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# P. Bahadur Test: Structure of Atom

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P. Bahadur Test: Structure of Atom - Question 1

### Electronic configuration of the element having atomic number 24.

Detailed Solution for P. Bahadur Test: Structure of Atom - Question 1

Atomic no 24 is of Cr. Due to half filled orbital stability it doesnot follow Afbau rule so its configuration is

P. Bahadur Test: Structure of Atom - Question 2

### The atom with the given atomic number Z=17, and the atomic mass A=35.5 is

Detailed Solution for P. Bahadur Test: Structure of Atom - Question 2

The element with atomic number(Z) 17 & mass number (A) 35 is chlorine =

P. Bahadur Test: Structure of Atom - Question 3

### Correct expression for mass number A is

Detailed Solution for P. Bahadur Test: Structure of Atom - Question 3

Mass no. = no. of protons + no. of neutrons.

P. Bahadur Test: Structure of Atom - Question 4

According to quantum mechanics ψ2(r) the wave function squared gives

Detailed Solution for P. Bahadur Test: Structure of Atom - Question 4

ψ has no physical significance while ψ2 represnts the probability density of finding an electron.

P. Bahadur Test: Structure of Atom - Question 5

Spin quantum number with two spin states of the electron represented by two arrows, ↑ (spin up) and ↓ (spin down) was introduced to account for

Detailed Solution for P. Bahadur Test: Structure of Atom - Question 5

In anomalous Zeeman effect the splitting of spectral lines occurs due to interaction of the applied magnetic field with the magnetic moment generated by the orbital and 'spin' motions of the electron.

P. Bahadur Test: Structure of Atom - Question 6

Values of e/m (charge/mass) in the categories alpha particle (α), electron (e) and protons (p) increase in the order:

Detailed Solution for P. Bahadur Test: Structure of Atom - Question 6

E/m values of particle (α), electron (e) and protons (p) increase in the order a< p < e

P. Bahadur Test: Structure of Atom - Question 7

A gas absorbs a photon of 355 nm and emits at two wavelengths. If one of the emissions is at 680 nm, the other is at:

Detailed Solution for P. Bahadur Test: Structure of Atom - Question 7

P. Bahadur Test: Structure of Atom - Question 8

The electronic configuration 1s22s22p1 belongs to

Detailed Solution for P. Bahadur Test: Structure of Atom - Question 8

It is of boron as it has atomic number 5.

P. Bahadur Test: Structure of Atom - Question 9

The energy associated with the first orbit in the hydrogen atom is -2.18 x 10−18 J/atom. What is the energy associated with the fifth orbit?

Detailed Solution for P. Bahadur Test: Structure of Atom - Question 9

Energy for any n shell = -2.18 x 10−18 )/n'2 (') stands for raise to the power of therefore, E associated with 5 orbit = -2.18 x 10−18/52 = -2.18 × 10-18/25 = -218 × 10-20/25 = -8.72 x 10-20J/atom

P. Bahadur Test: Structure of Atom - Question 10

Isobars are the atoms with

Detailed Solution for P. Bahadur Test: Structure of Atom - Question 10

Isobars are the atoms with same mass number but different atomic number.

P. Bahadur Test: Structure of Atom - Question 11

Due to the presence of electrons in the inner shells, the electron in the outer shell will not experience the full positive charge of the nucleus (Ze). This is known as

Detailed Solution for P. Bahadur Test: Structure of Atom - Question 11

This is known as shielding effect. Inner lying electrons shields the positive charge reaching the outer most electrons.

P. Bahadur Test: Structure of Atom - Question 12

Maximum number of electrons in a subshell with = 3 and = 4 is

Detailed Solution for P. Bahadur Test: Structure of Atom - Question 12

In this question l=3 means the sub shell is f & n=4 means it is present in 4th orbit.
Finally it is a 4f sub shell.
The no of orbital in f sub shell =2l+1
= 2*3+1
=7
Each orbital can accommodate 2 electrons.
7*2 = 14 electrons.

Maximum number of electrons in a sub shell with l=3& n=4 (4f) is 14electrons.

P. Bahadur Test: Structure of Atom - Question 13

Arrange the electrons present in the 4d, 3d, 4p and 3p orbitals in order of increasing energies

Detailed Solution for P. Bahadur Test: Structure of Atom - Question 13

Energy of orbital is determined by n+l value. The orbital having higher n+l value will have higher energy. If n+l value is same then orbital having higher n value will have higher energy.

P. Bahadur Test: Structure of Atom - Question 14

Isotopes are the atoms with

Detailed Solution for P. Bahadur Test: Structure of Atom - Question 14

Isotopes have same atomic no. but different mass no.

P. Bahadur Test: Structure of Atom - Question 15

The Aufbau principle states : In the ground state of the atoms, the orbitals are filled in order of

Detailed Solution for P. Bahadur Test: Structure of Atom - Question 15

According to Aufbau rule electrons are filled in increasing order of energy.

P. Bahadur Test: Structure of Atom - Question 16

Radio frequency region of the electromagnetic spectrum is used for broadcasting. It is

Detailed Solution for P. Bahadur Test: Structure of Atom - Question 16

Radio frequency region is present around 106106 Hz.

P. Bahadur Test: Structure of Atom - Question 17

In an atom, an electron is moving with a speed of 600m/s with an accuracy of 0.005%. Certainity with which the position of the electron can be located is (h = 6.6 ×10−34 Js)

Detailed Solution for P. Bahadur Test: Structure of Atom - Question 17

P. Bahadur Test: Structure of Atom - Question 18

Give the name and atomic number of the inert gas atom in which the total number of d-electrons is equal to the difference between the numbers of total p and total s electrons.

Detailed Solution for P. Bahadur Test: Structure of Atom - Question 18

It is Krypton .
Electronic configuration:  1s22s22p63s23p64s23d104p6
​Number of electrons in s orbital are 8
Number of electrons in p orbital are 18
Number of electrons in d orbitals are 10 (18-8=10)

P. Bahadur Test: Structure of Atom - Question 19

Photoelectric effect established that light

Detailed Solution for P. Bahadur Test: Structure of Atom - Question 19

Photoelectric effect proves the particle nature of light.

P. Bahadur Test: Structure of Atom - Question 20

According to Pauli’s exclusion principle

Detailed Solution for P. Bahadur Test: Structure of Atom - Question 20

Paulis exclusion principle stated that no two electron can have same set of all the four quantum nos.

P. Bahadur Test: Structure of Atom - Question 21

One of the orbitals is non-directional

Detailed Solution for P. Bahadur Test: Structure of Atom - Question 21

s orbital is spherically symmetrical hence non directional.

P. Bahadur Test: Structure of Atom - Question 22

The ionization energy of the lowest state, also called as the ground state, is:

Detailed Solution for P. Bahadur Test: Structure of Atom - Question 22

For hydrogen atom =  2.18 x 10−18J atom−1 =−E1(H)

P. Bahadur Test: Structure of Atom - Question 23

An cation A3+ has 18 electrons. Write the atomic number of A.

Detailed Solution for P. Bahadur Test: Structure of Atom - Question 23

3+ charge means no of electrons will be 3 less than no. of protons. So no. of protons will be 21. So atomic no. is 21.

P. Bahadur Test: Structure of Atom - Question 24

Emission spectrum of a material results from the material's (atom or molecules)

Detailed Solution for P. Bahadur Test: Structure of Atom - Question 24

Emission spectrum is recorded when a electron de excites from higher energy level to ground state.

P. Bahadur Test: Structure of Atom - Question 25

Dalton's atomic theory could not explain one of the following

Detailed Solution for P. Bahadur Test: Structure of Atom - Question 25

Dalton’s atomic theory stated that atoms were indivisible. However, the discovery of subatomic particles (such as protons, electrons, and neutrons) disproved this postulate.

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