level - 1 - Question 15

For cantilever beam shown in figure, the deflection at C due to a couple M applied at B is equal to

Detailed Solution for Test: Slope & Deflection Level - 1 - Question 15
∆C= ∆B + QB ∙ L

## Strength of Materials (SOM)

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## Strength of Materials (SOM)

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